CBSE Class 11 Mathematics — Flashcards

A: Step 1: List the numbers less than 10 that are odd natural numbers: 1, 3, 5, 7, 9. Step 2: Write the roster form: {1, 3, 5, 7, 9}. Step 3: This is a set because the collection is well-defined. It is p

A: चरण 1: 10 से कम वे संख्याएँ लिखिए जो विषम प्राकृतिक संख्याएँ हैं: 1, 3, 5, 7, 9. चरण 2: रोस्टर रूप लिखिए: {1, 3, 5, 7, 9}. चरण 3: यह एक समुच्चय है क्योंकि यह संग्रह सु-स्पष्ट है। यह साफ़-साफ़ तय करना

A: Step 1: Identify the common property: each element is a vowel in English alphabet. Step 2: Use the set-builder form: V = {x : x is a vowel in English alphabet} Step 3: Here x is the element variable.

A: Step 1: List each element of A with each element of B. Step 2: Pair red with b, c, s. Step 3: Pair blue with b, c, s. Step 4: Write all ordered pairs. Answer: A × B = {(red, b), (red, c), (red, s), (b

A: चरण 1: A के प्रत्येक अवयव को B के प्रत्येक अवयव के साथ लिखिए। चरण 2: red को b, c, s के साथ युग्मित कीजिए। चरण 3: blue को b, c, s के साथ युग्मित कीजिए। चरण 4: सभी क्रमित युग्म लिखिए। उत्तर: A × B = {(r

A: Use n(A × B) = pq. Step 1: Here p = 3 and q = 4. Step 2: Multiply: 3 × 4 = 12. Answer: n(A × B) = 12

A: Step 1: Use the conversion formula Radian measure = π/180 × Degree measure. Step 2: Substitute 45°. Radian measure = (π/180) × 45 = π/4. Answer: 45° = π/4 radian.

A: Step 1: Use the conversion formula Radian measure = π/180 × Degree measure. Step 2: Substitute 45°. Radian measure = (π/180) × 45 = π/4. Answer: 45° = π/4 radian.

A: Step 1: Use the conversion formula Degree measure = 180/π × Radian measure. Step 2: Substitute π/3. Degree measure = 180/π × π/3 = 60°. Answer: π/3 radian = 60°.