A Tale of Three Intersecting Lines — Flashcards
CBSE · Class 7 · Mathematics
64 flashcards for A Tale of Three Intersecting Lines (CBSE Class 7 Mathematics) to test yourself on key terms and facts.
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Construct an equilateral triangle of side 4 cm. What are the steps?
Answer
Step 1: Draw a base AB of 4 cm. Step 2: With A as centre and radius 4 cm, draw an arc. Step 3: With B as centre and radius 4 cm, draw another arc. Step 4: Let the arcs meet at C. Step 5: Join AC and B…
4 cm भुजा का एक समबाहु त्रिभुज बनाइए। इसके क्या चरण हैं?
Answer
चरण 1: 4 cm का आधार AB बनाएं। चरण 2: A को केंद्र मानकर और त्रिज्या 4 cm लेकर एक चाप बनाएं। चरण 3: B को केंद्र मानकर और त्रिज्या 4 cm लेकर एक और चाप बनाएं। चरण 4: चापों को C पर मिलने दें। चरण 5: AC और …
Why does the compass method work for constructing an equilateral triangle?
Answer
The two arcs are drawn with the same radius as the base. Any point where the arcs meet is 4 cm from A and 4 cm from B. So the third vertex is equally far from both base points. That makes all three si…
एक समबाहु त्रिभुज बनाने के लिए कम्पास विधि क्यों काम करती है?
Answer
दोनों चाप आधार के समान त्रिज्या से खींचे गए हैं। चाप जहाँ मिलते हैं, वह बिंदु A से 4 cm और B से 4 cm दूरी पर है। इसलिए तीसरा शीर्ष दोनों आधार बिंदुओं से समान दूरी पर है। इससे तीनों भुजाएँ बराबर हो जात…
Construct a triangle with sides 5 cm, 6 cm, and 4 cm. Which side should be used as the base?
Answer
Step 1: Take the longest side, 6 cm, as the base AB. Step 2: With A as centre and radius 5 cm, draw an arc. Step 3: With B as centre and radius 4 cm, draw another arc. Step 4: Let the arcs meet at C.
5 cm, 6 cm, और 4 cm भुजाओं वाला एक त्रिभुज बनाइए। किस भुजा को आधार के रूप में उपयोग किया जाना चाहिए?
Answer
चरण 1: सबसे लंबी भुजा, 6 cm, को आधार AB मान लें। चरण 2: A को केंद्र मानकर और त्रिज्या 5 cm लेकर एक चाप बनाएं। चरण 3: B को केंद्र मानकर और त्रिज्या 4 cm लेकर एक और चाप बनाएं। चरण 4: चापों को C पर मिलने…
Check whether 3 cm, 4 cm, and 5 cm can form a triangle.
Answer
Step 1: Take the longest side, 5 cm. Step 2: Check whether 3 + 4 > 5. Step 3: 7 > 5, so the condition is satisfied. Answer: Yes, a triangle exists.
जाँच करें कि क्या 3 cm, 4 cm और 5 cm एक त्रिभुज बना सकते हैं।
Answer
चरण 1: सबसे लंबी भुजा, 5 cm लें। चरण 2: जाँच करें कि क्या 3 + 4 > 5 है। चरण 3: 7 > 5, इसलिए शर्त पूरी हो जाती है। उत्तर: हाँ, एक त्रिभुज मौजूद है।…
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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