Reflection
ICSE · Class 10 · Mathematics
Flashcards for Reflection — ICSE Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
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See them allSolve: Find the reflection of P(4, 5) in the x-axis.
Answer
Step 1: Use the reflection rule in the x-axis: M_x(x,y) = (x,-y). Step 2: Substitute x = 4 and y = 5. Step 3: P' = (4,-5). Answer: (4,-5)…
Solve: Find the reflection of P(-3, 7) in the y-axis.
Answer
Step 1: Use the reflection rule in the y-axis: M_y(x,y) = (-x,y). Step 2: Substitute x = -3 and y = 7. Step 3: P' = (3,7). Answer: (3,7)…
Solve: Find the reflection of P(2, 3) in the origin.
Answer
Step 1: Use the reflection rule in the origin: M_0(x,y) = (-x,-y). Step 2: Substitute x = 2 and y = 3. Step 3: P' = (-2,-3). Answer: (-2,-3)…
Solve: Find the reflection of P(4, 5) in the line y = 2.
Answer
Step 1: Use the formula for reflection in y = a: (x,y) -> (x,-y+2a). Step 2: Here, a = 2, x = 4, y = 5. Step 3: New point = (4, -5 + 2×2) = (4, -1). Answer: (4,-1)…
Solve: Find the reflection of P(-2, -3) in the line y = 2.
Answer
Step 1: Use (x,y) -> (x,-y+2a). Step 2: Here, a = 2, x = -2, y = -3. Step 3: New point = (-2, -(-3) + 2×2) = (-2, 3 + 4) = (-2,7). Answer: (-2,7)…
Solve: Find the reflection of P(3, 4) in the line y = -1.
Answer
Step 1: Use (x,y) -> (x,-y+2a). Step 2: Here, a = -1, x = 3, y = 4. Step 3: New point = (3, -4 + 2×(-1)) = (3, -4 - 2) = (3,-6). Answer: (3,-6)…
Solve: Find the reflection of P(-3, -4) in the line x = 2.
Answer
Step 1: Use the formula for reflection in x = a: (x,y) -> (-x+2a, y). Step 2: Here, a = 2, x = -3, y = -4. Step 3: New point = (-(-3) + 2×2, -4) = (3 + 4, -4) = (7,-4). Answer: (7,-4)…
Solve: Find the reflection of P(2, 5) in the line x = -1.
Answer
Step 1: Use (x,y) -> (-x+2a, y). Step 2: Here, a = -1, x = 2, y = 5. Step 3: New point = (-2 + 2×(-1), 5) = (-2 - 2, 5) = (-4,5). Answer: (-4,5)…
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