Complex Numbers and Quadratic Equations
CBSE · Class 11 · Mathematics
Flashcards for Complex Numbers and Quadratic Equations — CBSE Class 11 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Complex Numbers and Quadratic Equations? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 11 students started this chapter today
Solve: x^2 + 1 = 0
Answer
Step 1: Rearrange to x^2 = -1. Step 2: No real number has a negative square. Step 3: Introduce i such that i^2 = -1. Answer: The equation has no real solution; its complex solutions are i and -i.
हल करें: x^2 + 1 = 0
Answer
चरण 1: x^2 = -1 के रूप में पुनर्व्यवस्थित करें। चरण 2: किसी भी वास्तविक संख्या का वर्ग ऋणात्मक नहीं होता है। चरण 3: i को इस प्रकार प्रस्तुत करें कि i^2 = -1 हो। उत्तर: समीकरण का कोई वास्तविक हल नहीं ह…
Solve: 4x + i(3x - y) = 3 + i(-6)
Answer
Step 1: Compare real parts: 4x = 3. Step 2: So x = 3/4. Step 3: Compare imaginary parts: 3x - y = -6. Step 4: Substitute x = 3/4: 9/4 - y = -6. Step 5: So -y = -33/4, hence y = 33/4. Answer: x = 3/4, …
हल करें: 4x + i(3x - y) = 3 + i(-6)
Answer
चरण 1: वास्तविक भागों की तुलना करें: 4x = 3. चरण 2: तो x = 3/4. चरण 3: काल्पनिक भागों की तुलना करें: 3x - y = -6. चरण 4: x = 3/4: 9/4 - y = -6. प्रतिस्थापित करें चरण 5: तो -y = -33/4, इसलिए y = 33/4.
Find the sum: (2 + 3i) + (-6 + 5i)
Answer
Step 1: Add real parts: 2 + (-6) = -4. Step 2: Add imaginary parts: 3i + 5i = 8i. Step 3: Combine the results. Answer: -4 + 8i.
योग ज्ञात कीजिए: (2 + 3i) + (-6 + 5i)
Answer
चरण 1: वास्तविक भाग जोड़ें: 2 + (-6) = -4. चरण 2: काल्पनिक भाग जोड़ें: 3i + 5i = 8i. चरण 3: परिणामों को मिलाएं। उत्तर: -4 + 8i.
Find the difference: (6 + 3i) - (2 - i)
Answer
Step 1: Change subtraction into addition of the negative. Step 2: (6 + 3i) - (2 - i) = (6 + 3i) + (-2 + i). Step 3: Add real parts: 6 + (-2) = 4. Step 4: Add imaginary parts: 3i + i = 4i. Answer: 4 + …
अंतर ज्ञात कीजिए: (6 + 3i) - (2 - i)
Answer
चरण 1: घटाव को ऋणात्मक के जोड़ में बदलें। चरण 2: (6 + 3i) - (2 - i) = (6 + 3i) + (-2 + i). चरण 3: वास्तविक भाग जोड़ें: 6 + (-2) = 4. चरण 4: काल्पनिक भाग जोड़ें: 3i + i = 4i. उत्तर: 4 + 4i.
+46 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Complex Numbers and Quadratic Equations for CBSE Class 11 Mathematics?
How to score full marks in Complex Numbers and Quadratic Equations — CBSE Class 11 Mathematics?
How many flashcards are available for Complex Numbers and Quadratic Equations?
Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Complex Numbers and Quadratic Equations
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Complex Numbers and Quadratic Equations chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for CBSE Class 11 Mathematics.