Statistics and Probability
Tamil Nadu Board · Class 10 · Mathematics
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The number of televisions sold in a week are 13, 8, 4, 9, 7, 12, 10. What is the variance of this data?
The range of the data set 25, 67, 48, 53, 18, 39, 44 is 49. What is the coefficient of range?
The mean of a data is 25.6 and its coefficient of variation is 18.75. What is the standard deviation?
Two dice are rolled. What is the probability that the sum of the outcomes is equal to 4?
Sample Questions
If P(A) = 0.37, P(B) = 0.42, and P(A∩B) = 0.09, what is P(A∪B)?
Show answer
0.70
Step 1: Use the Addition Theorem: P(A∪B) = P(A) + P(B) - P(A∩B). Step 2: Substitute values: P(A∪B) = 0.37 + 0.42 - 0.09. Step 3: P(A∪B) = 0.79 - 0.09 = 0.70. Step 4: Common mistake is adding all three values (getting 0.88) instead of subtracting P(A∩B), or forgetting to subtract the intersection.
The standard deviation of data 7, 4, 8, 10, 11 is approximately 2.28. If each value is multiplied by 4, what is the new standard deviation?
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9.12
Step 1: Original σ ≈ 2.28 for data 4, 7, 8, 10, 11. Step 2: Key property: When all data values are multiplied by a constant k, the new standard deviation = k × original σ. Step 3: New σ = 4 × 2.28 = 9.12. Step 4: This is because multiplying each value by k scales the deviations from the mean by k, and hence σ scales by k. Common mistake: thinking σ stays the same (that's only for addition/subtraction of a constant).
In a class of 50 students, 28 opted for NCC, 30 opted for NSS, and 18 opted for both. What is the probability that a randomly selected student opted for NCC but NOT NSS?
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1/5
Step 1: n(S)=50, n(A)=28 (NCC), n(B)=30 (NSS), n(A∩B)=18. Step 2: P(A) = 28/50, P(A∩B) = 18/50. Step 3: P(NCC but not NSS) = P(A∩B̄) = P(A) - P(A∩B) = 28/50 - 18/50 = 10/50 = 1/5. Step 4: Common mistake is using 28 - 30 = incorrect subtraction, or forgetting to divide by n(S).
The variance of first n natural numbers is given by (n²-1)/12. For n=5, what is the standard deviation of the first 5 natural numbers?
Show answer
√2
Step 1: For n=5, variance σ² = (n²-1)/12 = (25-1)/12 = 24/12 = 2. Step 2: Standard deviation σ = √(variance) = √2. Step 3: Verify: Data = 1,2,3,4,5; mean = 3; Σ(xi-x̄)² = 4+1+0+1+4 = 10; σ² = 10/5 = 2; σ = √2 ✓. Step 4: Common mistake is computing variance as n²/12 without subtracting 1.
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