Electrostatics — Flashcards
Maharashtra Board · Class 12 · Physics
22 flashcards for Electrostatics (Maharashtra Board Class 12 Physics) to test yourself on key terms and facts.
Interactive on Super Tutor
Studying Electrostatics? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
Free trial, no card needed.
State Gauss' Law and write its mathematical expression. What is a Gaussian surface?
Answer
Gauss' Law: The total electric flux through any closed surface is equal to the total charge enclosed by the surface divided by ε₀. Mathematical Expression: ∮ E⃗ · ds⃗ = q/ε₀ Gaussian Surface: An ima…
Derive the electric field intensity due to a uniformly charged spherical shell at points: (i) outside the shell (ii) on the surface (iii) inside the shell
Answer
Using Gauss' Law with spherical Gaussian surface of radius r: (i) Outside (r > R): E = q/(4πε₀r²) [same as point charge] (ii) On surface (r = R): E = q/(4πε₀R²) = σ/ε₀ (iii) Inside (r < R): E = 0 [no…
A sphere of radius 10 cm carries charge 1 μC. Calculate electric field at: (a) 30 cm from center (b) on surface (c) 5 cm from center
Answer
Given: R = 10 cm = 0.1 m, q = 1 μC = 1×10⁻⁶ C (a) At r = 30 cm = 0.3 m (outside): E = q/(4πε₀r²) = (9×10⁹ × 1×10⁻⁶)/(0.3)² = 10⁵ N/C (b) On surface (r = R = 0.1 m): E = q/(4πε₀R²) = (9×10⁹ × 1×10⁻⁶)…
Derive the electric field intensity due to an infinitely long straight charged wire using Gauss' Law.
Answer
For infinite line charge with linear charge density λ: 1. Choose cylindrical Gaussian surface of radius r and length l 2. By symmetry, E is radial and constant on curved surface 3. Flux through end c…
What is electric potential? How is it related to electric field? Define equipotential surface.
Answer
Electric Potential (V): Work done per unit positive charge in bringing it from infinity to that point. V = U/q = W∞/q Relation with Electric Field: E = -dV/dx (for 1D) E⃗ = -∇V (gradient of potential…
Derive the electric potential due to a point charge q at distance r from it.
Answer
Consider bringing unit positive charge from ∞ to distance r from charge q: Work done against electric force: dW = -F⃗ · dr⃗ = -E dr (taking radial path) Since E = q/(4πε₀r²): dW = -q/(4πε₀r²) dr To…
A wire bent in circle of radius 10 cm carries charge 250 μC uniformly distributed. Find electric potential at center.
Answer
Given: R = 10 cm = 0.1 m, q = 250 μC = 250×10⁻⁶ C For any point on the circular wire, distance to center = R Potential at center due to entire charge: V = q/(4πε₀R) V = (9×10⁹ × 250×10⁻⁶)/(0.1) V = …
Derive the electric potential due to an electric dipole at a point making angle θ with the dipole axis.
Answer
Consider dipole with charges +q and -q separated by 2l, dipole moment p = q×2l: For point P at distance r (r >> l) making angle θ with axis: r₁ ≈ r - l cos θ (distance from +q) r₂ ≈ r + l cos θ (dist…
+14 more flashcards
Practise AllFrequently Asked Questions
What are the important topics in Electrostatics for Maharashtra Board Class 12 Physics?
How many flashcards are available for Electrostatics?
How should I revise Electrostatics for the Maharashtra Board Class 12 board exam?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Electrostatics
For serious students
Get the full Electrostatics chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for Maharashtra Board Class 12 Physics. Free to start, no card needed.