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Chapter 5 of 9
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Coordinate Geometry

Tamil Nadu Board · Class 9 · Mathematics

Flashcards for Coordinate Geometry — Tamil Nadu Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions25 flashcards5 concepts

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A labeled diagram showing the x-axis, y-axis, origin, and a point (x, y) in the first quadrant, illustrating the basic setup of a Cartesian coordinate system.
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25 Flashcards
Card 1Cartesian Coordinate System

Identify the quadrant: Point (3, -8)

Answer

Step 1: Check the sign of x-coordinate: x = 3 (positive) Step 2: Check the sign of y-coordinate: y = -8 (negative) Step 3: Since x > 0 and y < 0, the point lies in Quadrant IV Answer: Quadrant IV Rem

Card 2Plotting Points

Plot the point (-3, 5) on a Cartesian plane. Which quadrant does it lie in?

Answer

Step 1: Start at origin O(0,0) Step 2: Move 3 units to the left (negative x-direction) Step 3: Move 5 units upward (positive y-direction) Step 4: Mark the intersection point at (-3, 5) Step 5: Check s

Card 3Distance Formula

Find the distance between points A(1, 2) and B(4, 3)

Answer

Using Distance Formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²] Step 1: Identify coordinates: (x₁,y₁) = (1,2), (x₂,y₂) = (4,3) Step 2: Apply formula: d = √[(4-1)² + (3-2)²] Step 3: Calculate: d = √[3² + 1²] S

Card 4Distance Formula

Calculate the distance between (-4, 3) and (2, -3)

Answer

Using Distance Formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²] Step 1: Identify: (x₁,y₁) = (-4,3), (x₂,y₂) = (2,-3) Step 2: Substitute: d = √[(2-(-4))² + (-3-3)²] Step 3: Simplify inside brackets: d = √[(2+4

Card 5Distance Formula

When do you use the distance formula? Give an example of a real-world situation

Answer

Use the distance formula when you need to: 1. Find the straight-line distance between two points 2. Check if points form geometric shapes (triangle, square, etc.) 3. Determine if three points are coll

Card 6Collinearity and Distance Formula

Are the points A(3, 1), B(6, 4), and C(8, 6) collinear?

Answer

Method: Three points are collinear if AB + BC = AC Step 1: Calculate AB = √[(6-3)² + (4-1)²] AB = √[9 + 9] = √18 = 3√2 Step 2: Calculate BC = √[(8-6)² + (6-4)²] BC = √[4 + 4] = √8 = 2√

Card 7Midpoint Formula

Find the midpoint of the line segment joining A(-8, -10) and B(4, -2)

Answer

Using Midpoint Formula: M = ((x₁+x₂)/2, (y₁+y₂)/2) Step 1: Identify coordinates: (x₁,y₁) = (-8,-10), (x₂,y₂) = (4,-2) Step 2: Calculate x-coordinate of midpoint: x = (-8 + 4)/2 = -4/2 = -2 Ste

Card 8Midpoint Formula Applications

The center of a circle is (3, -4). If one end of the diameter is (5, -6), find the other end

Answer

Key concept: Center is the midpoint of diameter Using: Center = ((x₁+x₂)/2, (y₁+y₂)/2) Step 1: Let other end be B(x₂, y₂). Given: Center (3, -4), A(5, -6) Step 2: For x-coordinate: 3 = (5 + x₂)/2

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Frequently Asked Questions

What are the important topics in Coordinate Geometry for Tamil Nadu Board Class 9 Mathematics?
Key topics in Coordinate Geometry include Coordinate Geometry – Chapter Overview Mind Map, Coordinate Geometry – Complete Chapter Overview, Coordinate Geometry - Concept Overview. These are the concepts Tamil Nadu Board Class 9 examiners draw on most — study them first, then practise related questions.
How to score full marks in Coordinate Geometry — Tamil Nadu Board Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Coordinate Geometry?
There are 25 flashcards for Coordinate Geometry covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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