Electricity
Karnataka Board · Class 10 · Science
Flashcards for Electricity — Karnataka Board Class 10 Science. Quick Q&A cards covering key concepts, definitions, and formulas.
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An electric heater draws 5 A current from a 220 V supply. Calculate its resistance and the power consumed.
Answer
Using Ohm's law: R = V/I = 220V/5A = 44Ω Power consumed: P = VI = 220V × 5A = 1100W = 1.1kW This heater consumes 1.1 units of electricity per hour.
Why does the filament of an electric bulb glow but the connecting wires remain cool?
Answer
The filament has much higher resistance than connecting wires. When current flows, heat generated (H = I²Rt) is proportional to resistance. The high-resistance filament gets hot enough to glow (around…
What is electric current and how is it measured?
Answer
Electric current is the rate of flow of electric charge through a conductor. Formula: I = Q/t, where Q is charge in coulombs and t is time in seconds. Unit: Ampere (A). Measured using an ammeter conne…
Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. Find the equivalent resistance.
Answer
For parallel connection: 1/Rp = 1/R₁ + 1/R₂ + 1/R₃ 1/Rp = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1 Therefore, Rp = 1Ω Note: Parallel resistance is always less than the smallest individual resistanc…
Why are household appliances connected in parallel instead of series?
Answer
In parallel connection: 1) Each appliance gets full voltage (220V), 2) Each works independently - if one fails, others continue working, 3) Different appliances can draw different currents as needed, …
A wire has resistance 10Ω. If it's stretched to double its length, what happens to its resistance?
Answer
When length doubles, cross-sectional area halves (volume remains constant). R = ρl/A. New resistance = ρ(2l)/(A/2) = 4ρl/A = 4R New resistance = 4 × 10Ω = 40Ω Resistance becomes 4 times the original v…
What happens during the process of measuring current in a circuit?
Answer
Steps: 1) Break the circuit at the point where current is to be measured, 2) Connect ammeter in series so all current flows through it, 3) Ensure correct polarity (+ terminal to higher potential), 4) …
An electric iron rated 1000W is used for 2 hours daily for 30 days. Calculate the electricity bill if the rate is ₹5 per unit.
Answer
Energy consumed = Power × Time = 1000W × 2h × 30 days = 60,000Wh = 60kWh = 60 units Cost = 60 units × ₹5/unit = ₹300 This shows how power rating and usage time affect electricity bills.
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Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
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