Sequences and Series — Flashcards
CBSE · Class 11 · Mathematics
60 flashcards for Sequences and Series (CBSE Class 11 Mathematics) to test yourself on key terms and facts. Part of the CBSE Class 11 Mathematics syllabus.
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Find the first five terms of the sequence defined by a_n = n(n + 2).
Answer
Step 1: Substitute n = 1, 2, 3, 4, 5. Step 2: a_1 = 1(1 + 2) = 3. Step 3: a_2 = 2(2 + 2) = 8. Step 4: a_3 = 3(3 + 2) = 15. Step 5: a_4 = 4(4 + 2) = 24. Step 6: a_5 = 5(5 + 2) = 35. Answer: 3, 8, 15, 2…
a_n = n(n + 2). द्वारा परिभाषित अनुक्रम के पहले पाँच पद ज्ञात कीजिए।
Answer
चरण 1: n = 1, 2, 3, 4, 5 प्रतिस्थापित करें। चरण 2: a_1 = 1(1 + 2) = 3. चरण 3: a_2 = 2(2 + 2) = 8. चरण 4: a_3 = 3(3 + 2) = 15. चरण 5: a_4 = 4(4 + 2) = 24. चरण 6: a_5 = 5(5 + 2) = 35. उत्तर: 3, 8, 15, 2…
Find the first five terms of the sequence defined by a_n = n / (n + 1).
Answer
Step 1: Substitute n = 1, 2, 3, 4, 5. Step 2: a_1 = 1/2. Step 3: a_2 = 2/3. Step 4: a_3 = 3/4. Step 5: a_4 = 4/5. Step 6: a_5 = 5/6. Answer: 1/2, 2/3, 3/4, 4/5, 5/6.
a_n = n / (n + 1). द्वारा परिभाषित अनुक्रम के पहले पाँच पद ज्ञात कीजिए।
Answer
चरण 1: n = 1, 2, 3, 4, 5 को प्रतिस्थापित करें। चरण 2: a_1 = 1/2. चरण 3: a_2 = 2/3. चरण 4: a_3 = 3/4. चरण 5: a_4 = 4/5. चरण 6: a_5 = 5/6. उत्तर: 1/2, 2/3, 3/4, 4/5, 5/6.
Find the first five terms of the sequence defined by a_n = 2^n.
Answer
Step 1: Substitute n = 1, 2, 3, 4, 5. Step 2: a_1 = 2^1 = 2. Step 3: a_2 = 2^2 = 4. Step 4: a_3 = 2^3 = 8. Step 5: a_4 = 2^4 = 16. Step 6: a_5 = 2^5 = 32. Answer: 2, 4, 8, 16, 32.
a_n = 2^n द्वारा परिभाषित अनुक्रम के पहले पाँच पद ज्ञात कीजिए।
Answer
चरण 1: n = 1, 2, 3, 4, 5 को प्रतिस्थापित करें। चरण 2: a_1 = 2^1 = 2. चरण 3: a_2 = 2^2 = 4. चरण 4: a_3 = 2^3 = 8. चरण 5: a_4 = 2^4 = 16. चरण 6: a_5 = 2^5 = 32. उत्तर: 2, 4, 8, 16, 32.
Find the 20th term of the sequence a_n = (n - 1)(2 - n)(3 + n).
Answer
Step 1: Substitute n = 20. Step 2: a_20 = (20 - 1)(2 - 20)(3 + 20). Step 3: a_20 = 19 × (-18) × 23. Step 4: 19 × 18 = 342. Step 5: 342 × 23 = 7866. Step 6: Sign is negative. Answer: a_20 = -7866.
अनुक्रम a_n = (n - 1)(2 - n)(3 + n). का 20वां पद ज्ञात कीजिए।
Answer
चरण 1: n = 20. प्रतिस्थापित करें चरण 2: a_20 = (20 - 1)(2 - 20)(3 + 20). चरण 3: a_20 = 19 × (-18) × 23. चरण 4: 19 × 18 = 342. चरण 5: 342 × 23 = 7866. चरण 6: चिह्न ऋणात्मक है। उत्तर: a_20 = -7866.
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- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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