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Complex Numbers and Quadratic Equations — Flashcards

CBSE · Class 11 · Mathematics

54 flashcards for Complex Numbers and Quadratic Equations (CBSE Class 11 Mathematics) to test yourself on key terms and facts. Sample: "Solve: x^2 + 1 = 0"

168 questions54 flashcards20 formulas & key relations5 concepts

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54 Flashcards·
Introduction to complex numbersसम्मिश्र संख्याओं का परिचयEquality of complex numbersसम्मिश्र संख्याओं की समानताAddition of complex numbersजटिल संख्याओं का योगDifference of complex numbersसम्मिश्र संख्याओं का अंतर
Card 1Introduction to complex numbers

Solve: x^2 + 1 = 0

Answer

Step 1: Rearrange to x^2 = -1. Step 2: No real number has a negative square. Step 3: Introduce i such that i^2 = -1. Answer: The equation has no real solution; its complex solutions are i and -i.

Card 2सम्मिश्र संख्याओं का परिचय

हल करें: x^2 + 1 = 0

Answer

चरण 1: x^2 = -1 के रूप में पुनर्व्यवस्थित करें। चरण 2: किसी भी वास्तविक संख्या का वर्ग ऋणात्मक नहीं होता है। चरण 3: i को इस प्रकार प्रस्तुत करें कि i^2 = -1 हो। उत्तर: समीकरण का कोई वास्तविक हल नहीं ह…

Card 3Equality of complex numbers

Solve: 4x + i(3x - y) = 3 + i(-6)

Answer

Step 1: Compare real parts: 4x = 3. Step 2: So x = 3/4. Step 3: Compare imaginary parts: 3x - y = -6. Step 4: Substitute x = 3/4: 9/4 - y = -6. Step 5: So -y = -33/4, hence y = 33/4. Answer: x = 3/4, …

Card 4सम्मिश्र संख्याओं की समानता

हल करें: 4x + i(3x - y) = 3 + i(-6)

Answer

चरण 1: वास्तविक भागों की तुलना करें: 4x = 3. चरण 2: तो x = 3/4. चरण 3: काल्पनिक भागों की तुलना करें: 3x - y = -6. चरण 4: x = 3/4: 9/4 - y = -6. प्रतिस्थापित करें चरण 5: तो -y = -33/4, इसलिए y = 33/4.

Card 5Addition of complex numbers

Find the sum: (2 + 3i) + (-6 + 5i)

Answer

Step 1: Add real parts: 2 + (-6) = -4. Step 2: Add imaginary parts: 3i + 5i = 8i. Step 3: Combine the results. Answer: -4 + 8i.

Card 6जटिल संख्याओं का योग

योग ज्ञात कीजिए: (2 + 3i) + (-6 + 5i)

Answer

चरण 1: वास्तविक भाग जोड़ें: 2 + (-6) = -4. चरण 2: काल्पनिक भाग जोड़ें: 3i + 5i = 8i. चरण 3: परिणामों को मिलाएं। उत्तर: -4 + 8i.

Card 7Difference of complex numbers

Find the difference: (6 + 3i) - (2 - i)

Answer

Step 1: Change subtraction into addition of the negative. Step 2: (6 + 3i) - (2 - i) = (6 + 3i) + (-2 + i). Step 3: Add real parts: 6 + (-2) = 4. Step 4: Add imaginary parts: 3i + i = 4i. Answer: 4 + …

Card 8सम्मिश्र संख्याओं का अंतर

अंतर ज्ञात कीजिए: (6 + 3i) - (2 - i)

Answer

चरण 1: घटाव को ऋणात्मक के जोड़ में बदलें। चरण 2: (6 + 3i) - (2 - i) = (6 + 3i) + (-2 + i). चरण 3: वास्तविक भाग जोड़ें: 6 + (-2) = 4. चरण 4: काल्पनिक भाग जोड़ें: 3i + i = 4i. उत्तर: 4 + 4i.

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Frequently Asked Questions

What are the important topics in Complex Numbers and Quadratic Equations for CBSE Class 11 Mathematics?
Key topics in Complex Numbers and Quadratic Equations include Need for Complex Numbers, Complex Numbers and Their Parts, Algebra of Complex Numbers, Powers of i and Square Roots of Negative Numbers. Study these first, then practise questions on each for Class 11 exams.
How many flashcards are available for Complex Numbers and Quadratic Equations?
There are 54 flashcards for Complex Numbers and Quadratic Equations covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Complex Numbers and Quadratic Equations for Class 11 exams?
Learn the core ideas first, then work through the 168 practice questions on Complex Numbers and Quadratic Equations. Revise definitions regularly and use flashcards for quick recall before the exam.

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