Areas Related to Circles
Madhya Pradesh Board · Class 10 · Mathematics
Flashcards for Areas Related to Circles — Madhya Pradesh Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
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See them allFind the area of a sector with radius 4 cm and angle 30°.
Answer
Step 1: Use area of a sector = (θ/360) × πr². Step 2: Substitute θ = 30° and r = 4 cm. Step 3: Area = (30/360) × 3.14 × 4² = (1/12) × 3.14 × 16. Step 4: Area = 4.1867... cm². Answer: 4.19 cm² approxim…
त्रिज्या 4 cm और कोण 30° वाले सेक्टर का क्षेत्रफल ज्ञात कीजिए।
Answer
चरण 1: सेक्टर का क्षेत्रफल = (θ/360) × πr² का उपयोग कीजिए। चरण 2: θ = 30° और r = 4 cm रखिए। चरण 3: क्षेत्रफल = (30/360) × 3.14 × 4² = (1/12) × 3.14 × 16। चरण 4: क्षेत्रफल = 4.1867... cm²। उत्तर: लगभग …
Find the area of the corresponding major sector when the minor sector has radius 4 cm and angle 30°.
Answer
Step 1: Area of the circle = πr² = 3.14 × 4² = 50.24 cm². Step 2: Minor sector area = 4.19 cm². Step 3: Major sector area = total circle area − minor sector area. Step 4: Major sector area = 50.24 − 4…
जब लघु सेक्टर की त्रिज्या 4 cm और कोण 30° हो, तो उससे संबंधित दीर्घ सेक्टर का क्षेत्रफल ज्ञात कीजिए।
Answer
चरण 1: वृत्त का क्षेत्रफल = πr² = 3.14 × 4² = 50.24 cm²। चरण 2: लघु सेक्टर का क्षेत्रफल = 4.19 cm²। चरण 3: दीर्घ सेक्टर का क्षेत्रफल = कुल वृत्त का क्षेत्रफल − लघु सेक्टर का क्षेत्रफल। चरण 4: दीर्घ से…
Find the length of an arc of a sector with radius 21 cm and angle 60°.
Answer
Step 1: Use length of an arc = (θ/360) × 2πr. Step 2: Substitute θ = 60° and r = 21 cm. Step 3: Arc length = (60/360) × 2 × (22/7) × 21. Step 4: Arc length = (1/6) × 132 = 22 cm. Answer: 22 cm.
त्रिज्या 21 cm और कोण 60° वाले सेक्टर के चाप की लंबाई ज्ञात कीजिए।
Answer
चरण 1: चाप की लंबाई = (θ/360) × 2πr का उपयोग कीजिए। चरण 2: θ = 60° और r = 21 cm रखिए। चरण 3: चाप की लंबाई = (60/360) × 2 × (22/7) × 21। चरण 4: चाप की लंबाई = (1/6) × 132 = 22 cm। उत्तर: 22 cm।…
Find the area of the sector of radius 21 cm and angle 120°.
Answer
Step 1: Use area of a sector = (θ/360) × πr². Step 2: Substitute θ = 120° and r = 21 cm. Step 3: Area = (120/360) × (22/7) × 21². Step 4: Area = (1/3) × (22/7) × 441 = 462 cm². Answer: 462 cm².
त्रिज्या 21 cm और कोण 120° वाले सेक्टर का क्षेत्रफल ज्ञात कीजिए।
Answer
चरण 1: सेक्टर का क्षेत्रफल = (θ/360) × πr² का उपयोग कीजिए। चरण 2: θ = 120° और r = 21 cm रखिए। चरण 3: क्षेत्रफल = (120/360) × (22/7) × 21²। चरण 4: क्षेत्रफल = (1/3) × (22/7) × 441 = 462 cm²। उत्तर: 462…
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