Straight Lines — Flashcards
CBSE · Class 11 · Mathematics
60 flashcards for Straight Lines (CBSE Class 11 Mathematics) to test yourself on key terms and facts. Part of the CBSE Class 11 Mathematics syllabus.
Interactive on Super Tutor
Studying Straight Lines? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
Free trial, no card needed.
Find the slope of the line through the points (3, -2) and (-1, 4).
Answer
Use the slope formula: m = (y2 - y1) / (x2 - x1) Step 1: Substitute the points: m = (4 - (-2)) / (-1 - 3) Step 2: Simplify: m = 6 / -4 Step 3: Reduce the fraction: m = -3/2 Answer: The slope is -3/2.
बिंदुओं (3, -2) और (-1, 4) से गुजरने वाली रेखा का ढलान ज्ञात कीजिए।
Answer
ढलान सूत्र का उपयोग करें: m = (y2 - y1) / (x2 - x1) चरण 1: बिंदुओं को प्रतिस्थापित करें: m = (4 - (-2)) / (-1 - 3) चरण 2: सरल करें: m = 6 / -4 चरण 3: भिन्न को कम करें: m = -3/2 उत्तर: ढलान -3/2 है।…
Find the slope of the line through the points (3, -2) and (7, -2).
Answer
Use m = (y2 - y1) / (x2 - x1) Step 1: Substitute: m = (-2 - (-2)) / (7 - 3) Step 2: Simplify: m = 0 / 4 Step 3: Final value: m = 0 Answer: The slope is 0. This is a horizontal line.
बिंदुओं (3, -2) और (7, -2) से गुजरने वाली रेखा का ढलान ज्ञात कीजिए।
Answer
m = (y2 - y1) / (x2 - x1) का प्रयोग करें चरण 1: प्रतिस्थापित करें: m = (-2 - (-2)) / (7 - 3) चरण 2: सरल करें: m = 0 / 4 चरण 3: अंतिम मान: m = 0 उत्तर: ढलान 0 है। यह एक क्षैतिज रेखा है।…
Find the slope of the line through the points (3, -2) and (3, 4).
Answer
Use m = (y2 - y1) / (x2 - x1) Step 1: Substitute: m = (4 - (-2)) / (3 - 3) Step 2: Simplify: m = 6 / 0 Step 3: Division by 0 is not defined Answer: The slope is not defined. This is a vertical line.
बिंदुओं (3, -2) और (3, 4) से गुजरने वाली रेखा का ढलान ज्ञात कीजिए।
Answer
m = (y2 - y1) / (x2 - x1) का उपयोग करें चरण 1: प्रतिस्थापित करें: m = (4 - (-2)) / (3 - 3) चरण 2: सरल करें: m = 6 / 0 चरण 3: 0 से विभाजन परिभाषित नहीं है उत्तर: ढलान परिभाषित नहीं है। यह एक ऊर्ध्वाधर …
If a line makes an inclination of 60° with the positive x-axis, find its slope.
Answer
Use m = tan θ Step 1: Here θ = 60° Step 2: Substitute: m = tan 60° Step 3: tan 60° = √3 Answer: The slope is √3.
यदि कोई रेखा धनात्मक x-अक्ष के साथ 60° का झुकाव बनाती है, तो उसकी ढलान ज्ञात कीजिए।
Answer
m = tan θ का प्रयोग करें चरण 1: यहाँ θ = 60° चरण 2: प्रतिस्थापित करें: m = tan 60° चरण 3: tan 60° = √3 उत्तर: ढलान √3. है…
+52 more flashcards
Practise AllFrequently Asked Questions
What are the important topics in Straight Lines for CBSE Class 11 Mathematics?
How many flashcards are available for Straight Lines?
How should I revise Straight Lines for Class 11 exams?
Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Straight Lines
Practice Quiz
Test yourself with a quick quiz
Important Questions
Exam-style questions with answers
Revision Notes
Key points for last-minute revision
Formula Sheet
The chapter's formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect
Study Plan
Step-by-step plan for this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Straight Lines chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for CBSE Class 11 Mathematics. Free to start, no card needed.