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Chapter 2 of 10
Practice Quiz

Motion — Practice Quiz

Tamil Nadu Board · Class 9 · Science

Try a 4-question quiz on Motion for Tamil Nadu Board Class 9 Science: tap an answer to check it and see why. 44 questions in the full chapter test.

44 questions29 flashcards5 concepts

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A line graph showing distance on the Y-axis and time on the X-axis, depicting a straight line passing through the origin, representing uniform speed. Includes labels for calculating speed from the slo
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Quick Quiz: Motion

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1

A car starts from rest and accelerates uniformly at 4 ms⁻² for 5 seconds, then moves with uniform velocity for 10 seconds, and finally decelerates uniformly to rest in 4 seconds. What is the total distance covered by the car?

2

A velocity-time graph for a uniformly accelerated body is a straight line. The area of the trapezium formed under this graph between t=0 and t=T represents which physical quantity?

3

An object is thrown vertically upward with an initial velocity of 20 ms⁻¹. Taking g = 10 ms⁻², what is the displacement of the object after 3 seconds from the point of projection?

4

A stone tied to a string is whirled in a horizontal circle. If the speed of the stone is doubled while the radius of the circle remains the same, how does the centripetal force change?

44 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

Which of the following correctly distinguishes between distance and displacement?

Show answer

Distance can never be zero if the body has moved; displacement can be zero even if the body has moved

Step 1: Distance is the total path length traveled, regardless of direction. It is a scalar quantity and always positive or zero. Step 2: Displacement is the shortest straight-line distance from the initial to the final position, and it is a vector quantity. Step 3: If a person walks in a circle and returns to the starting point, the distance traveled equals the circumference of the circle (non-zero), but displacement = 0 because initial and final positions are the same. Step 4: Distance can never decrease or be zero (unless no movement), while displacement CAN be zero after movement. Step 5:

2multiple choice
1 marks

From a velocity-time graph of a uniformly accelerated body, the acceleration can be calculated as:

Show answer

Slope of the velocity-time graph

Step 1: Acceleration is defined as the rate of change of velocity, i.e., a = Δv/Δt = (v-u)/t. Step 2: On a velocity-time graph, the Y-axis is velocity and the X-axis is time. The slope of any graph = change in Y / change in X. Step 3: Therefore, slope of v-t graph = Δv/Δt = acceleration. For uniform acceleration, this slope is constant and gives a straight line. Step 4: The area under the v-t graph gives displacement (not acceleration). Step 5: The slope of the distance-time graph gives speed. The ratio of total displacement to total time gives average velocity. These are commonly confused qua

3multiple choice
1 marks

A car accelerates from rest. In the first second it travels 10 m. Assuming uniform acceleration, what distance will it cover in the third second alone (not cumulative)?

Show answer

50 m

Step 1: The car starts from rest (u=0). In the first second, s = ½at² → 10 = ½×a×1² → a = 20 ms⁻². Step 2: Distance covered in 3 seconds total: s₃ = ½×20×9 = 90 m. Step 3: Distance covered in 2 seconds total: s₂ = ½×20×4 = 40 m. Step 4: Distance covered in the 3rd second ALONE = s₃ - s₂ = 90 - 40 = 50 m. Step 5: A key concept is that for uniform acceleration from rest, distances covered in successive seconds are in the ratio 1:3:5:7... (odd numbers). First second = 10 m, second second = 30 m, third second = 50 m – confirming our answer. Wrong options arise from confusing cumulative distance wi

4multiple choice
1 marks

An object moves in a circular path of radius 7 m with a uniform speed and completes one revolution in 11 seconds. What is the speed of the object? (Use π = 22/7)

Show answer

4 ms⁻¹

Step 1: For uniform circular motion, speed v = 2πr/T, where r is the radius and T is the time period for one revolution. Step 2: Given: r = 7 m, T = 11 s, π = 22/7. Step 3: v = 2 × (22/7) × 7 / 11 = 2 × 22 / 11 = 44/11 = 4 ms⁻¹. Step 4: Note that even though the speed is constant (uniform circular motion), the velocity direction keeps changing at every point, so this is still an accelerated motion. Step 5: Common mistake – students forget to multiply by 2 in 2πr (full circumference = 2πr, NOT πr). πr is only half the circumference. Option 2 ms⁻¹ results from using πr instead of 2πr.

+40 more questions on Motion (Tamil Nadu Board Class 9 Science)

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Frequently Asked Questions

What are the important topics in Motion for Tamil Nadu Board Class 9 Science?
Key topics in Motion include Rest and Motion - Fundamental Concepts, Uniform and Non-Uniform Motion, Distance and Displacement, Speed and Velocity. Study these first, then practise questions on each for Class 9 exams.
How many practice questions are there for Motion?
There are 44 questions on Motion. Try the 4-question sample quiz on this page first; each answer shows an explanation when you tap it.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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