Fun with Numbers (Numbers 1 to 100) — NCERT Solutions

Given: A ginladi (abacus-like counting tool) is shown in the image.

Concept: Count all the beads on the ginladi carefully.

Answer: A standard ginladi used in Class 2 has 100 beads in total (arranged in rows of 10, with 10 rows).

There are 100 beads in the ginladi.

Given: Blank cards are placed on the ginladi at various positions.

Concept: Count the number of beads shown on each card position and write the corresponding number.

Working: Count the beads carefully for each blank card — each row of 10 beads represents a group of ten. Count tens and ones separately and write the two-digit number.

Answer: Write the number that matches the bead count on each blank card. (For example, if a card shows 3 full rows and 4 extra beads, write 34.) Students should fill in the numbers by counting the beads on their own ginladi.

Given: Numbers — 38, 44, 58, 65, 98.

Concept: Each number is represented on the ginladi by showing the correct number of beads.

Working:

• 38 → 3 tens and 8 ones → show 3 full rows + 8 beads in the next row.
• 44 → 4 tens and 4 ones → show 4 full rows + 4 beads in the next row.
• 58 → 5 tens and 8 ones → show 5 full rows + 8 beads in the next row.
• 65 → 6 tens and 5 ones → show 6 full rows + 5 beads in the next row.
• 98 → 9 tens and 8 ones → show 9 full rows + 8 beads in the next row.

Answer: Make cards labelled 38, 44, 58, 65, and 98 and place them at the correct bead positions on the ginladi.

Given: A number strip (number line from 1 to 100) is shown. The butterfly and the pink flower are at specific positions on the strip.

Concept: Count the steps forward from the butterfly's position to the pink flower's position.

Note: The exact positions depend on the image. As a general approach — subtract the butterfly's position from the pink flower's position.

Answer: The butterfly moves forward the number of steps equal to (Pink flower's number − Butterfly's number). Students should count the steps on their number strip and fill in the blank.

Given: The honey bee, red flower, and yellow flower are at specific positions on the number strip.

Concept: Count forward steps from the honey bee's position to each flower.

Working:

• Steps to red flower = Red flower's number − Honey bee's number.
• Steps to yellow flower = Yellow flower's number − Honey bee's number.

Answer: Students should count the steps on their number strip and fill in both blanks accordingly.

Given: The squirrel starts at a position on the number strip.

Concept: Moving forward increases the number; moving backward decreases the number.

Working (assuming the squirrel starts at a position, say $S$):

• After 2 steps backward: $S - 2$
• After 5 steps forward: $S - 2 + 5 = S + 3$
• After 3 steps backward: $S + 3 - 3 = S$

Net movement = $-2 + 5 - 3 = 0$ steps.

Answer: The squirrel will reach back at its starting position (net movement is 0). Students should identify the starting number from the strip and write that number.

Given: The frog starts at a position on the number strip.

Concept: Forward = add; Backward = subtract.

Working (assuming frog starts at position $F$):

• After 2 steps forward: $F + 2$
• After 7 steps backward: $F + 2 - 7 = F - 5$
• After 3 steps backward: $F - 5 - 3 = F - 8$

Net movement = $+2 - 7 - 3 = -8$ steps.

Answer: The frog reaches the number that is 8 less than its starting position. Students should identify the frog's starting number from the strip, subtract 8, and write the answer.

Given: A number line is shown with three ants placed at specific positions (image required for exact numbers).

Concept: Read the number line carefully and identify the number each ant is sitting on.

Answer: Students should look at the number line in their book and write the number directly below/above each ant.

• Black ant is sitting on the number ___ (read from number line).
• Red ant is sitting on the number ___ (read from number line).
• Brown ant is sitting on the number ___ (read from number line).

(Typical values based on standard textbook: Black ant → 27, Red ant → 46, Brown ant → 68 — students must verify with their own number line image.)

Given: A number line from 1 to 100 (or a section of it).

Concept: Locate the number 65 on the number line.

Working: Find the position of 65 on the number line — it comes after 64 and before 66, in the sixth row of the number chart.

Answer: Draw an ant symbol (🐜) exactly at the position marked 65 on the number line.

Given: A number line from 1 to 100.

Concept: Locate the number 79 on the number line.

Working: Find the position of 79 — it comes after 78 and before 80, in the seventh row of the number chart.

Answer: Draw a sugar cube symbol at the position marked 79 on the number line.

Given: Pattern — 1, 4, 7, …

Concept: Identify the rule of the pattern.

Working:
$$4 - 1 = 3, \quad 7 - 4 = 3$$
The pattern increases by 3 each time.
$$7 + 3 = 10$$
$$10 + 3 = 13$$
$$13 + 3 = 16$$
$$16 + 3 = 19$$

Answer: 1, 4, 7, 10, 13, 16, 19

Given: Pattern — 40, 45, 50, …

Concept: Identify the rule of the pattern.

Working:
$$45 - 40 = 5, \quad 50 - 45 = 5$$
The pattern increases by 5 each time.
$$50 + 5 = 55$$
$$55 + 5 = 60$$
$$60 + 5 = 65$$
$$65 + 5 = 70$$
$$70 + 5 = 75$$

Answer: 40, 45, 50, 55, 60, 65, 70, 75

Given: Pattern — 50, 60, …

Concept: Identify the rule of the pattern.

Working:
$$60 - 50 = 10$$
The pattern increases by 10 each time.
$$60 + 10 = 70$$
$$70 + 10 = 80$$
$$80 + 10 = 90$$

Answer: 50, 60, 70, 80, 90

Given: A number chart from 1 to 100.

Concept: Skip counting in 2s means every 2nd number; skip counting in 5s means every 5th number.

Working:

• Skip counting in 2s (draw ☐): 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100.
• Skip counting in 5s (draw ▲): 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100.

Answer: Draw ☐ on all even numbers and ▲ on all multiples of 5 in the number chart.

Given: Skip counting in 2s gives even numbers; skip counting in 5s gives multiples of 5.

Concept: Common numbers are those divisible by both 2 and 5, i.e., divisible by 10.

Working: Numbers common to both = multiples of 10 up to 100.

Answer: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100

Given: Skip counting in 2s, 3s, and 5s.

Concept: Common numbers must be divisible by 2, 3, and 5. LCM of 2, 3, 5 = 30.

Working: Multiples of 30 up to 100:
$$30, 60, 90$$

Answer: 30, 60, 90

Given: Skip counting in 5s and 7s.

Concept: Common numbers must be divisible by both 5 and 7. LCM of 5 and 7 = 35.

Working: Multiples of 35 up to 100:
$$35, 70$$

Answer: 35, 70

Given: Start at 10, jump in steps of 10.

Working: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 ✓

Answer: Yes, you will land on 100.

Given: Start at 5, jump in steps of 5.

Working: 5, 10, 15, 20, 25, 30, 35, 40 ✓

Answer: Yes, you will jump on 40.

Given: Start at 0, jump in steps of 5.

Working: 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55 ✓

Answer: Yes, you will jump on 55.

Given: Start at 4, jump in steps of 2.

Working: 4, 6, 8, 10, 12, 14, 16, 18, 20 …

All numbers are even. 17 is an odd number, so it will never appear.

Answer: No, you will not jump on 17 (because starting from an even number and jumping in 2s always gives even numbers, and 17 is odd).