Wave Optics
Tamil Nadu Board · Class 12 · Physics
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Quick Quiz: Wave Optics
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In Young's double slit experiment, the two slits are separated by 0.3 mm and the screen is placed 1.5 m away. If the wavelength of light used is 600 nm, what is the fringe width (bandwidth)?
Two light sources have amplitudes in the ratio 3:1. What is the ratio of maximum intensity to minimum intensity when they interfere?
Which of the following is the correct condition for constructive interference in the reflected light from a thin film of refractive index μ and thickness d?
A diffraction grating has 5000 lines per centimetre. What is the angle at which the first order diffraction maximum occurs for light of wavelength 500 nm?
Sample Questions
According to Malus' Law, plane polarised light of intensity I₀ passes through an analyser whose transmission axis makes an angle of 60° with the polariser. What is the intensity of the emergent light?
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I₀/4
Step 1: Malus' Law states I = I₀ cos²θ. Step 2: θ = 60°, so cos 60° = 1/2. Step 3: I = I₀ × (1/2)² = I₀ × 1/4 = I₀/4. Option B (I₀/2) is incorrect — students often apply cos θ instead of cos²θ. Option C (3I₀/4) would correspond to θ = 30°. Option D involves the wrong trigonometric function. The law specifically uses the square of cosine.
In a single slit diffraction experiment, the slit width is 0.5 mm and the screen is 1 m away. If the wavelength of light is 500 nm, the width of the central maximum on the screen is:
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2 mm
Step 1: The central maximum extends from the first minimum on one side to the first minimum on the other side. Step 2: Position of first minimum: y₁ = λD/a = (500 × 10⁻⁹ × 1) / (0.5 × 10⁻³) = 1 × 10⁻³ m = 1 mm. Step 3: Width of central maximum = 2y₁ = 2 × 1 mm = 2 mm. Step 4: The factor of 2 is because the central maximum spreads on BOTH sides. Option B (1 mm) is just y₁ — a common mistake of forgetting both sides. Option A is less than y₁. Option D doubles incorrectly.
Brewster's law states that when light is incident at the polarising angle iₚ on a surface with refractive index n, which of the following relations is correct?
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tan iₚ = n
Step 1: At the polarising angle iₚ, the reflected and refracted rays are perpendicular to each other. Step 2: This means rₚ = 90° − iₚ. Step 3: Applying Snell's law: sin iₚ / sin rₚ = n → sin iₚ / sin(90° − iₚ) = n. Step 4: Since sin(90° − iₚ) = cos iₚ, we get sin iₚ / cos iₚ = tan iₚ = n. This is Brewster's Law. Options A, B, D use wrong trigonometric ratios. Note that for glass (n = 1.5), iₚ = tan⁻¹(1.5) ≈ 56.3°.
The wavelength of light from a sodium source in vacuum is 5893 Å. When this light travels in water (refractive index 1.33), its wavelength in water is approximately:
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4431 Å
Step 1: Use the relation λ₁/λ₂ = n₂/n₁. Step 2: λ₁ = 5893 Å (in vacuum, n₁ = 1), n₂ = 1.33. Step 3: λ₂ = λ₁ × (n₁/n₂) = 5893 × (1/1.33). Step 4: λ₂ = 5893 / 1.33 ≈ 4431 Å. The wavelength decreases in a denser medium because light slows down. Option A (5893 Å) — frequency stays the same but wavelength changes. Option B (7837 Å) is wrong — wavelength increases (incorrect direction). Option D is too small. Note: frequency remains unchanged in all media.
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