Nuclear Physics
Tamil Nadu Board · Class 10 · Science
Practice quiz for Nuclear Physics — Tamil Nadu Board Class 10 Science. MCQs and questions with answers to test your preparation.
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Quick Quiz: Nuclear Physics
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Henri Becquerel discovered radioactivity in 1896. Which material did he use that first showed the property of radioactivity?
Which of the following correctly describes the SI unit of radioactivity — Becquerel (Bq)?
Which type of radioactive radiation has the HIGHEST ionising power?
Which type of radioactive radiation has the HIGHEST penetrating power?
Sample Questions
According to Soddy and Fajan's displacement law, when a radioactive nucleus undergoes alpha decay, the daughter nucleus will have:
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Mass number decreased by 4, atomic number decreased by 2
Step 1: An alpha particle is a helium nucleus represented as ₂He⁴. It has mass number 4 and atomic number 2. Step 2: When a parent nucleus emits an alpha particle, it loses 4 units of mass number (2 protons + 2 neutrons). Step 3: It also loses 2 units of atomic number (2 protons). Step 4: Example: ₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴. Here, U has mass 238 → Th has mass 234 (decreased by 4), and atomic number 92 → 90 (decreased by 2). Step 5: For beta decay: mass number stays same, atomic number increases by 1. For gamma decay: both mass and atomic number remain unchanged.
In beta decay, a phosphorous nucleus ₁₅P³² undergoes beta decay. What is the atomic number of the daughter nucleus formed?
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16
Step 1: In beta decay, a beta particle (electron, ₋₁e⁰) is emitted. Step 2: According to Soddy and Fajan's displacement law for beta decay: mass number remains the same, but atomic number increases by 1. Step 3: Parent nucleus: ₁₅P³² — Atomic number = 15, Mass number = 32. Step 4: After beta decay: Atomic number = 15 + 1 = 16, Mass number = 32 (unchanged). Step 5: The daughter nucleus is ₁₆S³² (Sulphur-32). The element is identified by its atomic number, not mass number. So the correct answer is 16.
Nuclear fission of Uranium-235 is represented as: ₉₂U²³⁵ + ₀n¹ → ₅₆Ba¹⁴¹ + ₃₆Kr⁹² + X neutrons + Energy. How many neutrons (X) are released in this fission reaction?
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3
Step 1: In nuclear fission, mass number and atomic number must be conserved (balanced) on both sides. Step 2: Left side mass numbers: 235 (U) + 1 (neutron) = 236. Step 3: Right side mass numbers: 141 (Ba) + 92 (Kr) + X(1) = 233 + X. Step 4: Balancing: 236 = 233 + X → X = 3. Step 5: This means 3 neutrons are released in each fission event. This is what makes a chain reaction possible — each fission releases neutrons that can trigger further fissions. The average energy released per fission is about 3.2 × 10⁻¹¹ J.
What is the key difference between a controlled chain reaction and an uncontrolled chain reaction?
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In controlled reaction, only one neutron is maintained to cause further fission; in uncontrolled, neutrons multiply indefinitely
Step 1: In a chain reaction, neutrons released by fission trigger further fissions, which release more neutrons. Step 2: In a controlled chain reaction, extra neutrons are absorbed by control rods (made of boron or cadmium), leaving only ONE neutron to trigger the next fission. This keeps the reaction sustained but steady. Step 3: Controlled chain reactions are used in nuclear reactors to generate electricity safely. Step 4: In an uncontrolled chain reaction, all neutrons are free to cause further fissions — the number multiplies geometrically (1 → 3 → 9 → 27...). Step 5: This results in a hug
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