Gujarat Board Class 10 Mathematics — Flashcards
Gujarat Board Class 10 Mathematics flashcards, chapter by chapter — 326 flashcards across 14 chapters. Follows the GSEB syllabus.
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Chapter-Wise Flashcards — 14 Chapters
Q: Find the prime factorization of 32760 using a factor tree method
A: Step 1: Divide 32760 by 2 → 16380 Step 2: Divide 16380 by 2 → 8190 Step 3: Divide 8190 by 2 → 4095 Step 4: Divide 4095 by 3 → 1365 Step 5: Divide 1365 by 3 → 455 Step 6: Divide 455 by 5 → 91 Step 7: D
Q: Express 123456789 in prime factor form if 123456789 = 3² × 3803 × 3607. Verify that 3803 and 3607 are prime.
A: Prime factorization: 123456789 = 3² × 3803 × 3607 To verify 3803 is prime: - Check divisibility by primes up to √3803 ≈ 61.7 - Test primes: 2 (odd, so no), 3 (3+8+0+3=14, not divisible), 5 (doesn't e
Q: State the Fundamental Theorem of Arithmetic. Why is it important?
A: The Fundamental Theorem of Arithmetic: Every composite number can be expressed (factorised) as a product of primes, and this factorisation is unique, except for the order in which the prime factors oc
Q: Identify the degree and type of polynomial: 3x² + 5x - 2
A: Step 1: Look at the highest power of x in the polynomial → x² is the highest power Step 2: Degree = 2 Step 3: A polynomial of degree 2 is called a quadratic polynomial Answer: Degree = 2, Type = Quadr
Q: Is 5/x + 3x - 2 a polynomial? Justify your answer.
A: Step 1: Check each term in the expression - First term: 5/x = 5x⁻¹ (has negative exponent) - Second term: 3x (positive integer exponent ✓) - Third term: -2 (constant term ✓) Step 2: Polynomials
Q: Classify by degree: (i) 7y + 4 (ii) 2x³ - 5x + 1 (iii) 8 (iv) √2u⁴ + 3u² - 5
A: Step 1: Find highest power of variable in each (i) 7y + 4: Highest power is y¹ → Degree = 1 → Linear polynomial (ii) 2x³ - 5x + 1: Highest power is x³ → Degree = 3 → Cubic polynomial (iii) 8: Co
Q: Solve the pair of equations using substitution method: y = 2x + 1 3x + y = 11
A: Step 1: We have y = 2x + 1 from the first equation. Step 2: Substitute this value of y into the second equation: 3x + (2x + 1) = 11 Step 3: Simplify: 5x + 1 = 11 Step 4: Solve for x: 5x = 10 → x = 2 S
Q: Solve using the elimination method: 2x + 3y = 13 5x - 3y = 8
A: Step 1: Observe that the coefficients of y are +3 and -3 (opposites). Step 2: Add both equations to eliminate y: (2x + 3y) + (5x - 3y) = 13 + 8 Step 3: Simplify: 7x = 21 Step 4: Solve for x: x = 3 Ste
Q: Determine if the pair of equations is consistent, inconsistent, or dependent: 3x + 4y = 12 6x + 8y = 24
A: For equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0, rewrite: 3x + 4y - 12 = 0 6x + 8y - 24 = 0 Calculate the ratios: a₁/a₂ = 3/6 = 1/2 b₁/b₂ = 4/8 = 1/2 c₁/c₂ = -12/-24 = 1/2 Since a₁/a₂ = b₁/b
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Where can I find Gujarat Board Class 10 Mathematics Flashcards?
This page has flashcards for 14 chapters of Gujarat Board Class 10 Mathematics for the board exams 2027. Each chapter links to its own page with the full set.
How should I prepare for Gujarat Board Class 10 Mathematics board exams?
Go through the syllabus first, then work chapter by chapter: learn the ideas, practise questions, and revise with notes and flashcards. Leave time at the end to revise every chapter once more under timed conditions.
How do I use flashcards for Gujarat Board Class 10 Mathematics?
Read the question side, answer it in your head, then check. Put the cards you got wrong back into the pile and review them again the next day. Short daily sessions work better than long ones.
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Gujarat Board Class 10
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