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Chapter 7 of 8
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Mensuration

Tamil Nadu Board · Class 10 · Mathematics

Flashcards for Mensuration — Tamil Nadu Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions40 flashcards5 concepts

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40 Flashcards
Card 1Cylinder - Surface Area

Find the curved surface area of a cylinder with radius 7 cm and height 10 cm.

Answer

Formula: C.S.A. = 2πrh Given: r = 7 cm, h = 10 cm Step 1: C.S.A. = 2 × (22/7) × 7 × 10 Step 2: C.S.A. = 2 × 22 × 10 Step 3: C.S.A. = 440 cm² Answer: 440 cm²

Card 2Cylinder - Formulas

Formula for total surface area of a cylinder

Answer

T.S.A. of cylinder = 2πr(h + r) square units Where: - r = radius of the base - h = height of the cylinder - π ≈ 22/7 or 3.14 Example: For r = 5 cm, h = 12 cm T.S.A. = 2π(5)(12 + 5) = 2π(5)(17) = 170

Card 3Cylinder - Surface Area

A cylindrical drum has height 20 cm and base radius 14 cm. Find its total surface area.

Answer

Formula: T.S.A. = 2πr(h + r) Given: h = 20 cm, r = 14 cm Step 1: T.S.A. = 2 × (22/7) × 14 × (20 + 14) Step 2: T.S.A. = 2 × (22/7) × 14 × 34 Step 3: T.S.A. = 2 × 22 × 2 × 34 Step 4: T.S.A. = 2992 cm² A

Card 4Cylinder - Surface Area

The curved surface area of a cylinder is 88 cm² and height is 14 cm. Find the diameter.

Answer

Formula: C.S.A. = 2πrh Given: C.S.A. = 88 cm², h = 14 cm Step 1: 88 = 2 × (22/7) × r × 14 Step 2: 88 = 2 × 22 × r × 2 Step 3: 88 = 88r Step 4: r = 1 cm Step 5: Diameter = 2r = 2 cm Answer: 2 cm

Card 5Cylinder - Application

A garden roller of length 3 m and diameter 2.8 m covers what area in 8 revolutions?

Answer

Concept: One revolution = curved surface area of cylinder Given: Length h = 3 m, Diameter d = 2.8 m, Radius r = 1.4 m Step 1: Area in 1 revolution = C.S.A. = 2πrh Step 2: Area = 2 × (22/7) × 1.4 × 3 S

Card 6Cone - Formulas

Formula for curved surface area of a right circular cone

Answer

C.S.A. of cone = πrl square units Where: - r = radius of the base - l = slant height = √(h² + r²) - h = height of the cone Example: For r = 5 cm, h = 12 cm First find l: l = √(144 + 25) = √169 = 13

Card 7Cone - Surface Area Application

A conical tent has radius 7 m and height 24 m. Calculate the length of canvas needed if canvas width is 4 m.

Answer

Step 1: Find slant height l = √(r² + h²) = √(49 + 576) = √625 = 25 m Step 2: C.S.A. = πrl = (22/7) × 7 × 25 = 550 m² Step 3: Length of canvas = Area ÷ Width = 550 ÷ 4 = 137.5 m Answer: 137.5 m of canv

Card 8Cone - Formulas

Formula for total surface area of a cone

Answer

T.S.A. of cone = πr(l + r) square units Alternatively: T.S.A. = πrl + πr² Where: - r = radius of the base - l = slant height - π ≈ 22/7 Example: For r = 7 cm, l = 25 cm T.S.A. = (22/7) × 7 × (25 + 7

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Frequently Asked Questions

What are the important topics in Mensuration for Tamil Nadu Board Class 10 Mathematics?
Key topics in Mensuration include Mensuration Concepts Hierarchy, Mensuration Chapter Overview, Mensuration – Complete Formula Overview. These are the concepts Tamil Nadu Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Mensuration — Tamil Nadu Board Class 10 Mathematics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Mensuration?
There are 40 flashcards for Mensuration covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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