Complex Numbers and De Moivre’s Theorem — Revision Notes
Telangana Open School (TOSS) · Class 12 · Mathematics
Complex Numbers and De Moivre’s Theorem revision notes for Telangana Open School (TOSS) Class 12 Mathematics: 4 topics in quick points.
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Key Topics to Revise
Introduction to Complex Numbers
- The equation \(x^2 + 1 = 0\) has no real solution because the square of any real number is non-negative.
- To solve such equations, we introduce a new number \(i = \sqrt{-1}\), called iota.
- A complex number is any number of the form \(z = a + bi\), where \(a\) and \(b\) are real numbers and \(i = \sqrt{-1}\).
Algebra of Complex Numbers
- Addition: \((a + bi) + (c + di) = (a + c) + (b + d)i\)
- Subtraction: \((a + bi) - (c + di) = (a - c) + (b - d)i\)
- Multiplication: \((a + bi)(c + di) = (ac - bd) + (ad + bc)i\)
Modulus, Argument, and Polar Form
- Modulus of \(z = a + bi\) is \(|z| = \sqrt{a^2 + b^2}\).
- Argument \(\theta\) is the angle made with the positive real axis: \(\theta = \tan^{-1}(b/a)\).
- Polar form: \(z = r(\cos\theta + i\sin\theta)\), where \(r = |z|\).
De Moivre’s Theorem and Applications
- De Moivre’s Theorem: \((\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta)\) for any integer \(n\).
- Used to find powers and roots of complex numbers easily.
- \(n^{\text{th}}\) roots of unity are solutions to \(x^n = 1\), given by \(\cos(2k\pi/n) + i\sin(2k\pi/n)\), \(k = 0,1,\dots,n-1\).
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