Statistics
CBSE · Class 11 · Mathematics
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Batsman A scored 30, 91, 0, 64, 42, 80, 30, 5, 117, 71 in 10 matches. Find the mean.
Answer
Step 1: Add the scores = 30 + 91 + 0 + 64 + 42 + 80 + 30 + 5 + 117 + 71 = 530. Step 2: Divide by the number of observations: 530 ÷ 10 = 53. Answer: Mean = 53.
बल्लेबाज ए ने 10 मैचों में 30, 91, 0, 64, 42, 80, 30, 5, 117, 71 रन बनाए। माध्य ज्ञात कीजिए।
Answer
चरण 1: स्कोरs = 30 + 91 + 0 + 64 + 42 + 80 + 30 + 5 + 117 + 71 = 530. जोड़ें चरण 2: प्रेक्षणों की संख्या से भाग दें: 530 ÷ 10 = 53. उत्तर: मीn = 53.
Batsman B scored 53, 46, 48, 50, 53, 53, 58, 60, 57, 52 in 10 matches. Find the median.
Answer
Step 1: Arrange in order: 46, 48, 50, 52, 53, 53, 53, 57, 58, 60. Step 2: There are 10 observations, so median is the mean of the 5th and 6th observations. Step 3: 5th = 53 and 6th = 53. Step 4: Media…
बल्लेबाज बी ने 10 मैचों में 53, 46, 48, 50, 53, 53, 58, 60, 57, 52 रन बनाए। माध्यिका ज्ञात कीजिए।
Answer
चरण 1: क्रम में लगाएँ: 46, 48, 50, 52, 53, 53, 53, 57, 58, 60. चरण 2: यहाँ 10 अवलोकन हैं, इसलिए माध्यिका 5वें और 6वें अवलोकन का माध्य है। चरण 3: 5th = 53 and 6th = 53. चरण 4: माध्यn = (53 + 53) ÷ 2 = …
Find the range of Batsman A's scores: 30, 91, 0, 64, 42, 80, 30, 5, 117, 71.
Answer
Step 1: Identify the maximum value = 117. Step 2: Identify the minimum value = 0. Step 3: Use Range = Maximum value – Minimum value. Step 4: Range = 117 – 0 = 117. Answer: Range = 117.
बल्लेबाज ए के अंकों की सीमा ज्ञात कीजिए: 30, 91, 0, 64, 42, 80, 30, 5, 117, 71।
Answer
चरण 1: अधिकतम मानe = 117. की पहचान करें चरण 2: न्यूनतम मानe = 0. की पहचान करें चरण 3: रंगe = Maximum value – Minimum value. का उपयोग करें चरण 4: रंगe = 117 – 0 = 117. उत्तर: रंगe = 117.
Why can two data sets have the same mean and median but different spread? Use the two batsmen scores as an example.
Answer
Same mean and median show the centre of the data, but they do not show how far the values are spread out. Batsman A has scores from 0 to 117, so the spread is large. Batsman B has scores from 46 to 60…
दो डेटा सेटों का माध्य और माध्यिका समान क्यों हो सकता है लेकिन प्रसार अलग-अलग क्यों हो सकता है? दो बल्लेबाजों के स्कोर को एक उदाहरण के रूप में उपयोग करें।
Answer
माध्य और माध्यिका दोनों ही डेटा के केंद्र को दर्शाते हैं, लेकिन वे यह नहीं बताते कि मान कितने दूर तक फैले हुए हैं। बल्लेबाज ए के स्कोर 0 से 117 तक हैं, इसलिए फैलाव अधिक है। बल्लेबाज बी के स्कोर 46 से …
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