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Chapter 6 of 9
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Trigonometry

Tamil Nadu Board · Class 9 · Mathematics

Flashcards for Trigonometry — Tamil Nadu Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions30 flashcards5 concepts

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A labeled diagram of a right-angled triangle showing the perpendicular, base, and hypotenuse relative to an acute angle, and defining the six trigonometric ratios (sine, cosine, tangent, cosecant, sec
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30 Flashcards
Card 1Basic Trigonometric Ratios

In a right-angled triangle ABC with right angle at B, if angle C = θ, AC = 13 cm (hypotenuse), and BC = 5 cm (adjacent to θ). Find sin θ.

Answer

Step 1: Identify the sides relative to angle θ. AC = hypotenuse = 13 cm, BC = adjacent = 5 cm. Step 2: Find the opposite side using Pythagoras theorem: AB² + BC² = AC² → AB² + 5² = 13² → AB² + 25 = 16

Card 2All Six Trigonometric Ratios

Find all six trigonometric ratios for angle θ if tan θ = 3/4.

Answer

Step 1: From tan θ = 3/4, we know opposite/adjacent = 3/4. Let opposite = 3k and adjacent = 4k. Step 2: Find hypotenuse using Pythagoras: hypotenuse = √(3k)² + (4k)² = √(9k² + 16k²) = √(25k²) = 5k. St

Card 3Formula Application

When do you use sin θ = opposite/hypotenuse? Give a practical example.

Answer

Use sin θ when you know (or need to find) the angle and the opposite side relative to that angle in a right-angled triangle, and you're given the hypotenuse or need to find it. EXAMPLE: A ladder of le

Card 4Key Formulas

Formula for: sin θ

Answer

sin θ = opposite side / hypotenuse Where: • opposite side = the side opposite to angle θ in a right-angled triangle • hypotenuse = the longest side of the right-angled triangle (opposite the right an

Card 5Basic Trigonometric Ratios

In a right triangle, if sin A = 7/25, find cos A and tan A.

Answer

Step 1: From sin A = 7/25, we know opposite/hypotenuse = 7/25. Let opposite = 7k and hypotenuse = 25k. Step 2: Find adjacent using Pythagoras: adjacent² + opposite² = hypotenuse² → adjacent² + (7k)² =

Card 6Standard Angles Evaluation

Evaluate: sin 30° + cos 60° - tan 45°

Answer

Step 1: Recall standard angle values: • sin 30° = 1/2 • cos 60° = 1/2 • tan 45° = 1 Step 2: Substitute values into expression: sin 30° + cos 60° - tan 45° = 1/2 + 1/2 - 1 Step 3: Calculate: = 1/2 +

Card 7Standard Angles and Identities

Find the value of: sin² 45° + cos² 45°

Answer

Step 1: Recall standard angle value: sin 45° = cos 45° = 1/√2 Step 2: Calculate sin² 45°: sin² 45° = (1/√2)² = 1/2 Step 3: Calculate cos² 45°: cos² 45° = (1/√2)² = 1/2 Step 4: Add them: sin² 45° +

Card 8Complementary Angles

When do you use complementary angle relationships? Give an example with calculation.

Answer

Use complementary angle relationships when you know one angle and need to find trigonometric ratios of its complement (two angles that sum to 90°). Key relationships: sin θ = cos(90° - θ), cos θ = sin

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Frequently Asked Questions

What are the important topics in Trigonometry for Tamil Nadu Board Class 9 Mathematics?
Key topics in Trigonometry include Trigonometry - Complete Chapter Overview, Trigonometry Concepts Overview, Flowchart showing the three types of sides in a right-angled triangle and how they relate to the chosen angle. These are the concepts Tamil Nadu Board Class 9 examiners draw on most — study them first, then practise related questions.
How to score full marks in Trigonometry — Tamil Nadu Board Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Trigonometry?
There are 30 flashcards for Trigonometry covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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