Surface Chemistry
Tamil Nadu Board · Class 12 · Chemistry
Practice quiz for Surface Chemistry — Tamil Nadu Board Class 12 Chemistry. MCQs and questions with answers to test your preparation.
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Quick Quiz: Surface Chemistry
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According to the Freundlich adsorption isotherm, a graph of log(x/m) versus log P gives a straight line. If the slope of this line is 0.4 and the intercept is 0.6, what is the amount of gas adsorbed (x/m) when pressure P = 100 atm? (Given: log K = 0.6)
In the manufacture of sulphuric acid by the Contact Process, the catalyst V₂O₅ is used. Which of the following correctly describes the role of V₂O₅ in the reaction 2SO₂(g) + O₂(g) → 2SO₃(g)?
The gold number of gelatin is 0.005–0.01 mg and that of potato starch is 25 mg. Which of the following conclusions is CORRECT?
During enzyme catalysis, the enzyme urease catalyses the hydrolysis of urea but does NOT catalyse the hydrolysis of methyl urea (H₂N-CO-NH-CH₃). This is best explained by which property of enzyme catalysis?
Sample Questions
In the Bredig's arc method for preparation of colloidal gold, an electrical arc is struck between gold electrodes in ice-cold water. Why is the water kept ice-cold during this process?
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To prevent coagulation of colloidal gold particles by keeping thermal energy of particles low
Step 1: In Bredig's arc method, gold electrodes produce an arc that vaporises gold, which then condenses in water to form colloidal particles. Step 2: The newly formed colloidal particles are extremely small (1–200 nm) and thermodynamically unstable — they tend to aggregate (coagulate) due to their high surface energy. Step 3: At higher temperatures, colloidal particles gain more kinetic energy, collide more frequently, and coagulate more readily. Ice-cold water removes this thermal energy, reducing particle motion and collision frequency. Step 4: Option A is incorrect — conductivity is not th
In the process of dialysis for purifying a colloidal solution of Fe(OH)₃, the colloidal solution is placed inside a semipermeable membrane bag suspended in flowing water. Which of the following statements CORRECTLY explains why this purification works?
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The pores of the semipermeable membrane allow small ions (like Fe³⁺ and Cl⁻ from FeCl₃ impurity) to pass through but retain larger colloidal Fe(OH)₃ particles
Step 1: Fe(OH)₃ sol is prepared by hydrolysis of FeCl₃: FeCl₃ + 3H₂O → Fe(OH)₃ (sol) + 3HCl. The impurity is excess FeCl₃ or HCl (electrolytes containing small Fe³⁺, Cl⁻ ions). Step 2: The semipermeable membrane has pores of size intermediate between colloidal particles (1–200 nm) and true solution ions (< 1 nm). Step 3: Small electrolyte ions (Fe³⁺, Cl⁻, H⁺) pass freely through the membrane pores, diffusing into the flowing water and being carried away. Colloidal Fe(OH)₃ particles (larger size) cannot pass through and are retained. Step 4: Option A is wrong — charge of colloidal particles is
Consider the following statement about chemisorption: 'When temperature is raised, chemisorption first increases and then decreases.' Which of the following CORRECTLY explains this observation?
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Initial increase occurs because chemisorption requires activation energy — higher temperature activates more molecules; decrease at high temperature is due to desorption as kinetic energy of adsorbate exceeds adsorption energy
Step 1: Chemisorption involves formation of chemical bonds between adsorbent and adsorbate, which requires activation energy (unlike physisorption). Step 2: At low temperatures, molecules do not have sufficient energy to overcome the activation energy barrier. As temperature increases, more molecules gain enough energy → chemisorption increases. This is why chemisorption is also called 'activated adsorption'. Step 3: At very high temperatures, the kinetic energy of adsorbed molecules becomes very large. These molecules overcome the adsorption forces and escape from the surface — this is called
In the Haber's process for ammonia synthesis: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), iron is used as a catalyst and molybdenum as a promoter. H₂S is a catalyst poison. Which of the following CORRECTLY explains the action of H₂S as a catalyst poison based on adsorption theory?
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H₂S molecules are preferentially and strongly adsorbed on the active centres (steps, cracks, corners) of the Fe catalyst surface, blocking N₂ and H₂ from adsorbing
Step 1: According to adsorption theory, heterogeneous catalysis occurs at 'active centres' — coordinatively unsaturated atoms at steps, cracks, and corners of the catalyst surface that have residual bonding forces. Step 2: H₂S molecules have a strong affinity for iron surfaces and get chemisorbed onto these active centres with great strength. Since chemisorption forms monolayers, these sites become permanently occupied. Step 3: With active centres blocked, N₂ and H₂ molecules cannot adsorb on the Fe surface → no activated complex formation → no catalysis. Step 4: Option A is wrong — H₂S does n
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