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Relations and Functions

Tamil Nadu Board · Class 10 · Mathematics

Flashcards for Relations and Functions — Tamil Nadu Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts

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A diagram illustrating the domain, range, and co-domain of a relation R from set A to set B, highlighting which elements belong to each category.
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24 Flashcards
Card 1Cartesian Product

Find A × B where A = {1, 2, 3} and B = {a, b}. How many elements will A × B have?

Answer

Step 1: A × B contains all ordered pairs (x, y) where x ∈ A and y ∈ B. Step 2: For each element in A, pair it with each element in B: - 1 pairs with: a, b → (1,a), (1,b) - 2 pairs with: a, b → (2,a),

Card 2Cartesian Product

If n(A × B) = 20 and n(A) = 4, find n(B).

Answer

Step 1: Use the formula: n(A × B) = n(A) × n(B) Step 2: Substitute the given values: 20 = 4 × n(B) Step 3: Divide both sides by 4: n(B) = 20 ÷ 4 = 5 Answer: n(B) = 5 Explanation: The total number of o

Card 3Cartesian Product

When should you use A × B instead of B × A? Explain with an example.

Answer

Use A × B when you need the Cartesian product with first coordinates from A and second coordinates from B. Example: If A = {Roll Numbers} and B = {Names}, then: - A × B = {(1, Raj), (2, Priya), ...} -

Card 4Relations

Identify which of these sets are relations from A = {1,2,3} to B = {p,q}: (i) {(1,p), (2,q), (3,p)} (ii) {(1,p), (2,p), (2,q)} (iii) {(1,p), (q,2), (3,q)}

Answer

A relation from A to B must be a subset of A × B. First, find A × B = {(1,p), (1,q), (2,p), (2,q), (3,p), (3,q)} (i) {(1,p), (2,q), (3,p)} ✓ RELATION All ordered pairs have first coordinate from A an

Card 5Relations

Find the domain, co-domain, and range of the relation R = {(2,4), (3,6), (5,10)} from A = {1,2,3,4,5} to B = {2,4,6,8,10,12}.

Answer

Step 1: Identify domain (first coordinates that appear in R): Domain = {2, 3, 5} ⊂ A Step 2: Identify co-domain (the set B given in the relation definition): Co-domain = B = {2,4,6,8,10,12} Step 3:

Card 6Functions

Write the relation R = {(x,y) | y = x + 2, x ∈ {1,2,3,4}} in roster form. Is it a function?

Answer

Step 1: Find all ordered pairs by substituting values of x: When x = 1: y = 1 + 2 = 3 → (1,3) When x = 2: y = 2 + 2 = 4 → (2,4) When x = 3: y = 3 + 2 = 5 → (3,5) When x = 4: y = 4 + 2 = 6 → (4,6) Ste

Card 7Functions

Determine whether f = {(1,2), (2,3), (1,4), (3,5)} is a function. Explain why or why not.

Answer

Step 1: Check if every element in domain has exactly one image. Step 2: Examine the pairs: - Element 1 appears twice: (1,2) and (1,4) - This means 1 has TWO different images: 2 and 4 Step 3: Apply f

Card 8Functions

Evaluate f(3) and f(-1) where f(x) = x² - 2x + 5.

Answer

For f(x) = x² - 2x + 5: Step 1: Find f(3) Substitute x = 3: f(3) = (3)² - 2(3) + 5 f(3) = 9 - 6 + 5 f(3) = 8 Step 2: Find f(-1) Substitute x = -1: f(-1) = (-1)² - 2(-1) + 5 f(-1) = 1 + 2 + 5 f(-1) =

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Frequently Asked Questions

What are the important topics in Relations and Functions for Tamil Nadu Board Class 10 Mathematics?
Key topics in Relations and Functions include Relations and Functions – Complete Chapter Overview, Relations and Functions – Complete Concept Map, Relations and Functions - Concept Overview. These are the concepts Tamil Nadu Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Relations and Functions — Tamil Nadu Board Class 10 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Relations and Functions?
There are 24 flashcards for Relations and Functions covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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