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Trigonometry — Flashcards

Tamil Nadu Board · Class 10 · Mathematics

25 flashcards for Trigonometry (Tamil Nadu Board Class 10 Mathematics) to test yourself on key terms and facts.

45 questions25 flashcards6 formulas & key relations5 concepts

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A comprehensive table summarizing the values of sine, cosine, tangent, cotangent, secant, and cosecant for standard angles 0°, 30°, 45°, 60°, and 90°.
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25 Flashcards·
Trigonometric RatiosReciprocal Trigonometric RatiosTrigonometric IdentitiesTrigonometric Ratios of Complementary AnglesTrigonometric Values of Standard Angles
Card 1Trigonometric Ratios

Problem: In a right-angled triangle ABC with right angle at B, if AB = 5 cm and BC = 12 cm, find sin(C), cos(C), and tan(C).

Answer

Step 1: Find hypotenuse using Pythagoras theorem: AC² = AB² + BC² = 5² + 12² = 25 + 144 = 169, so AC = 13 cm. Step 2: Identify sides relative to angle C: - Opposite side to C = AB = 5 cm - Adjacent s…

Card 2Reciprocal Trigonometric Ratios

Problem: Find sec(θ), cosec(θ), and cot(θ) for the triangle in FC1 where angle C is θ.

Answer

Using the reciprocal trigonometric ratios from FC1: - sin(θ) = 5/13, cos(θ) = 12/13, tan(θ) = 5/12 Step 1: Find sec(θ) (reciprocal of cos): sec(θ) = 1/cos(θ) = 1/(12/13) = 13/12 Step 2: Find cosec(θ…

Card 3Trigonometric Identities

Prove the identity: sin²θ + cos²θ = 1

Answer

Proof using right-angled triangle: Consider right-angled triangle OMP with right angle at M. Let OP = hypotenuse, OM = adjacent side, MP = opposite side. By Pythagoras theorem: OP² = OM² + MP² Divi…

Card 4Trigonometric Identities

Problem: Using the identity sin²θ + cos²θ = 1, if sin(θ) = 3/5, find cos(θ).

Answer

Step 1: Use the fundamental identity: sin²θ + cos²θ = 1 Step 2: Rearrange to find cos²θ: cos²θ = 1 - sin²θ Step 3: Substitute sin(θ) = 3/5: cos²θ = 1 - (3/5)² cos²θ = 1 - 9/25 cos²θ = 25/25 - 9/25 c…

Card 5Trigonometric Identities

When do you use the identity 1 + tan²θ = sec²θ? Provide an example.

Answer

Use 1 + tan²θ = sec²θ when: - You know tan(θ) and need to find sec(θ) - You need to simplify expressions containing both tan and sec - You're proving other trigonometric identities - You need to manip…

Card 6Trigonometric Identities

Problem: Prove that tan²θ - sin²θ = tan²θ × sin²θ

Answer

Step 1: Start with the left side and express tan in terms of sin and cos: tan²θ - sin²θ = sin²θ/cos²θ - sin²θ Step 2: Find common denominator: = sin²θ/cos²θ - sin²θ × cos²θ/cos²θ = (sin²θ - sin²θ × c…

Card 7Trigonometric Ratios of Complementary Angles

What are the trigonometric ratios of complementary angles? Give the relationship between sin(90°-θ) and cos(θ).

Answer

Complementary Angles Relationships: If two angles are complementary (sum = 90°), their trigonometric ratios are related: 1. sin(90° - θ) = cos(θ) 2. cos(90° - θ) = sin(θ) 3. tan(90° - θ) = cot(θ) 4.

Card 8Trigonometric Values of Standard Angles

Problem: Find the value of sin(30°) × cos(60°) + cos(30°) × sin(60°)

Answer

Step 1: Recall standard angle values from the trigonometric table: sin(30°) = 1/2 cos(30°) = √3/2 sin(60°) = √3/2 cos(60°) = 1/2 Step 2: Substitute values into the expression: sin(30°) × cos(60°) + c…

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Frequently Asked Questions

What are the important topics in Trigonometry for Tamil Nadu Board Class 10 Mathematics?
Key topics in Trigonometry include 1 Trigonometric Ratios - Foundation Concepts, 2 Trigonometric Ratios of Complementary Angles, 3 Standard Values of Trigonometric Ratios, 4 Trigonometric Identities - Proving and Simplifying. Study these first, then practise questions on each for the Tamil Nadu Board Class 10 board exam.
How many flashcards are available for Trigonometry?
There are 25 flashcards for Trigonometry covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Trigonometry for the Tamil Nadu Board Class 10 board exam?
Learn the core ideas first, then work through the 45 practice questions on Trigonometry. Revise definitions regularly and use flashcards for quick recall before the exam.

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Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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