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Chapter 7 of 10
Practice Quiz

Atoms and Molecules

Tamil Nadu Board · Class 10 · Science

Practice quiz for Atoms and Molecules — Tamil Nadu Board Class 10 Science. MCQs and questions with answers to test your preparation.

44 questions36 flashcards5 concepts

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Quick Quiz: Atoms and Molecules

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1

What is the standard used to measure the Relative Atomic Mass of elements today?

2

What is the value of Avogadro's Number?

3

The number of atoms present in a molecule is called its:

4

Which of the following is a homodiatomic molecule?

44 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

What is the gram molecular mass of water (H₂O)? (Atomic masses: H = 1, O = 16)

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18 g

Step 1: To find the molecular mass of H₂O, we add the atomic masses of all atoms present in the molecule. Step 2: H₂O contains 2 hydrogen atoms and 1 oxygen atom. Step 3: Mass of 2 hydrogen atoms = 2 × 1 = 2 amu. Step 4: Mass of 1 oxygen atom = 1 × 16 = 16 amu. Step 5: Total molecular mass = 2 + 16 = 18 g. So the gram molecular mass of water is 18 g. Option A (16 g) counts only oxygen. Option B (17 g) adds only one hydrogen. Option D (20 g) is incorrect arithmetic.

2multiple choice
1 marks

According to Avogadro's Law, equal volumes of all gases under similar conditions of temperature and pressure contain:

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Equal number of molecules

Step 1: Avogadro's Law was proposed by Italian scientist Amedeo Avogadro in 1811. Step 2: The law states that equal volumes of all gases at the same temperature and pressure contain equal NUMBER OF MOLECULES. Step 3: For example, 1 litre of hydrogen and 1 litre of oxygen at the same temperature and pressure both contain the same number of molecules. Step 4: The masses of gases are NOT equal because different molecules have different masses. Step 5: This is why gases with different densities can still contain the same number of molecules in equal volumes. Option A is wrong because molecules hav

3multiple choice
1 marks

What is the relationship between Relative Molecular Mass and Vapour Density?

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Molecular Mass = 2 × Vapour Density

Step 1: Vapour Density (V.D.) is the ratio of the mass of a given volume of a gas to the mass of an equal volume of hydrogen at the same conditions. Step 2: According to Avogadro's law, equal volumes contain equal number of molecules. Step 3: So V.D. = mass of 1 molecule of gas / mass of 2 atoms of hydrogen (because hydrogen is diatomic, H₂). Step 4: Relative Molecular Mass = mass of 1 molecule / mass of 1 atom of hydrogen. Step 5: Comparing both formulas: Molecular Mass = 2 × Vapour Density. For example, if V.D. of CO₂ is 22, then molecular mass = 44. This is a key formula to remember.

4multiple choice
1 marks

How many moles are present in 46 g of sodium? (Atomic mass of Na = 23)

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2 moles

Step 1: The formula to calculate the number of moles from mass is: Number of moles = Mass / Atomic Mass. Step 2: Here, Mass of sodium = 46 g and Atomic mass of sodium (Na) = 23. Step 3: Number of moles = 46 / 23 = 2 moles. Step 4: This means 46 g of sodium contains 2 × 6.023 × 10²³ atoms of sodium. Step 5: Option A (1 mole) would be correct for 23 g of Na. Option C (0.5 mole) would be correct for 11.5 g of Na. Always divide the given mass by the atomic mass to find moles.

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What are the important topics in Atoms and Molecules for Tamil Nadu Board Class 10 Science?
Key topics in Atoms and Molecules include Atoms and Molecules – Complete Chapter Overview, Mind map showing all major applications of Avogadro's law in chemistry, Summary of key formulas organized by category: atomic, molecular, and mole formulas. These are the concepts Tamil Nadu Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Atoms and Molecules — Tamil Nadu Board Class 10 Science?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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