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Chapter 7 of 9
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Mensuration

Tamil Nadu Board · Class 9 · Mathematics

Flashcards for Mensuration — Tamil Nadu Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions25 flashcards5 concepts

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Card 1Heron's Formula

Find the area of a triangle with sides 13 cm, 14 cm, and 15 cm using Heron's formula.

Answer

Step 1: Calculate semi-perimeter s = (a+b+c)/2 = (13+14+15)/2 = 42/2 = 21 cm Step 2: Apply Heron's formula: Area = √[s(s-a)(s-b)(s-c)] Step 3: Area = √[21(21-13)(21-14)(21-15)] Step 4: Area = √[21 × 8

Card 2Heron's Formula

Formula for area of a triangle using Heron's formula

Answer

Formula: Area = √[s(s-a)(s-b)(s-c)] sq. units Where: s = (a+b+c)/2 (semi-perimeter) a, b, c = the three sides of the triangle Example: Triangle with sides 10 cm, 24 cm, 26 cm s = (10+24+26)/2 = 30 cm

Card 3Heron's Formula - Application

A triangular field has sides 28 m, 15 m, and 41 m. Find the area and cost of levelling at ₹20 per m².

Answer

Step 1: Calculate s = (28+15+41)/2 = 84/2 = 42 m Step 2: Apply Heron's formula Area = √[42(42-28)(42-15)(42-41)] Area = √[42 × 14 × 27 × 1] Area = √[15876] = √[2×3×7 × 7×2 × 3³] = 2×3×7×3 = 126 m² Ste

Card 4Heron's Formula - Comparison

Three triangular plots have the same perimeter of 120 m with sides: (i) 30, 40, 50 m (ii) 35, 40, 45 m (iii) 40, 40, 40 m. Which plot is most spacious?

Answer

Plot (i) - Right angled triangle: s = 60 m Area = √[60×30×20×10] = √[360000] = 600 m² Plot (ii) - Acute angled triangle: s = 60 m Area = √[60×25×20×15] = √[450000] = 300√5 ≈ 670.8 m² Plot (iii) - Eq

Card 5Heron's Formula - Quadrilaterals

Find the area of a quadrilateral ABCD with sides AB=13 cm, BC=12 cm, CD=9 cm, AD=14 cm and diagonal BD=15 cm.

Answer

Method: Divide into two triangles using diagonal BD Triangle ABD: sides 13 cm, 14 cm, 15 cm s = (13+14+15)/2 = 21 cm Area = √[21×8×7×6] = √[7056] = 84 cm² Triangle BCD: sides 12 cm, 9 cm, 15 cm s =

Card 6Heron's Formula - Special Quadrilaterals

A rhombus has perimeter 400 m and one diagonal 120 m. Find its area using Heron's formula.

Answer

Step 1: Find each side of rhombus Perimeter = 4 × side = 400 m Side = 100 m Step 2: In triangle ABC formed by two sides and diagonal Sides of triangle: a=100 m, b=100 m, c=120 m (diagonal) s = (100+1

Card 7Surface Area - Cuboid

Find the Total Surface Area (TSA) of a cuboid with length 7.5 m, breadth 3 m, and height 5 m.

Answer

Formula: TSA = 2(lb + bh + lh) sq. units Given: l = 7.5 m, b = 3 m, h = 5 m Step 1: Calculate each product lb = 7.5 × 3 = 22.5 m² bh = 3 × 5 = 15 m² lh = 7.5 × 5 = 37.5 m² Step 2: Sum the products

Card 8Surface Area - Cuboid

Find the Lateral Surface Area (LSA) of a cuboid with length 7.5 m, breadth 3 m, and height 5 m.

Answer

Formula: LSA = 2(l + b)h sq. units (LSA excludes top and bottom faces) Given: l = 7.5 m, b = 3 m, h = 5 m Step 1: Add length and breadth l + b = 7.5 + 3 = 10.5 m Step 2: Multiply by 2 and height LS

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Frequently Asked Questions

What are the important topics in Mensuration for Tamil Nadu Board Class 9 Mathematics?
Key topics in Mensuration include Pie chart showing distribution of mensuration applications across different industries, Flowchart showing verification steps to avoid common mistakes, Comprehensive mind map summarizing all key formulas from the chapter. These are the concepts Tamil Nadu Board Class 9 examiners draw on most — study them first, then practise related questions.
How to score full marks in Mensuration — Tamil Nadu Board Class 9 Mathematics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Mensuration?
There are 25 flashcards for Mensuration covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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