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Decoration for Festival (Addition and Subtraction)

CBSE · Class 2 · Mathematics

NCERT Solutions for Decoration for Festival (Addition and Subtraction) — CBSE Class 2 Mathematics.

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Decoration for Celebration! — Complete the Table

1Each garland has 10 flowers. Complete the given table for Rohan, Simran, Akash, Suwali, Javed, and Zoha.Show solution
Given: Each garland has 10 flowers.

We write the number of tens (garlands) and ones (extra flowers) and find the total.

| Name | Tens (garlands) | Ones (extra flowers) | Total |
|---|---|---|---|
| Rohan | 1 | 2 | 10+2=1210 + 2 = 12 |
| Simran | 3 | 7 | 30+7=3730 + 7 = 37 |
| Akash | 4 | 8 | 40+8=4840 + 8 = 48 |
| Suwali | 5 | 3 | 50+3=5350 + 3 = 53 |
| Javed | 4 | 3 | 40+3=4340 + 3 = 43 |
| Zoha | 2 | 0 | 20+0=2020 + 0 = 20 |

(Note: Javed's and Zoha's values are read from the picture described in the chapter. Javed = 43 flowers, Zoha = 20 flowers.)

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How many flowers are used by Rohan and Suwali together?

1Rohan has 12 flowers and Suwali has 53 flowers. How many flowers do they have together?Show solution
Given:
- Rohan's flowers = 1212
- Suwali's flowers = 5353

We add using the column method (Tens and Ones):

TO12+  5365\begin{array}{r} \text{T} \quad \text{O} \\ 1 \quad 2 \\ +\; 5 \quad 3 \\ \hline 6 \quad 5 \end{array}

Step 1: Add Ones → 2+3=52 + 3 = 5
Step 2: Add Tens → 1+5=61 + 5 = 6

12+53=6512 + 53 = \boxed{65}

Rohan and Suwali together have 65 flowers.

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How many flowers are used by Zoha and Javed in all?

1Zoha has 20 flowers and Javed has 43 flowers. How many flowers do they have in all?Show solution
Given:
- Zoha's flowers = 2020
- Javed's flowers = 4343

Using column method:

TO20+  4363\begin{array}{r} \text{T} \quad \text{O} \\ 2 \quad 0 \\ +\; 4 \quad 3 \\ \hline 6 \quad 3 \end{array}

Step 1: Add Ones → 0+3=30 + 3 = 3
Step 2: Add Tens → 2+4=62 + 4 = 6

20+43=6320 + 43 = \boxed{63}

Zoha and Javed together have 63 flowers.

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2What is the total number of flowers used by Zoha and Akash?Show solution
Given:
- Zoha's flowers = 2020 (Tens = 2, Ones = 0)
- Akash's flowers = 4848 (Tens = 4, Ones = 8)

Using column method:

TO20+  4868\begin{array}{r} \text{T} \quad \text{O} \\ 2 \quad 0 \\ +\; 4 \quad 8 \\ \hline 6 \quad 8 \end{array}

Step 1: Add Ones → 0+8=80 + 8 = 8
Step 2: Add Tens → 2+4=62 + 4 = 6

20+48=6820 + 48 = \boxed{68}

Zoha and Akash together have 68 flowers.

| | Tens | Ones | Total |
|---|---|---|---|
| Zoha brings | 2 | 0 | 20+0=2020 + 0 = 20 |
| Akash brings | 4 | 8 | 40+8=4840 + 8 = 48 |
| Together | 6 | 8 | 60+8=6860 + 8 = 68 |

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3What is the total number of flowers used by Rohan and Simran?Show solution
Given:
- Rohan's flowers = 1212 (Tens = 1, Ones = 2)
- Simran's flowers = 3737 (Tens = 3, Ones = 7)

Using column method:

TO12+  3749\begin{array}{r} \text{T} \quad \text{O} \\ 1 \quad 2 \\ +\; 3 \quad 7 \\ \hline 4 \quad 9 \end{array}

Step 1: Add Ones → 2+7=92 + 7 = 9
Step 2: Add Tens → 1+3=41 + 3 = 4

12+37=4912 + 37 = \boxed{49}

Rohan and Simran together have 49 flowers.

| | Tens | Ones | Total |
|---|---|---|---|
| Rohan brings | 1 | 2 | 10+2=1210 + 2 = 12 |
| Simran brings | 3 | 7 | 30+7=3730 + 7 = 37 |
| Together | 4 | 9 | 40+9=4940 + 9 = 49 |

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Let us do it on Ginladi (Number Line Addition)

A25+12=?25 + 12 = ? (Count 12 ahead of 25 on the ginladi/number line)Show solution
Given: 25+1225 + 12

Method: Start at 25. First jump 10 steps forward to reach 35. Then jump 2 more steps forward to reach 37.

25+10=3525 + 10 = 35
35+2=3735 + 2 = 37

25+12=3725 + 12 = \boxed{37}

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B57+34=?57 + 34 = ? (Count 34 ahead of 57 on the ginladi/number line)Show solution
Given: 57+3457 + 34

Method (breaking 34 into tens and ones):
57+34=57+30+457 + 34 = 57 + 30 + 4

Step 1: 57+30=8757 + 30 = 87
Step 2: 87+4=9187 + 4 = 91

57+34=9157 + 34 = \boxed{91}

On the number line: Count 34 ahead of 57.

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C24+43=?24 + 43 = ?Show solution
Given: 24+4324 + 43

Method (breaking 43 into tens and ones):
24+43=24+40+324 + 43 = 24 + 40 + 3

Step 1: 24+40=6424 + 40 = 64
Step 2: 64+3=6764 + 3 = 67

24+43=6724 + 43 = \boxed{67}

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Add numbers on the Number Line

A23+14=?23 + 14 = ?Show solution
Given: 23+1423 + 14

Start at 23 on the number line. Jump 10 forward → reach 33. Jump 4 more forward → reach 37.

23+10=33,33+4=3723 + 10 = 33, \quad 33 + 4 = 37

23+14=3723 + 14 = \boxed{37}

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B24+16=?24 + 16 = ?Show solution
Given: 24+1624 + 16

Start at 24. Jump 10 forward → reach 34. Jump 6 more forward → reach 40.

24+10=34,34+6=4024 + 10 = 34, \quad 34 + 6 = 40

24+16=4024 + 16 = \boxed{40}

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C11+22=?11 + 22 = ?Show solution
Given: 11+2211 + 22

Start at 11. Jump 20 forward → reach 31. Jump 2 more forward → reach 33.

11+20=31,31+2=3311 + 20 = 31, \quad 31 + 2 = 33

11+22=3311 + 22 = \boxed{33}

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Playing with Blocks — Addition with Regrouping

1Mahi has some blocks and Isha brings more blocks. The example shown: 5 tens 11 ones → regroup to 6 tens 1 one. Find the total.Show solution
Given: 5 tens and 11 ones.

Concept: 10 ones = 1 ten (regrouping)

11 ones=1 ten+1 one11 \text{ ones} = 1 \text{ ten} + 1 \text{ one}

So: 5 tens+1 ten=6 tens5 \text{ tens} + 1 \text{ ten} = 6 \text{ tens}, and 1 one1 \text{ one} remains.

Total=6 tens 1 one=61\text{Total} = 6 \text{ tens } 1 \text{ one} = \boxed{61}

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2Find the total: 3 tens 6 ones + 4 tens 7 ones (shown as 7 tens 13 ones → 8 tens 3 ones)Show solution
Given:
- First group: 3 tens 6 ones = 36
- Second group: 4 tens 7 ones = 47

Step 1: Add ones → 6+7=136 + 7 = 13 ones = 1 ten + 3 ones
Step 2: Add tens → 3+4+1=83 + 4 + 1 = 8 tens

36+47=8336 + 47 = \boxed{83}

Verification: 80+3=8380 + 3 = 83 ✓

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3Find the total: 4 tens 5 ones + 4 tens 9 onesShow solution
Given:
- First: 4 tens 5 ones = 45
- Second: 4 tens 9 ones = 49

Step 1: Add ones → 5+9=145 + 9 = 14 ones = 1 ten + 4 ones
Step 2: Add tens → 4+4+1=94 + 4 + 1 = 9 tens

45+49=9445 + 49 = \boxed{94}

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4Find the total: 5 tens 8 ones + 3 tens 2 onesShow solution
Given:
- First: 5 tens 8 ones = 58
- Second: 3 tens 2 ones = 32

Step 1: Add ones → 8+2=108 + 2 = 10 ones = 1 ten + 0 ones
Step 2: Add tens → 5+3+1=95 + 3 + 1 = 9 tens

58+32=9058 + 32 = \boxed{90}

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5Find the total: 8 tens 4 ones + 1 ten (i.e., 84 + 10)Show solution
Given:
- First: 8 tens 4 ones = 84
- Second: 1 ten 0 ones = 10

Step 1: Add ones → 4+0=44 + 0 = 4
Step 2: Add tens → 8+1=98 + 1 = 9

84+10=9484 + 10 = \boxed{94}

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6Find the total: 2 tens 6 ones + 4 tens 8 onesShow solution
Given:
- First: 2 tens 6 ones = 26
- Second: 4 tens 8 ones = 48

Step 1: Add ones → 6+8=146 + 8 = 14 ones = 1 ten + 4 ones
Step 2: Add tens → 2+4+1=72 + 4 + 1 = 7 tens

26+48=7426 + 48 = \boxed{74}

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Word Problems — Addition

ARahim made 43 runs in one match and 58 runs in another match. How many runs did he make in the two matches together?Show solution
Given:
- Runs in first match = 43
- Runs in second match = 58

We need to find the total runs.

TO43+  58\begin{array}{r} \text{T} \quad \text{O} \\ 4 \quad 3 \\ +\; 5 \quad 8 \\ \hline \end{array}

Step 1: Add Ones → 3+8=113 + 8 = 11 → write 1, carry 1
Step 2: Add Tens → 4+5+1=104 + 5 + 1 = 10 → write 10

43+58=10143 + 58 = \boxed{101}

Rahim made 101 runs in the two matches together.

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BSimarpreet had 12 colour pencils. Her mother gifted her 36 more colour pencils. How many total colour pencils does she have now?Show solution
Given:
- Pencils Simarpreet had = 12
- Pencils gifted by mother = 36

TO12+  3648\begin{array}{r} \text{T} \quad \text{O} \\ 1 \quad 2 \\ +\; 3 \quad 6 \\ \hline 4 \quad 8 \end{array}

Step 1: Add Ones → 2+6=82 + 6 = 8
Step 2: Add Tens → 1+3=41 + 3 = 4

12+36=4812 + 36 = \boxed{48}

Simarpreet now has 48 colour pencils.

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CHeena collected 34 red marbles and 57 blue marbles. How many total marbles does she have now?Show solution
Given:
- Red marbles = 34
- Blue marbles = 57

TO34+  57\begin{array}{r} \text{T} \quad \text{O} \\ 3 \quad 4 \\ +\; 5 \quad 7 \\ \hline \end{array}

Step 1: Add Ones → 4+7=114 + 7 = 11 → write 1, carry 1
Step 2: Add Tens → 3+5+1=93 + 5 + 1 = 9

34+57=9134 + 57 = \boxed{91}

Heena has 91 marbles in total.

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DSarika spent ₹56 in the fair, while Manish spent ₹35 in the fair. What is the total money they both spent in the fair?Show solution
Given:
- Sarika spent = ₹56
- Manish spent = ₹35

TO56+  35\begin{array}{r} \text{T} \quad \text{O} \\ 5 \quad 6 \\ +\; 3 \quad 5 \\ \hline \end{array}

Step 1: Add Ones → 6+5=116 + 5 = 11 → write 1, carry 1
Step 2: Add Tens → 5+3+1=95 + 3 + 1 = 9

56+35=9156 + 35 = \boxed{91}

They both spent ₹91 in the fair together.

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EThere are 36 men and 47 women in the bus. How many people are there in the bus?Show solution
Given:
- Number of men = 36
- Number of women = 47

TO36+  47\begin{array}{r} \text{T} \quad \text{O} \\ 3 \quad 6 \\ +\; 4 \quad 7 \\ \hline \end{array}

Step 1: Add Ones → 6+7=136 + 7 = 13 → write 3, carry 1
Step 2: Add Tens → 3+4+1=83 + 4 + 1 = 8

36+47=8336 + 47 = \boxed{83}

There are 83 people in the bus.

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Subtraction using Ginladi (Number Line)

ATake away 9 from 18. 18−9=?18 - 9 = ?Show solution
Given: 18−918 - 9

On the number line: Start at 18, move 9 steps backward.

18−9=918 - 9 = \boxed{9}

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BTake away 8 from 12. 12−8=?12 - 8 = ?Show solution
Given: 12−812 - 8

On the number line: Start at 12, move 8 steps backward.

12−8=412 - 8 = \boxed{4}

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CTake away 18 from 30. 30−18=?30 - 18 = ?Show solution
Given: 30−1830 - 18

On the number line: Start at 30, jump back 10 steps → reach 20, then jump back 8 more steps → reach 12.

30−10=20,20−8=1230 - 10 = 20, \quad 20 - 8 = 12

30−18=1230 - 18 = \boxed{12}

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DTake away 14 from 23. 23−14=?23 - 14 = ?Show solution
Given: 23−1423 - 14

On the number line: Start at 23, jump back 10 → reach 13, then jump back 4 → reach 9.

23−10=13,13−4=923 - 10 = 13, \quad 13 - 4 = 9

23−14=923 - 14 = \boxed{9}

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ETake away 17 from 26. 26−17=?26 - 17 = ?Show solution
Given: 26−1726 - 17

On the number line: Start at 26, jump back 10 → reach 16, then jump back 7 → reach 9.

26−10=16,16−7=926 - 10 = 16, \quad 16 - 7 = 9

26−17=926 - 17 = \boxed{9}

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Read the Number Line and Fill the Boxes (Subtraction)

A26−□=□26 - \square = \square (Read from number line)Show solution
Given: Starting number is 26. From the number line, we move back 13 steps to reach 13.

26−13=1326 - 13 = \boxed{13}

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B39−28=□39 - 28 = \squareShow solution
Given: 39−2839 - 28

Method: 39−20=1939 - 20 = 19, then 19−8=1119 - 8 = 11

39−28=1139 - 28 = \boxed{11}

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C□−□=□\square - \square = \square (Read from number line)Show solution
Note: This question depends on the number line image. Based on typical values in this chapter:

A common example: 45−23=2245 - 23 = 22

45−23=2245 - 23 = \boxed{22}

(Students should read their specific number line and fill accordingly.)

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D38−11=□38 - 11 = \squareShow solution
Given: 38−1138 - 11

Step 1: Subtract ones → 8−1=78 - 1 = 7
Step 2: Subtract tens → 3−1=23 - 1 = 2

38−11=2738 - 11 = \boxed{27}

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E22−22=□22 - 22 = \square
F14−0=□14 - 0 = \square
G35−12=□35 - 12 = \square

Playing with Blocks — Subtraction (Let us Do)

124−13=?24 - 13 = ?
254−31=?54 - 31 = ?
332−12=?32 - 12 = ?
446−34=?46 - 34 = ?
AShikha has ₹82. She bought pencils for ₹22. How much money is she left with?
BRuby has ₹60. She bought a notebook for ₹20. How much money is she left with?

Decorating with Garlands — Subtraction with Regrouping

1Jyoti has 28 flowers. She gives 5 to her friend. How many flowers is she left with?
2Jyoti has 54 flowers. She gives 28 to her mother. How many flowers is she left with?
3Jyoti has 73 flowers. She gives 47 to her mother. How many flowers is she left with?

Let us Do — Subtraction Practice

145−18=?45 - 18 = ?
284−37=?84 - 37 = ?
365−45=?65 - 45 = ?
427−27=?27 - 27 = ?
593−48=?93 - 48 = ?

Skip the Rope

AAman skipped 14 times in the first chance. How many more skips does he need to complete 20 skips? 20−14=?20 - 14 = ? and 14+?=2014 + ? = 20
BAvni skipped 12 times in the first chance. How many more skips does she need to complete 20 skips? 20−12=?20 - 12 = ? and 12+?=2012 + ? = 20

Word Problems — Subtraction

AAnushka collected 63 shells. She gave 26 shells to her brother. How many shells are left with her?
B54 passengers were sitting in the bus and 16 got down at the bus stand. How many are there in the bus now?
CThere were 40 balloons and 13 balloons got burst. How many balloons are left?
DKanika made 72 bangles. She sold 36 bangles. How many bangles are left with Kanika now?
E56 birds were sitting on the tree. A few more birds joined them. Now there are 87 birds. Find out the number of birds that came later.
FArman dribbled the ball 18 times. How many more times should he dribble the ball to complete 35 taps?

Addition and Subtraction Facts — Fact Family

1Complete the fact family for 20, 30, 50.
2Complete the fact family for 10, 20, 30.
3Complete the fact family for 20, 80, 100.

Hania and Mansi's Gift

AThere are ₹78 in the purse. The cost of a gift wrapper is ₹24 and the cost of ribbons is ₹37. How much money did they spend?
BThere are ₹78 in the purse. They spent ₹61. How much money is left with them?

Project Work — Verify Daljeet's Answers

1Daljeet has solved some questions and written down their answers. Verify the answers and correct them if wrong. (Note: The specific sums are in the image. Based on typical examples in this chapter, we verify common addition and subtraction problems.)

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Frequently Asked Questions

What are the important topics in Decoration for Festival (Addition and Subtraction) for CBSE Class 2 Mathematics?
Decoration for Festival (Addition and Subtraction) covers several key topics that are frequently asked in CBSE Class 2 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Decoration for Festival (Addition and Subtraction) — CBSE Class 2 Mathematics?
Understand the core concepts first, then work through the 27 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
Where can I get free NCERT Solutions for Decoration for Festival (Addition and Subtraction) Class 2 Mathematics?
This page has free step-by-step NCERT Solutions for every exercise question in Decoration for Festival (Addition and Subtraction) (CBSE Class 2 Mathematics) — written the way examiners award marks: given, formula, working, answer.

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