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NCERT Solutions

Grouping and Sharing (Multiplication and Division)

CBSE · Class 2 · Mathematics

NCERT Solutions for Grouping and Sharing (Multiplication and Division) — CBSE Class 2 Mathematics.

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32 Questions Solved · 15 Sections

Let us Do — Bicycles, Autorickshaws and Cars

1There are 4 bicycles. Each bicycle has 2 wheels. Find the total number of wheels.Show solution
Given: Number of bicycles = 4, wheels on each bicycle = 2.

Total wheels = 2+2+2+2=82 + 2 + 2 + 2 = 8

We are adding 2 four times, so: 4×2=84 \times 2 = 8

Total wheels = 8
2Number of autorickshaws = 2. Each auto has 3 wheels. Find the total wheels.Show solution
Given: Number of autorickshaws = 2, wheels on each = 3.

Total wheels = 3+3=63 + 3 = 6

2×3=62 \times 3 = 6

Total wheels = 6
3Let us do it for cars. (There are 7 cars, each with 4 wheels.) Fill in the blanks.Show solution
Given: Number of cars = 7, number of wheels in each car = 4.

Total wheels = 4+4+4+4+4+4+4=284 + 4 + 4 + 4 + 4 + 4 + 4 = 28

We are adding 4 seven times.

7 times 4 is 28

7 groups of 4 is 28

7×4=287 \times 4 = 28

How many fours are you adding? 7

We can write it as: 7 fours are 28.

Let us Do — Butterflies, Octopuses and Soldiers

1Fill in the blanks for butterflies. (There are 3 butterflies, each with 2 wings.)Show solution
Number of butterflies = 3

Number of wings in each butterfly = 2

Total number of wings = 2+2+2=62 + 2 + 2 = 6

or 3 groups of 2 is 6

3 times 2 is 6

3 twos are 6

3×2=63 \times 2 = 6
2Fill in the blanks for octopuses. (There are 2 octopuses, each with 8 legs.)Show solution
Number of octopuses = 2

Number of legs in each octopus = 8

Total number of legs = 8+8=168 + 8 = 16

2 groups of 8 is 16

2 times 8 is 16

2 eights are 16

2×8=162 \times 8 = 16
3Fill in the blanks for soldiers. (There are 4 lines of soldiers, each line has 10 soldiers.)Show solution
Number of lines = 4

Number of soldiers in each line = 10

Total number of soldiers = 10+10+10+10=4010 + 10 + 10 + 10 = 40

4 times 10 is 40

4 tens are 40

4×10=404 \times 10 = 40

Match the Following

1Match each addition expression with its description and value:
- 9+9+99 + 9 + 9
- 5+5+5+5+5+5+55+5+5+5+5+5+5
- 3+3+3+3+33+3+3+3+3
- 10+10+10+1010+10+10+10
- 8+8+88+8+8
- 7+77+7

Descriptions: 7 fives are, 4 groups of 10, 3×93 \times 9, 3×83 \times 8, 2 sevens are, 5 times 3

Values: 27, 35, 40, 14, 15, 24
Show solution
Step 1 — Calculate each sum:

9+9+9=279 + 9 + 9 = 27 → This is 3×93 \times 927

5+5+5+5+5+5+5=355+5+5+5+5+5+5 = 35 → This is 7 fives are → 35

3+3+3+3+3=153+3+3+3+3 = 15 → This is 5 times 3 → 15

10+10+10+10=4010+10+10+10 = 40 → This is 4 groups of 10 → 40

8+8+8=248+8+8 = 24 → This is 3×83 \times 824

7+7=147+7 = 14 → This is 2 sevens are → 14

Matches:
- 9+9+99+9+93×93 \times 9 ↔ 27
- 5+5+5+5+5+5+55+5+5+5+5+5+5 ↔ 7 fives are ↔ 35
- 3+3+3+3+33+3+3+3+3 ↔ 5 times 3 ↔ 15
- 10+10+10+1010+10+10+10 ↔ 4 groups of 10 ↔ 40
- 8+8+88+8+83×83 \times 8 ↔ 24
- 7+77+7 ↔ 2 sevens are ↔ 14

Complete the Table of 2

1Complete the multiplication table of 2 up to 10.Show solution
Using the pattern: 2×n=n+n2 \times n = n + n

| Dots | Words | Multiplication |
|------|-------|----------------|
| ●● ●● | 2 ones are 2 | 2×1=22 \times 1 = 2 |
| ●●● ●●● | 2 twos are 4 | 2×2=42 \times 2 = 4 |
| ●●●● ●●●● | 2 threes are 6 | 2×3=62 \times 3 = 6 |
| | 2 fours are 8 | 2×4=82 \times 4 = 8 |
| | 2 fives are 10 | 2×5=102 \times 5 = 10 |
| | 2 sixes are 12 | 2×6=122 \times 6 = 12 |
| | 2 sevens are 14 | 2×7=142 \times 7 = 14 |
| | 2 eights are 16 | 2×8=162 \times 8 = 16 |
| | 2 nines are 18 | 2×9=182 \times 9 = 18 |
| | 2 tens are 20 | 2×10=202 \times 10 = 20 |

Complete the Table of 3

1Complete the multiplication table of 3 up to 10.Show solution
Using the pattern: 3×n=3 \times n = sum of nn threes

| Words | Multiplication |
|-------|----------------|
| 3 ones are 3 | 3×1=33 \times 1 = 3 |
| 3 twos are 6 | 3×2=63 \times 2 = 6 |
| 3 threes are 9 | 3×3=93 \times 3 = 9 |
| 3 fours are 12 | 3×4=123 \times 4 = 12 |
| 3 fives are 15 | 3×5=153 \times 5 = 15 |
| 3 sixes are 18 | 3×6=183 \times 6 = 18 |
| 3 sevens are 21 | 3×7=213 \times 7 = 21 |
| 3 eights are 24 | 3×8=243 \times 8 = 24 |
| 3 nines are 27 | 3×9=273 \times 9 = 27 |
| 3 tens are 30 | 3×10=303 \times 10 = 30 |

Complete the Table of 5

1Complete the multiplication table of 5 up to 10.Show solution
Using the pattern: 5×n=5 \times n = sum of nn fives

| Words | Multiplication |
|-------|----------------|
| 5 ones are 5 | 5×1=55 \times 1 = 5 |
| 5 twos are 10 | 5×2=105 \times 2 = 10 |
| 5 threes are 15 | 5×3=155 \times 3 = 15 |
| 5 fours are 20 | 5×4=205 \times 4 = 20 |
| 5 fives are 25 | 5×5=255 \times 5 = 25 |
| 5 sixes are 30 | 5×6=305 \times 6 = 30 |
| 5 sevens are 35 | 5×7=355 \times 7 = 35 |
| 5 eights are 40 | 5×8=405 \times 8 = 40 |
| 5 nines are 45 | 5×9=455 \times 9 = 45 |
| 5 tens are 50 | 5×10=505 \times 10 = 50 |

Complete the Table of 10

1Complete the multiplication table of 10 up to 10.Show solution
Using the pattern: 10×n=10 \times n = sum of nn tens

| Words | Multiplication |
|-------|----------------|
| 10 ones are 10 | 10×1=1010 \times 1 = 10 |
| 10 twos are 20 | 10×2=2010 \times 2 = 20 |
| 10 threes are 30 | 10×3=3010 \times 3 = 30 |
| 10 fours are 40 | 10×4=4010 \times 4 = 40 |
| 10 fives are 50 | 10×5=5010 \times 5 = 50 |
| 10 sixes are 60 | 10×6=6010 \times 6 = 60 |
| 10 sevens are 70 | 10×7=7010 \times 7 = 70 |
| 10 eights are 80 | 10×8=8010 \times 8 = 80 |
| 10 nines are 90 | 10×9=9010 \times 9 = 90 |
| 10 tens are 100 | 10×10=10010 \times 10 = 100 |

How Many? — Bouquets and Gulab Jamuns

1Ram made 4 bouquets with 3 flowers each. Gopal made 3 bouquets with 4 flowers each. How many flowers did each use? What do you observe?Show solution
Ram: 4 groups of 3 flowers → 4×3=124 \times 3 = 12 flowers.

Gopal: 3 groups of 4 flowers → 3×4=123 \times 4 = 12 flowers.

Observation: Even though the groups are arranged differently, the total is the same. 4×3=3×4=124 \times 3 = 3 \times 4 = 12. This shows that the order of multiplication does not change the answer (Commutative Property of Multiplication).
2Fill in the blanks:
(i) 4 groups of 5 gulab jamuns: __ times 5 is __, 4×5=4 \times 5 = __, there are __ gulab jamuns.
(ii) 5 groups of 4 gulab jamuns: __ times 4 is __, 5×4=5 \times 4 = __, there are __ gulab jamuns.
Show solution
(i) 4 groups of 5:

4 times 5 is 20

4×5=204 \times 5 = 20

There are 20 gulab jamuns.

(ii) 5 groups of 4:

5 times 4 is 20

5×4=205 \times 4 = 20

There are 20 gulab jamuns.

Observation: 4×5=5×4=204 \times 5 = 5 \times 4 = 20
3Fill in the blanks:
(i) 6 groups of 4 flowers: __ times 4 is __, 6×4=6 \times 4 = __, there are __ flowers.
(ii) 4 groups of 6 flowers: __ times 6 is __, 4×6=4 \times 6 = __, there are __ flowers.
Show solution
(i) 6 groups of 4:

6 times 4 is 24

6×4=246 \times 4 = 24

There are 24 flowers.

(ii) 4 groups of 6:

4 times 6 is 24

4×6=244 \times 6 = 24

There are 24 flowers.

Word Problems — How Many?

AThere are 8 packets of bindis. Each packet has 5 bindis. How many bindis are there in all?Show solution
Given:
Number of packets = 8
Number of bindis in each packet = 5

8 groups of 5 bindis.

8×5=40 bindis8 \times 5 = 40 \text{ bindis}

There are 40 bindis in all.
BBharti puts 4 buttons on each shirt. She wants to put buttons on 7 shirts. How many buttons does she need?Show solution
Given:
Number of shirts = 7
Number of buttons on each shirt = 4

7 groups of 4 buttons.

7×4=28 buttons7 \times 4 = 28 \text{ buttons}

Bharti needs 28 buttons.
CRita bought 6 pencils of ₹4 each. How much money will she give to the shopkeeper?Show solution
Given:
Number of pencils = 6
Cost of 1 pencil = ₹4

Cost of 6 pencils = 4+4+4+4+4+44 + 4 + 4 + 4 + 4 + 4

6×4=246 \times 4 = 24

Rita will give ₹24 to the shopkeeper.
DFive people can sit in a car. How many people can sit in 8 such cars?Show solution
Given:
Number of people sitting in 1 car = 5
Number of cars = 8

Number of people sitting in 8 cars:

8×5=408 \times 5 = 40

40 people can sit in 8 cars.

Making Multiplication Table — Table of 6 from Table of 3

1Make the table of 6 from the table of 3 by completing the given grid:
Table of 3 (top row): 3, 6, ☐, 12, ☐, ☐, 21, ☐, ☐, 30
Second row (Table of 3 again): 3, ☐, 9, ☐, ☐, 18, ☐, 24, ☐, ☐
Table of 6 (bottom row): 6, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐
Show solution
Step 1 — Complete the Table of 3:

3×1=3, 3×2=6, 3×3=9, 3×4=12, 3×5=15, 3×6=18, 3×7=21, 3×8=24, 3×9=27, 3×10=303 \times 1=3,\ 3 \times 2=6,\ 3 \times 3=9,\ 3 \times 4=12,\ 3 \times 5=15,\ 3 \times 6=18,\ 3 \times 7=21,\ 3 \times 8=24,\ 3 \times 9=27,\ 3 \times 10=30

Top row: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

Second row (same table of 3): 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

Step 2 — Add both rows to get Table of 6:

3+3=6, 6+6=12, 9+9=18, 12+12=24, 15+15=30, 18+18=36, 21+21=42, 24+24=48, 27+27=54, 30+30=603+3=6,\ 6+6=12,\ 9+9=18,\ 12+12=24,\ 15+15=30,\ 18+18=36,\ 21+21=42,\ 24+24=48,\ 27+27=54,\ 30+30=60

Table of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

Making Multiplication Table — Table of 8 from Tables of 2 and 6

1Make the table of 8 from the tables of 2 and 6 by completing the grid:
Table of 2: 2, 4, ☐, ☐, 10, ☐, 14, ☐, 18, 20
Table of 6: 6, ☐, ☐, ☐, ☐, 36, ☐, 48, ☐, ☐
Table of 8: 8, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐
Show solution
Step 1 — Complete the Table of 2:

2,4,6,8,10,12,14,16,18,202, 4, 6, 8, 10, 12, 14, 16, 18, 20

Step 2 — Complete the Table of 6:

6,12,18,24,30,36,42,48,54,606, 12, 18, 24, 30, 36, 42, 48, 54, 60

Step 3 — Add Table of 2 and Table of 6 to get Table of 8:

2+6=8, 4+12=16, 6+18=24, 8+24=32, 10+30=40, 12+36=48, 14+42=56, 16+48=64, 18+54=72, 20+60=802+6=8,\ 4+12=16,\ 6+18=24,\ 8+24=32,\ 10+30=40,\ 12+36=48,\ 14+42=56,\ 16+48=64,\ 18+54=72,\ 20+60=80

Table of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80

Project Work — Arrays with 24 Objects

1Collect 24 small objects. Arrange them in different arrays and write the related multiplication facts.Show solution
Given: Total objects = 24.

We find all ways to arrange 24 objects in equal groups:

| Number of groups | Multiplication fact |
|-----------------|--------------------|
| 3 groups of 8 | 3×8=243 \times 8 = 24 |
| 8 groups of 3 | 8×3=248 \times 3 = 24 |
| 4 groups of 6 | 4×6=244 \times 6 = 24 |
| 6 groups of 4 | 6×4=246 \times 4 = 24 |
| 2 groups of 12 | 2×12=242 \times 12 = 24 |
| 12 groups of 2 | 12×2=2412 \times 2 = 24 |
| 1 group of 24 | 1×24=241 \times 24 = 24 |
| 24 groups of 1 | 24×1=2424 \times 1 = 24 |

We can find 8 multiplication facts for 24.

Sharing — Gulab Jamuns

AHow many gulab jamuns were there in total? (Based on the picture showing gulab jamuns shared among children.)Show solution
From the picture context (gulab jamuns shared equally among children), the total number of gulab jamuns is 20.

*(Note: The exact number depends on the figure. A common version of this problem uses 20 gulab jamuns shared among 4 children.)*

Total gulab jamuns = 20
BHave they shared equally? Yes/NoShow solution
Yes, they have shared equally — each child gets the same number of gulab jamuns.
CHow many gulab jamuns did each of them get?Show solution
Total gulab jamuns = 20, shared among 4 children.

20÷4=520 \div 4 = 5

Each child got 5 gulab jamuns.

Let us Do — Sharing Activities

AComplete Ritu's art and craft project by drawing 12 bindis equally on 2 ice cream cones as cherries. How many bindis on each cone?Show solution
Given: Total bindis = 12, number of cones = 2.

12÷2=612 \div 2 = 6

Each ice cream cone gets 6 bindis (cherries).

Draw 6 dots on each of the 2 cones.
BPooja has 2 plates with laddoos. Help her divide the laddoos equally in 3 plates. (The 2 plates together have some laddoos — a common version uses 12 laddoos total.)Show solution
Given: Total laddoos on 2 plates = 12 (assumed from standard version of this problem), number of plates to share into = 3.

12÷3=412 \div 3 = 4

Each of the 3 plates gets 4 laddoos.

Draw and colour 4 laddoos on each of the 3 plates.

Let us Make — Division Problems

AEach string has 7 beads. How many strings can we make with 21 beads?Show solution
Given: Total beads = 21, beads per string = 7.

21÷7=321 \div 7 = 3

We can make 3 strings with 21 beads.
BThere are 54 flowers. Join 9 flowers to make 1 bracelet. How many bracelets can we make with 54 flowers?Show solution
Given: Total flowers = 54, flowers per bracelet = 9.

54÷9=654 \div 9 = 6

We can make 6 bracelets with 54 flowers.
CThere are 25 roses. 5 roses can be placed in 1 vase. How many vases are needed for placing 25 roses?Show solution
Given: Total roses = 25, roses per vase = 5.

25÷5=525 \div 5 = 5

5 vases are needed.
DThere are 27 candles. Put them equally in 3 boxes. How many candles will be in each box?Show solution
Given: Total candles = 27, number of boxes = 3.

27÷3=927 \div 3 = 9

There will be 9 candles in each box.
EA tailor puts 6 buttons on one shirt. Here are 30 buttons. On how many shirts can the tailor put buttons?Show solution
Given: Total buttons = 30, buttons per shirt = 6.

30÷6=530 \div 6 = 5

The tailor will be able to put 30 buttons on 5 shirts.
FShare 24 bananas equally among 3 monkeys. How many bananas will each monkey get?Show solution
Given: Total bananas = 24, number of monkeys = 3.

24÷3=824 \div 3 = 8

Each monkey will get 8 bananas.

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Frequently Asked Questions

What are the important topics in Grouping and Sharing (Multiplication and Division) for CBSE Class 2 Mathematics?
Grouping and Sharing (Multiplication and Division) covers several key topics that are frequently asked in CBSE Class 2 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Grouping and Sharing (Multiplication and Division) — CBSE Class 2 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
Where can I get free NCERT Solutions for Grouping and Sharing (Multiplication and Division) Class 2 Mathematics?
This page has free step-by-step NCERT Solutions for every exercise question in Grouping and Sharing (Multiplication and Division) (CBSE Class 2 Mathematics) — written the way examiners award marks: given, formula, working, answer.

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