The Baudhayana-Pythagoras Theorem — Important Questions
CBSE · Class 8 · Mathematics
70 important questions from The Baudhayana-Pythagoras Theorem for CBSE Class 8 Mathematics, with answers. Part of the CBSE Class 8 Mathematics syllabus.
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Important Questions from The Baudhayana-Pythagoras Theorem
A right triangle has hypotenuse 25 cm and one shorter side 7 cm. What is the other shorter side?
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24 cm
Step 1: Use a^2 + b^2 = c^2. Step 2: Let the unknown side be x. Step 3: 7^2 + x^2 = 25^2. Step 4: 49 + x^2 = 625. Step 5: x^2 = 625 - 49 = 576. Step 6: x = 24 cm. So the other side is 24 cm.
A right triangle has sides 6 cm and 8 cm as the shorter sides. What is its area?
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24 sq. cm
Step 1: Area of a right triangle = 1/2 × base × height. Step 2: Use the two shorter sides as base and height. Step 3: Area = 1/2 × 6 × 8 = 24 sq. cm. So the area is 24 sq. cm.
A square on the diagonal of a unit square has area 2 sq. units. What is the length of the diagonal?
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√2 units
Step 1: The area of the square on the diagonal is c^2. Step 2: Here c^2 = 2. Step 3: So c = √2. The diagonal is √2 units long.
The decimal value of √2 lies between 1.41 and 1.42. Which of these values gives a better lower bound for √2: 1.414 or 1.41?
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1.414
Step 1: A better lower bound is the one closer to √2 from below. Step 2: 1.414 is closer to 1.41421356... than 1.41. So 1.414 is the better lower bound.
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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