CBSE Class 11 Biotechnology — NCERT Solutions
CBSE Class 11 Biotechnology NCERT solutions, chapter by chapter — 136 textbook questions solved across 12 chapters. Follows the CBSE syllabus.
About these solutions
136 NCERT textbook questions for CBSE Class 11 Biotechnology, solved step by step across 12 chapters. Each chapter page has every exercise: half the solutions are open to read and the rest are free with a Super Tutor account.
Introduction
5 questions solved
- Exercises · 5 questions
Q1.What do you understand by the term 'Biotechnology'? Explain giving suitable examples.
Given/Concept: The term 'Biotechnology' combines 'biology' and 'technology'. It refers to the use of living organisms, cells, or their components to develop products and processes for human welfare.
Definition:
Biotechnology is defined as the integration of natural sciences and engineering sciences in order to achieve the application of organisms, cells, parts thereof, and molecular analogues for products and services. (European Federation of Biotechnology, EFB)
In simpler terms, biotechnology involves the use of biological systems (microorganisms, plants, animals, or their components) to develop useful products and processes.
Key aspects of Biotechnology:
- It uses living organisms or their derivatives.
- It involves manipulation at the molecular, cellular, or organismal level.
- It aims at producing useful products or solving problems.
Examples:
| Example | Description |
|---|---|
| Insulin production | Human insulin gene is inserted into bacteria (E. coli) using recombinant DNA technology to produce insulin for diabetic patients. |
| Fermentation | Yeast (Saccharomyces cerevisiae) is used to produce beer, wine, bread, and other fermented products — an ancient biotechnological practice. |
| Bt crops | Genes from Bacillus thuringiensis are introduced into crop plants (e.g., Bt cotton) to make them resistant to insect pests. |
| Vaccines | Hepatitis B vaccine is produced using yeast cells that carry the gene for the hepatitis B surface antigen. |
| Cheese and curd | Microorganisms like Lactobacillus are used to convert milk into curd and cheese. |
Conclusion: Biotechnology is a broad, multidisciplinary field that harnesses biological knowledge and engineering principles to benefit agriculture, medicine, industry, and the environment.
Q2.Give a comparative account of the ancient and modern concept of biotechnology.
Given/Concept: Biotechnology has been practised by humans for thousands of years, but the nature and scale of its application have changed dramatically with advances in science.
Comparative Account:
| Basis of Comparison | Ancient (Traditional) Biotechnology | Modern Biotechnology |
|---|---|---|
| Time period | Since prehistoric times (8000–10000 years ago) | From the 1970s onwards |
| Knowledge base | Empirical; based on trial and error | Scientific; based on molecular biology, genetics, and biochemistry |
| Techniques used | Fermentation, selective breeding, hybridisation | Recombinant DNA technology, tissue culture, genetic engineering, PCR, CRISPR |
| Organisms used | Microorganisms (yeast, bacteria), plants, animals | Microorganisms, plants, animals at the molecular/genetic level |
| Scale of manipulation | Organism or cellular level | Molecular (DNA/protein) level |
| Examples | Making curd, bread, wine, beer; selective breeding of cattle and crops | Production of human insulin, Bt crops, gene therapy, monoclonal antibodies, transgenic animals |
| Precision | Low; unpredictable outcomes | Very high; specific genes can be targeted |
| Products | Food, beverages, improved crop varieties | Biopharmaceuticals, vaccines, diagnostic kits, stress-resistant crops |
| Ethical concerns | Minimal | Significant (GMO safety, bioethics, biosafety) |
Key Distinction:
- Ancient biotechnology relied on naturally occurring biological processes without understanding the underlying mechanisms.
- Modern biotechnology deliberately manipulates genetic material (DNA) to achieve desired outcomes with precision and predictability.
Conclusion: While ancient biotechnology laid the foundation by demonstrating the utility of microorganisms and selective breeding, modern biotechnology has revolutionised the field by enabling precise genetic manipulation, leading to products and solutions that were previously unimaginable.
Cellular Organelles
13 questions solved
- EXERCISES — Cellular Organelles · 13 questions
Q1.The Fluid Mosaic Model has been proposed by
(a) Robert Brown
(b) Schleiden and Schwann
(c) Robert Virchow
(d) Singer and Nicolson
Correct Option: (d) Singer and Nicolson
The Fluid Mosaic Model of the plasma membrane was proposed by S.J. Singer and G.L. Nicolson in 1972. According to this model, the membrane is a fluid phospholipid bilayer in which proteins are embedded (like a mosaic), and both lipids and proteins can move laterally. Robert Brown discovered the nucleus; Schleiden and Schwann proposed the Cell Theory; Virchow proposed 'Omnis cellula e cellula'.
Q2.Ribosomes are composed of
(a) only rRNA
(b) rRNA and proteins
(c) rRNA, proteins and DNA
(d) lipids, proteins and DNA
Correct Option: (b) rRNA and proteins
Ribosomes are ribonucleoprotein particles composed of ribosomal RNA (rRNA) and proteins. They do not contain DNA or lipids. Each ribosome consists of two subunits (large and small), both made of rRNA molecules associated with specific ribosomal proteins. They are the sites of protein synthesis in the cell.
Biomolecules
30 questions solved
- Exercises · 30 questions
Q1.Describe the classification of carbohydrates.
Given/Concept: Carbohydrates are polyhydroxy aldehydes or ketones. They are classified on the basis of the number of sugar units they contain.
Classification of Carbohydrates:
1. Monosaccharides (Simple sugars):
- Cannot be hydrolysed further into simpler sugars.
- General formula: where to .
- Classified by number of carbon atoms:
- Trioses (): e.g., Glyceraldehyde, Dihydroxyacetone
- Tetroses (): e.g., Erythrose
- Pentoses (): e.g., Ribose, Deoxyribose
- Hexoses (): e.g., Glucose, Fructose, Galactose
- Heptoses (): e.g., Sedoheptulose
- Further classified as aldoses (contain aldehyde group, ) or ketoses (contain ketone group, ).
2. Oligosaccharides:
- Contain 2–10 monosaccharide units joined by glycosidic bonds.
- Sub-classified as:
- Disaccharides (2 units): e.g., Sucrose (glucose + fructose), Maltose (glucose + glucose), Lactose (glucose + galactose)
- Trisaccharides (3 units): e.g., Raffinose
- Tetrasaccharides (4 units): e.g., Stachyose
3. Polysaccharides:
- Contain more than 10 (often hundreds to thousands) monosaccharide units.
- Two types:
- Homopolysaccharides: Made of one type of monosaccharide. e.g., Starch, Glycogen, Cellulose (all made of glucose)
- Heteropolysaccharides: Made of two or more types of monosaccharides. e.g., Hyaluronic acid, Heparin
Conclusion: Carbohydrates are broadly classified into monosaccharides, oligosaccharides, and polysaccharides based on the degree of polymerisation.
Q2.Differentiate between D- and L-forms of glucose.
Concept: The D- and L- designation of glucose is based on the configuration of the asymmetric carbon atom farthest from the carbonyl (aldehyde) group, i.e., C-5 in glucose. This is compared to the reference molecule glyceraldehyde.
| Feature | D-Glucose | L-Glucose |
|---|---|---|
| Configuration at C-5 | The group on C-5 is on the right side (same as D-glyceraldehyde) | The group on C-5 is on the left side (same as L-glyceraldehyde) |
| Reference | Based on D-glyceraldehyde | Based on L-glyceraldehyde |
| Occurrence in nature | Naturally occurring form; found in plants and animals | Rarely found in nature |
| Biological activity | Metabolically active; can be utilised by cells | Not metabolised by most organisms |
| Optical rotation | Dextrorotatory (+) — rotates plane-polarised light to the right | Levorotatory (−) — rotates plane-polarised light to the left |
| Mirror image | D and L forms are mirror images (enantiomers) of each other | Mirror image of D-glucose |
Note: The D/L designation refers to the spatial configuration at the reference carbon, not to the direction of optical rotation.
Conclusion: D- and L-glucose are enantiomers differing in the orientation of the group at C-5. D-glucose is the biologically important form.
Enzymes and Bioenergetics
11 questions solved
- EXERCISES — Enzymes and Bioenergetics · 11 questions
Q1.In order to catalyse a reaction, an enzyme is required to
(a) be saturated with substrate
(b) decrease the activation energy
(c) increase the equilibrium constant
(d) increase the activation energy
Correct Option: (b) decrease the activation energy
Justification: Enzymes are biological catalysts. They function by lowering the activation energy (energy barrier) required for a reaction to proceed, thereby increasing the rate of the reaction. Enzymes do not alter the equilibrium constant of a reaction, nor do they need to be saturated with substrate to catalyse a reaction. They certainly do not increase the activation energy.
Cellular Processes
14 questions solved
- Exercises · 14 questions
Q1(a).Give a comparative account of Apoptosis and Necrosis.
Apoptosis vs. Necrosis
| Feature | Apoptosis | Necrosis |
|---|---|---|
| Nature | Programmed (controlled) cell death | Uncontrolled, accidental cell death |
| Cause | Developmental signals, DNA damage, immune signals | Physical injury, toxins, infection, ischemia |
| Energy requirement | ATP-dependent (active process) | Does not require ATP (passive process) |
| Cell morphology | Cell shrinks, chromatin condenses, membrane blebbing | Cell swells, membrane ruptures |
| Inflammation | No inflammation; apoptotic bodies are phagocytosed | Causes inflammation due to release of cellular contents |
| DNA fragmentation | Internucleosomal DNA fragmentation (ladder pattern) | Random DNA degradation |
| Outcome | Beneficial; removes unwanted or damaged cells | Harmful; leads to tissue damage |
Conclusion: Apoptosis is a physiologically regulated process essential for normal development and homeostasis, whereas necrosis is a pathological process resulting from acute cellular injury.
Basic Principles of Inheritance
7 questions solved
- EXERCISES — Basic Principles of Inheritance · 7 questions
Q1.Differentiate between the following:
(a) Genotype and Phenotype
(b) Dominant and Recessive characters
(c) Hybrid and Pure individuals
(d) Heterozygous and Homozygous progeny
(e) Monohybrid and Dihybrid cross
(f) Gene and allele
(g) Incomplete dominance and codominance
(a) Genotype and Phenotype
| Feature | Genotype | Phenotype |
|---|---|---|
| Definition | The genetic constitution (allelic combination) of an organism | The observable/expressed characteristics of an organism |
| Visibility | Cannot be seen directly; determined by molecular/breeding analysis | Can be observed directly (morphology, physiology, behaviour) |
| Example | , , | Tall, Tall, Dwarf |
| Stability | Remains constant throughout life | Can be influenced by environment |
(b) Dominant and Recessive Characters
| Feature | Dominant Character | Recessive Character |
|---|---|---|
| Definition | The character that expresses itself in the hybrid (heterozygous condition) | The character that remains suppressed in the presence of the dominant allele |
| Expression | Expressed in both homozygous () and heterozygous () state | Expressed only in homozygous state () |
| Example | Tallness () in pea | Dwarfness () in pea |
(c) Hybrid and Pure Individuals
| Feature | Hybrid Individual | Pure Individual |
|---|---|---|
| Definition | An individual produced by crossing two genetically different parents; carries two different alleles for a trait | An individual that breeds true for a trait; carries two identical alleles |
| Genotype | Heterozygous, e.g., | Homozygous, e.g., or |
| Offspring | Produces varied offspring on selfing | Produces identical offspring on selfing |
(d) Heterozygous and Homozygous Progeny
| Feature | Heterozygous Progeny | Homozygous Progeny |
|---|---|---|
| Definition | Progeny carrying two different alleles for a gene locus | Progeny carrying two identical alleles for a gene locus |
| Genotype | e.g., , | e.g., , , , |
| Gametes produced | Two types of gametes | Only one type of gamete |
| Breeding behaviour | Does not breed true | Breeds true |
(e) Monohybrid and Dihybrid Cross
| Feature | Monohybrid Cross | Dihybrid Cross |
|---|---|---|
| Definition | Cross between parents differing in only one pair of contrasting characters | Cross between parents differing in two pairs of contrasting characters |
| Example | (tall dwarf) | (tall round dwarf wrinkled) |
| Phenotypic ratio | ||
| Genotypic ratio | ||
| Law demonstrated | Law of Dominance and Law of Segregation | Law of Independent Assortment |
(f) Gene and Allele
| Feature | Gene | Allele |
|---|---|---|
| Definition | A specific segment of DNA that codes for a particular protein/trait | Alternative forms of the same gene occupying the same locus on homologous chromosomes |
| Location | Occupies a specific locus on a chromosome | Present at the same locus but on homologous chromosomes |
| Example | Gene for seed colour in pea | (round) and (wrinkled) are alleles of the seed-shape gene |
(g) Incomplete Dominance and Codominance
| Feature | Incomplete Dominance | Codominance |
|---|---|---|
| Definition | Neither allele is completely dominant; the heterozygote shows an intermediate phenotype | Both alleles are expressed simultaneously and independently in the heterozygote |
| Phenotype | Intermediate between two parents | Both parental phenotypes expressed together |
| Phenotypic ratio | (same as genotypic ratio) | (same as genotypic ratio) |
| Example | Flower colour in Antirrhinum (snapdragon): Red () White () Pink () | ABO blood groups: genotype shows both A and B antigens (AB blood group) |
Basic Processes
7 questions solved
- Exercises · 7 questions
Q1.What is the importance of gene expression? What are the steps involved in it?
Given / Concept: Gene expression is the process by which the information encoded in a gene is used to synthesize a functional gene product (usually a protein).
Importance of Gene Expression:
- It converts the genetic information stored in DNA into functional proteins that carry out all biological activities of a cell.
- It regulates growth, development, differentiation, and metabolism of an organism.
- It allows cells to respond to environmental changes by switching genes on or off.
- It determines the phenotype of an organism.
- It is essential for maintaining cellular homeostasis.
Steps Involved in Gene Expression:
Step 1 — Transcription:
- The DNA double helix unwinds at the gene locus.
- RNA polymerase binds to the promoter region and reads the template (antisense) strand in the direction.
- A complementary mRNA strand is synthesized in the direction.
- In eukaryotes, the primary transcript (pre-mRNA) undergoes post-transcriptional modifications: addition of 5' cap, 3' poly-A tail, and splicing out of introns to produce mature mRNA.
Step 2 — Translation:
- The mature mRNA moves to the ribosome.
- The ribosome reads the mRNA codons (triplets of bases) in the direction.
- tRNA molecules carry specific amino acids; their anticodons pair with the mRNA codons.
- Peptide bonds form between successive amino acids, elongating the polypeptide chain.
- Translation ends at a stop codon (UAA, UAG, or UGA).
- The polypeptide is released and folds into a functional protein (sometimes requiring post-translational modifications).
Summary equation:
Final Answer: Gene expression is vital for converting genetic information into functional proteins. It involves two main steps: transcription (DNA → mRNA) and translation (mRNA → Protein).
Genetic Disorder
5 questions solved
- Exercises · 5 questions
Q1.Define following terms: dominant, recessive, homozygous, heterozygous, phenotype and genotype.
Given: A set of fundamental genetic terms to be defined.
Definitions:
(i) Dominant:
A dominant allele is one that expresses its effect (trait) in the phenotype even when only one copy is present (i.e., in heterozygous condition). It masks the effect of the recessive allele. It is conventionally represented by a capital letter (e.g., ).
(ii) Recessive:
A recessive allele is one whose effect is masked by the dominant allele when both are present together. It expresses itself only when present in homozygous condition (i.e., two copies of the recessive allele are present). It is represented by a lowercase letter (e.g., ).
(iii) Homozygous:
An organism is said to be homozygous for a particular gene locus when it carries two identical alleles at that locus on homologous chromosomes. It can be homozygous dominant () or homozygous recessive (). Homozygous organisms breed true for that trait.
(iv) Heterozygous:
An organism is said to be heterozygous for a particular gene locus when it carries two different alleles at that locus on homologous chromosomes (e.g., ). The dominant allele is expressed in the phenotype, while the recessive allele remains hidden. Such organisms are also called carriers.
(v) Phenotype:
Phenotype refers to the observable physical, biochemical, or physiological characteristics of an organism that result from the interaction of its genotype with the environment. Examples include height, eye colour, blood group, and skin colour. Two organisms with different genotypes may have the same phenotype (e.g., and both show the dominant phenotype).
(vi) Genotype:
Genotype refers to the complete genetic constitution (allelic composition) of an organism for a particular trait or for all traits. It represents the actual set of alleles present in the organism's genome. For example, for a gene with alleles and , possible genotypes are , , or . The genotype determines the potential phenotype of the organism.
Introduction to Bioinformatics
11 questions solved
- Exercises · 11 questions
Q1.Name the two modalities of analysis following sequencing.
Given: A question about the two modalities of analysis that follow sequencing.
Answer:
The two modalities of analysis following sequencing are:
- De novo assembly – In this approach, the sequenced reads are assembled without the use of a reference genome. It is used when no reference genome is available for the organism under study.
- Reference-guided (Genome-guided) assembly/mapping – In this approach, the sequenced reads are aligned or mapped to an already available reference genome. It is used when a well-annotated reference genome exists for the organism.
Protein Informatics and Cheminformatics
6 questions solved
- EXERCISES — Protein Informatics and Cheminformatics · 6 questions
Q1.What is the role of information technology in determination of protein properties?
Given/Concept: Information technology (IT) provides computational tools and databases that allow scientists to analyse protein sequences and structures without performing every experiment in the laboratory.
Answer:
Information technology plays a crucial role in the determination of protein properties in the following ways:
- Sequence Analysis: IT tools allow rapid analysis of amino acid sequences to determine physicochemical properties such as molecular weight, isoelectric point (pI), instability index, aliphatic index, and GRAVY (Grand Average of Hydropathy) value. Servers like ProtParam (ExPASy) perform these calculations automatically from raw sequence data.
- Secondary Structure Prediction: Tools such as APSSP, CPSSP, SOPMA, and GOR predict the secondary structural elements (α-helices, β-sheets, coils) of a protein from its primary sequence.
- Domain and Motif Prediction: IT-based tools (e.g., PROSITE, Pfam, InterPro) identify functional domains and conserved motifs within a protein sequence.
- 3D Structure Prediction: Computational methods like homology modelling, fold prediction, and de novo prediction use IT to build three-dimensional models of proteins whose structures have not been experimentally determined.
- Database Management: Large biological databases (UniProt, PDB, NCBI) store and organise vast amounts of protein data, making it accessible for analysis worldwide.
Conclusion: Thus, information technology accelerates protein characterisation, reduces experimental cost and time, and enables large-scale proteomics studies.
Programming and Systems Biology
9 questions solved
- EXERCISES — Programming and Systems Biology (Biotechnology, Class 11) · 9 questions
Q1.Why are programming languages a boon for biologists?
Given / Context: Modern biology generates enormous volumes of data (genomic sequences, proteomics data, metabolic networks, etc.) that cannot be handled manually.
Answer:
Programming languages are considered a boon for biologists for the following reasons:
- Handling large datasets: Biological experiments (e.g., genome sequencing, microarray analysis) produce massive datasets. Programming languages such as Python, R, and Perl allow biologists to store, retrieve, and process these datasets efficiently.
- Statistical analysis: Programming languages provide built-in and third-party statistical libraries (e.g., NumPy, SciPy in Python; statistical packages in R) that help biologists perform complex statistical analyses without requiring deep mathematical expertise.
- Automation: Repetitive tasks such as sequence alignment, BLAST searches, and data formatting can be automated using scripts, saving enormous time and reducing human error.
- Visualisation: Libraries like Matplotlib (Python) and ggplot2 (R) allow biologists to create publication-quality graphs and visual representations of biological data.
- Bioinformatics tools: Most bioinformatics applications (e.g., BLAST, ClustalW, genome browsers) are built on programming platforms, and knowledge of programming helps biologists customise and extend these tools.
- Modelling and simulation: Programming languages enable the construction of computational models of metabolic pathways, signalling networks, and gene regulatory networks, which is central to systems biology.
Conclusion: Thus, programming languages bridge the gap between raw biological data and meaningful biological insight, making them indispensable tools for modern biologists.
Tools and Techniques
18 questions solved
- EXERCISES — Chapter: Tools and Techniques (Biotechnology, CBSE Class 11) · 18 questions
Q1.The function of ethidium bromide in electrophoresis is to
(a) track the progression of electrophoresis
(b) visualise the DNA molecules
(c) separate the DNA molecules
(d) provide charge to DNA molecules
Correct Option: (b) visualise the DNA molecules
Justification: Ethidium bromide (EtBr) is a fluorescent intercalating dye that inserts itself between the stacked base pairs of DNA. When exposed to UV light, it fluoresces bright orange, making the DNA bands visible on the agarose gel. It does not separate DNA, provide charge, or track electrophoresis progression (that is done by tracking dyes like bromophenol blue).
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This page has NCERT solutions for 12 chapters of CBSE Class 11 Biotechnology for the 2026-27 session. Each chapter links to its own page with the full set.
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Go through the syllabus first, then work chapter by chapter: learn the ideas, practise questions, and revise with notes and flashcards. Leave time at the end to revise every chapter once more under timed conditions.
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