Binary Logic — Flashcards
NIOS · Class 12 · Computer Science
24 flashcards for Binary Logic (NIOS Class 12 Computer Science) to test yourself on key terms and facts. Sample: "What is a binary number system and why.
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What is a binary number system and why do computers use it?
Answer
A binary number system uses only two digits: 0 and 1 (base 2). Computers use binary because: 1. Electronic components have two stable states (ON/OFF, HIGH/LOW) 2. These states map naturally to 0 and 1…
Convert the decimal number 25 to binary using successive division method
Answer
Using successive division by 2: 25 ÷ 2 = 12 remainder 1 (LSB) 12 ÷ 2 = 6 remainder 0 6 ÷ 2 = 3 remainder 0 3 ÷ 2 = 1 remainder 1 1 ÷ 2 = 0 remainder 1 (MSB) Reading remainders from bottom to top: (25…
What are octal and hexadecimal number systems and their bases?
Answer
Octal (Oct) Number System: - Base: 8 - Digits used: 0, 1, 2, 3, 4, 5, 6, 7 - Why used: More compact representation than binary - Example: (17)₈ = 1×8 + 7 = 15 in decimal Hexadecimal (Hex) Number Syst…
Convert decimal 47 to octal number
Answer
Using successive division by 8: 47 ÷ 8 = 5 remainder 7 (LSB) 5 ÷ 8 = 0 remainder 5 (MSB) Reading remainders from bottom to top: (47)₁₀ = (57)₈ Verification: 5×8 + 7×1 = 40 + 7 = 47 ✓ This method is…
Convert decimal 156 to hexadecimal
Answer
Using successive division by 16: 156 ÷ 16 = 9 remainder 12 (LSB, which is C in hex) 9 ÷ 16 = 0 remainder 9 (MSB) Reading remainders from bottom to top: (156)₁₀ = (9C)₁₆ Verification: 9×16 + 12×1 = 1…
How do you convert a binary number (1101)₂ to decimal?
Answer
Use the place value method by multiplying each digit by its corresponding power of 2: (1101)₂ = 1×2³ + 1×2² + 0×2¹ + 1×2⁰ = 1×8 + 1×4 + 0×2 + 1×1 = 8 + 4 + 0 + 1 = (13)₁₀ Steps …
Convert octal number (345)₈ to decimal
Answer
Use the place value method by multiplying each digit by its corresponding power of 8: (345)₈ = 3×8² + 4×8¹ + 5×8⁰ = 3×64 + 4×8 + 5×1 = 192 + 32 + 5 = (229)₁₀ Key points: - Start…
Convert hexadecimal number (2A7)₁₆ to decimal
Answer
Use the place value method by multiplying each digit by its corresponding power of 16: (2A7)₁₆ = 2×16² + A×16¹ + 7×16⁰ Remember: A = 10, so: = 2×256 + 10×16 + 7×1 = 512 + 160 + 7 …
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