Pythagoras Theorem — Chapter Summary
Maharashtra Board · Class 10 · Mathematics
Summary of Pythagoras Theorem for Maharashtra Board Class 10 Mathematics. Part of the Maharashtra Board Class 10 Mathematics syllabus.
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Overview
Count the square on the hypotenuse and compare it with the squares on the other two sides. In a right angled triangle, that check gives the central idea of Pythagoras theorem: the square of the hypotenuse equals the sum of the squares of the remaining two sides.
Key Concepts
In a right angled triangle
In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. For triangle PQR with angle PQR =
A triplet of natural numbers
A triplet of natural numbers is a Pythagorean triplet if the square of the largest number equals the sum of the squares of the other two numbers. Exam
If a and b are natural
If a and b are natural numbers with a > b, then [(a^2 + b^2), (a^2 - b^2), (2ab)] is a Pythagorean triplet. For a = 5 and b = 3, the triplet is (34,16
If the acute angles are 30°
If the acute angles are 30° and 60°, then the side opposite 30° is half the hypotenuse and the side opposite 60° is (√3/2) times the hypotenuse. In tr
If the acute angles are 45°
If the acute angles are 45° and 45°, then each perpendicular side is (1/√2) times the hypotenuse. In triangle XYZ, XY = XZ = (1/√2) × ZY. If ZY = 3√2
Learning Objectives
- State Pythagoras theorem in a right angled triangle.
- Use the theorem in the forms PR^2 = PQ^2 + QR^2 and q^2 = p^2 + r^2.
- Identify and verify Pythagorean triplets.
- Use the formula [(a^2 + b^2), (a^2 - b^2), (2ab)] for Pythagorean triplets when a > b.
- Apply side ratios of 30-60-90 and 45-45-90 triangles.
Frequently Asked Questions
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Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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