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Chapter 7 of 8
Practice Quiz

Mensuration

Tamil Nadu Board · Class 10 · Mathematics

Practice quiz for Mensuration — Tamil Nadu Board Class 10 Mathematics. MCQs and questions with answers to test your preparation.

44 questions40 flashcards5 concepts

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Quick Quiz: Mensuration

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1

A cylinder has radius 7 cm and height 10 cm. What is its curved surface area?

2

The total surface area of a solid cone with radius 6 cm and slant height 10 cm is:

3

The volume of a sphere of radius 21 cm is:

4

A cone has height 8 cm and base radius 6 cm. What is its slant height?

44 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

The curved surface area of a hemisphere of radius 14 cm is:

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1232 cm²

Step 1: Given r = 14 cm. We need CSA of hemisphere. Step 2: CSA of hemisphere = 2πr² Step 3: CSA = 2 × (22/7) × 14 × 14 Step 4: CSA = 2 × (22/7) × 196 = 2 × 22 × 28 = 1232 cm² Common mistake: Using 4πr² (full sphere) instead of 2πr² for hemisphere CSA.

2multiple choice
1 marks

A metallic sphere of radius 6 cm is melted and recast into small spheres of radius 1 cm each. How many small spheres are formed?

Show answer

216

Step 1: Large sphere radius R = 6 cm, small sphere radius r = 1 cm. Step 2: Number of small spheres = Volume of large sphere / Volume of small sphere Step 3: n = [(4/3)πR³] / [(4/3)πr³] = R³/r³ Step 4: n = 6³/1³ = 216/1 = 216 Common mistake: Using ratios of radii directly (6/1 = 6) instead of cubing the ratio.

3multiple choice
1 marks

The volume of a frustum of a cone with height 12 cm and radii 8 cm and 4 cm is:

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1408 cm³

Step 1: Given h = 12 cm, R = 8 cm, r = 4 cm. Step 2: Volume of frustum = (πh/3)(R² + r² + Rr) Step 3: = (22/7 × 12/3)(64 + 16 + 32) Step 4: = (22/7 × 4)(112) = (22 × 448)/7 = 9856/7 = 1408 cm³ Common mistake: Using the cone volume formula instead of the frustum formula.

4multiple choice
1 marks

A cylinder and a cone have the same base radius and height. The ratio of the volume of the cylinder to the volume of the cone is:

Show answer

3:1

Step 1: Let radius = r and height = h for both solids. Step 2: Volume of cylinder = πr²h Step 3: Volume of cone = (1/3)πr²h Step 4: Ratio = πr²h : (1/3)πr²h = 1 : 1/3 = 3 : 1 This is a fundamental relationship: a cylinder holds exactly 3 times the volume of a cone with the same base and height.

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Frequently Asked Questions

What are the important topics in Mensuration for Tamil Nadu Board Class 10 Mathematics?
Key topics in Mensuration include Mensuration Concepts Hierarchy, Mensuration Chapter Overview, Mensuration – Complete Formula Overview. These are the concepts Tamil Nadu Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Mensuration — Tamil Nadu Board Class 10 Mathematics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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