Solutions — Practice Quiz
Tamil Nadu Board · Class 10 · Science
Try a 4-question quiz on Solutions for Tamil Nadu Board Class 10 Science: tap an answer to check it and see why. 43 questions in the full chapter test.
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Quick Quiz: Solutions
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Which of the following is the correct definition of solubility?
A student dissolves 36 g of NaCl in 100 g of water at 25°C. No more NaCl dissolves after this. What type of solution has been formed?
What is the mass percentage of sugar in a solution prepared by dissolving 25 g of sugar in 100 g of water?
Which of the following is an example of a gaseous solution?
Sample Questions
The principle 'like dissolves like' in chemistry means which of the following?
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Polar solvents dissolve polar solutes and non-polar solvents dissolve non-polar solutes
Step 1: The phrase 'like dissolves like' refers to the polarity of substances. Step 2: Polar compounds (like common salt, NaCl) are soluble in polar solvents (like water). Step 3: Non-polar compounds (like fat, sulphur) are soluble in non-polar solvents (like ether, carbon disulphide). Step 4: This is why sulphur dissolves in CS₂ but not in water — sulphur is non-polar and water is polar. Step 5: Options C and D describe irrelevant physical properties (size, weight) that do not determine solubility.
When blue copper sulphate crystals (CuSO₄·5H₂O) are gently heated, what happens?
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They lose water of crystallization and turn colourless
Step 1: Copper sulphate pentahydrate (CuSO₄·5H₂O) is a hydrated salt — it has 5 molecules of water of crystallization. Step 2: When gently heated, the salt loses these 5 water molecules: CuSO₄·5H₂O → CuSO₄ + 5H₂O. Step 3: The blue colour of CuSO₄ crystals is due to the presence of water of crystallization. Step 4: After losing water, the resulting anhydrous CuSO₄ becomes colourless/white and amorphous. Step 5: This reaction is reversible — adding a few drops of water to anhydrous CuSO₄ makes it turn blue again, which is used as a test for moisture.
What is the solubility of a solute if 1.5 g of it dissolves in 15 g of water to form a saturated solution at 298 K?
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10 g per 100 g water
Step 1: Formula: Solubility = (Mass of solute / Mass of solvent) × 100. Step 2: Mass of solute = 1.5 g; Mass of solvent = 15 g. Step 3: Solubility = (1.5 / 15) × 100 = 10 g per 100 g of water. Step 4: This means 10 g of this solute can dissolve in 100 g of water to form a saturated solution at 298 K. Step 5: Option C (15 g) is a common error where students confuse the mass of solvent directly with solubility without scaling to 100 g.
Which of the following substances is an example of a deliquescent substance?
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Caustic soda (NaOH)
Step 1: Deliquescent substances absorb so much moisture from the air that they completely dissolve in the absorbed water. Step 2: Caustic soda (NaOH) is a classic deliquescent substance — it absorbs water from humid air and eventually forms a liquid solution. Step 3: Silica gel, Quick lime (CaO), and Phosphorus pentoxide (P₂O₅) are hygroscopic substances — they absorb moisture but do not dissolve. Step 4: The key difference is that deliquescent substances change their physical state (solid → liquid), while hygroscopic substances do not. Step 5: Deliquescence is maximum at low temperatures and
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