Coordinate Geometry — Flashcards
Madhya Pradesh Board · Class 10 · Mathematics
48 flashcards for Coordinate Geometry (Madhya Pradesh Board Class 10 Mathematics) to test yourself on key terms and facts.
Interactive on Super Tutor
Studying Coordinate Geometry? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
Free trial, no card needed.
Learn better with visuals Super Tutor pairs illustrations like this with notes and quizzes for Coordinate Geometry.
Find the coordinates of a point on the x-axis that is 5 units from the origin.
Answer
Step 1: A point on the x-axis has the form (x, 0). Step 2: The distance from the origin is OP = √(x² + y²). Step 3: Here y = 0 and OP = 5, so √(x²) = 5. Step 4: So, x = 5 or x = -5. Answer: The point …
x-अक्ष पर एक बिंदु के निर्देशांक ज्ञात कीजिए जो मूल बिंदु से 5 इकाई दूर है।
Answer
चरण 1: x-अक्ष पर एक बिंदु का रूप (x, 0) है। चरण 2: मूल से दूरी OP = √(x² + y²) है। चरण 3: यहाँ y = 0 और OP = 5 है, इसलिए √(x²) = 5 है। चरण 4: तो, x = 5 or x = -5. उत्तर: बिंदु (5, 0) या (-5, 0) हो सकत…
Find the distance between A(4, 0) and B(6, 0).
Answer
Step 1: Both points lie on the x-axis. Step 2: Distance on the x-axis is found by subtracting x-values. Step 3: AB = 6 - 4 = 2 units. Answer: 2 units…
A(4, 0) और B(6, 0) के बीच की दूरी ज्ञात कीजिए।
Answer
चरण 1: दोनों बिंदु x-अक्ष पर स्थित हैं। चरण 2: x-अक्ष पर दूरी x-मानों को घटाकर ज्ञात की जाती है। चरण 3: AB = 6 - 4 = 2 इकाई। उत्तर: 2 इकाई…
Find the distance between C(0, 3) and D(0, 8).
Answer
Step 1: Both points lie on the y-axis. Step 2: Distance on the y-axis is found by subtracting y-values. Step 3: CD = 8 - 3 = 5 units. Answer: 5 units…
C(0, 3) और D(0, 8) के बीच की दूरी ज्ञात कीजिए।
Answer
चरण 1: दोनों बिंदु y-अक्ष पर स्थित हैं। चरण 2: y-अक्ष पर दूरी, y-मानों को घटाकर ज्ञात की जाती है। चरण 3: CD = 8 - 3 = 5 इकाई। उत्तर: 5 इकाई…
Apply the distance formula to P(4, 6) and Q(6, 8).
Answer
Step 1: Use PQ = √((x2 - x1)² + (y2 - y1)²). Step 2: PQ = √((6 - 4)² + (8 - 6)²) Step 3: PQ = √(2² + 2²) = √8 Step 4: PQ = 2√2 units Answer: 2√2 units…
पी(4, 6) और क्यू(6, 8) पर दूरी सूत्र लागू करें।
Answer
चरण 1: PQ = √((x2 - x1)² + (y2 - y1)²) का उपयोग करें। चरण 2: PQ = √((6 - 4)² + (8 - 6)²) चरण 3: PQ = √(2² + 2²) = √8 चरण 4: PQ = 2√2 इकाई उत्तर: 2√2 इकाई…
+40 more flashcards
Practise AllFrequently Asked Questions
What are the important topics in Coordinate Geometry for Madhya Pradesh Board Class 10 Mathematics?
How many flashcards are available for Coordinate Geometry?
How should I revise Coordinate Geometry for the Madhya Pradesh Board Class 10 board exam?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Coordinate Geometry
Practice Quiz
Test yourself with a quick quiz
Important Questions
Exam-style questions with answers
Revision Notes
Key points for last-minute revision
Formula Sheet
The chapter's formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect
Study Plan
Step-by-step plan for this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Coordinate Geometry chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for Madhya Pradesh Board Class 10 Mathematics. Free to start, no card needed.