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Mechanical Properties of Fluids

Maharashtra Board · Class 12 · Physics

Flashcards for Mechanical Properties of Fluids — Maharashtra Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions25 flashcards5 concepts

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25 Flashcards
Card 1Introduction to Fluids

What is a fluid and what are its key characteristics?

Answer

A fluid is any substance that can flow and deforms continually under external force. Key characteristics: 1) Shear modulus is zero 2) Cannot resist shear stress 3) Takes shape of container 4) Includes

Card 2Ideal Fluid

State the four properties of an ideal fluid.

Answer

1) Incompressible: density is constant 2) Irrotational flow: smooth flow without turbulence 3) Non-viscous: no internal friction 4) Steady flow: velocity at each point is constant in time. Real fluids

Card 3Pressure

Define pressure and write its formula with units.

Answer

Pressure is the normal force exerted by a fluid per unit area. Formula: P = F/A, where F is force and A is area. SI unit: N/m² = Pascal (Pa). Dimension: [L⁻¹M¹T⁻²]. Other units: bar, torr, mmHg.

Card 4Pressure

Derive the expression for pressure due to a liquid column of height h.

Answer

Consider a cylinder of liquid: Area A, height h, density ρ. Weight = mg = (Volume × density) × g = Ahρg. Pressure = Weight/Area = Ahρg/A = hρg. Therefore, P = hρg. This shows pressure depends only on

Card 5Atmospheric Pressure

What is atmospheric pressure and how is it measured?

Answer

Atmospheric pressure is the pressure exerted by the weight of air column from any point to the top of atmosphere. At sea level: 1 atm = 760 mmHg = 760 torr = 1.01 × 10⁵ Pa. Measured using mercury baro

Card 6Pressure Types

Distinguish between absolute pressure and gauge pressure.

Answer

Absolute pressure = atmospheric pressure + pressure due to liquid column = P₀ + hρg. Gauge pressure = absolute pressure - atmospheric pressure = hρg. Gauge pressure measures excess pressure above atmo

Card 7Pascal's Law

State Pascal's Law and give two practical applications.

Answer

Pascal's Law: Pressure applied at any point of an enclosed fluid at rest is transmitted equally and undiminished to every point of the fluid and container walls. Applications: 1) Hydraulic lift: F₂ =

Card 8Pascal's Law

A hydraulic lift has pistons of areas 0.1 m² and 2 m². If 500 N force is applied on smaller piston, find the force on larger piston.

Answer

Given: A₁ = 0.1 m², A₂ = 2 m², F₁ = 500 N. By Pascal's law: F₁/A₁ = F₂/A₂. Therefore: F₂ = F₁ × (A₂/A₁) = 500 × (2/0.1) = 500 × 20 = 10,000 N = 10⁴ N. The force is magnified 20 times due to area ratio

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What are the important topics in Mechanical Properties of Fluids for Maharashtra Board Class 12 Physics?
Mechanical Properties of Fluids covers several key topics that are frequently asked in Maharashtra Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Mechanical Properties of Fluids — Maharashtra Board Class 12 Physics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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