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NCERT Solutions

Grouping and Sharing (Multiplication and Division) — NCERT Solutions

CBSE · Class 2 · Mathematics

NCERT Solutions for Grouping and Sharing (Multiplication and Division), CBSE Class 2 Mathematics: 32 textbook questions solved step by step.

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32 Questions Solved · 15 Sections

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Let us Do — Bicycles, Autorickshaws and Cars

1There are 4 bicycles. Each bicycle has 2 wheels. Find the total number of wheels.Show solution

Given: Number of bicycles = 4, wheels on each bicycle = 2.

Total wheels = 2+2+2+2=82 + 2 + 2 + 2 = 8

We are adding 2 four times, so: 4×2=84 \times 2 = 8

Total wheels = 8

2Number of autorickshaws = 2. Each auto has 3 wheels. Find the total wheels.Show solution

Given: Number of autorickshaws = 2, wheels on each = 3.

Total wheels = 3+3=63 + 3 = 6

2×3=62 \times 3 = 6

Total wheels = 6

3Let us do it for cars. (There are 7 cars, each with 4 wheels.) Fill in the blanks.Show solution

Given: Number of cars = 7, number of wheels in each car = 4.

Total wheels = 4+4+4+4+4+4+4=284 + 4 + 4 + 4 + 4 + 4 + 4 = 28

We are adding 4 seven times.

7 times 4 is 28

7 groups of 4 is 28

7×4=287 \times 4 = 28

How many fours are you adding? 7

We can write it as: 7 fours are 28.

Let us Do — Butterflies, Octopuses and Soldiers

1Fill in the blanks for butterflies. (There are 3 butterflies, each with 2 wings.)Show solution

Number of butterflies = 3

Number of wings in each butterfly = 2

Total number of wings = 2+2+2=62 + 2 + 2 = 6

or 3 groups of 2 is 6

3 times 2 is 6

3 twos are 6

3×2=63 \times 2 = 6

2Fill in the blanks for octopuses. (There are 2 octopuses, each with 8 legs.)Show solution

Number of octopuses = 2

Number of legs in each octopus = 8

Total number of legs = 8+8=168 + 8 = 16

2 groups of 8 is 16

2 times 8 is 16

2 eights are 16

2×8=162 \times 8 = 16

3Fill in the blanks for soldiers. (There are 4 lines of soldiers, each line has 10 soldiers.)Show solution

Number of lines = 4

Number of soldiers in each line = 10

Total number of soldiers = 10+10+10+10=4010 + 10 + 10 + 10 = 40

4 times 10 is 40

4 tens are 40

4×10=404 \times 10 = 40

Match the Following

1Match each addition expression with its description and value:
- 9+9+99 + 9 + 9
- 5+5+5+5+5+5+55+5+5+5+5+5+5
- 3+3+3+3+33+3+3+3+3
- 10+10+10+1010+10+10+10
- 8+8+88+8+8
- 7+77+7

Descriptions: 7 fives are, 4 groups of 10, 3×93 \times 9, 3×83 \times 8, 2 sevens are, 5 times 3

Values: 27, 35, 40, 14, 15, 24
Show solution

Step 1 — Calculate each sum:

9+9+9=279 + 9 + 9 = 27 → This is 3×93 \times 9 → 27

5+5+5+5+5+5+5=355+5+5+5+5+5+5 = 35 → This is 7 fives are → 35

3+3+3+3+3=153+3+3+3+3 = 15 → This is 5 times 3 → 15

10+10+10+10=4010+10+10+10 = 40 → This is 4 groups of 10 → 40

8+8+8=248+8+8 = 24 → This is 3×83 \times 8 → 24

7+7=147+7 = 14 → This is 2 sevens are → 14

Matches:

  • 9+9+99+9+9 ↔ 3×93 \times 9 ↔ 27
  • 5+5+5+5+5+5+55+5+5+5+5+5+5 ↔ 7 fives are ↔ 35
  • 3+3+3+3+33+3+3+3+3 ↔ 5 times 3 ↔ 15
  • 10+10+10+1010+10+10+10 ↔ 4 groups of 10 ↔ 40
  • 8+8+88+8+8 ↔ 3×83 \times 8 ↔ 24
  • 7+77+7 ↔ 2 sevens are ↔ 14

Complete the Table of 2

1Complete the multiplication table of 2 up to 10.Show solution

Using the pattern: 2×n=n+n2 \times n = n + n

DotsWordsMultiplication
●● ●●2 ones are 22×1=22 \times 1 = 2
●●● ●●●2 twos are 42×2=42 \times 2 = 4
●●●● ●●●●2 threes are 62×3=62 \times 3 = 6
2 fours are 82×4=82 \times 4 = 8
2 fives are 102×5=102 \times 5 = 10
2 sixes are 122×6=122 \times 6 = 12
2 sevens are 142×7=142 \times 7 = 14
2 eights are 162×8=162 \times 8 = 16
2 nines are 182×9=182 \times 9 = 18
2 tens are 202×10=202 \times 10 = 20

Complete the Table of 3

1Complete the multiplication table of 3 up to 10.Show solution

Using the pattern: 3×n=3 \times n = sum of nn threes

WordsMultiplication
3 ones are 33×1=33 \times 1 = 3
3 twos are 63×2=63 \times 2 = 6
3 threes are 93×3=93 \times 3 = 9
3 fours are 123×4=123 \times 4 = 12
3 fives are 153×5=153 \times 5 = 15
3 sixes are 183×6=183 \times 6 = 18
3 sevens are 213×7=213 \times 7 = 21
3 eights are 243×8=243 \times 8 = 24
3 nines are 273×9=273 \times 9 = 27
3 tens are 303×10=303 \times 10 = 30

Complete the Table of 5

1Complete the multiplication table of 5 up to 10.Show solution

Using the pattern: 5×n=5 \times n = sum of nn fives

WordsMultiplication
5 ones are 55×1=55 \times 1 = 5
5 twos are 105×2=105 \times 2 = 10
5 threes are 155×3=155 \times 3 = 15
5 fours are 205×4=205 \times 4 = 20
5 fives are 255×5=255 \times 5 = 25
5 sixes are 305×6=305 \times 6 = 30
5 sevens are 355×7=355 \times 7 = 35
5 eights are 405×8=405 \times 8 = 40
5 nines are 455×9=455 \times 9 = 45
5 tens are 505×10=505 \times 10 = 50

Complete the Table of 10

1Complete the multiplication table of 10 up to 10.Show solution

Using the pattern: 10×n=10 \times n = sum of nn tens

WordsMultiplication
10 ones are 1010×1=1010 \times 1 = 10
10 twos are 2010×2=2010 \times 2 = 20
10 threes are 3010×3=3010 \times 3 = 30
10 fours are 4010×4=4010 \times 4 = 40
10 fives are 5010×5=5010 \times 5 = 50
10 sixes are 6010×6=6010 \times 6 = 60
10 sevens are 7010×7=7010 \times 7 = 70
10 eights are 8010×8=8010 \times 8 = 80
10 nines are 9010×9=9010 \times 9 = 90
10 tens are 10010×10=10010 \times 10 = 100

How Many? — Bouquets and Gulab Jamuns

1Ram made 4 bouquets with 3 flowers each. Gopal made 3 bouquets with 4 flowers each. How many flowers did each use? What do you observe?Show solution

Ram: 4 groups of 3 flowers → 4×3=124 \times 3 = 12 flowers.

Gopal: 3 groups of 4 flowers → 3×4=123 \times 4 = 12 flowers.

Observation: Even though the groups are arranged differently, the total is the same. 4×3=3×4=124 \times 3 = 3 \times 4 = 12. This shows that the order of multiplication does not change the answer (Commutative Property of Multiplication).

2Fill in the blanks:
(i) 4 groups of 5 gulab jamuns: __ times 5 is __, 4×5=4 \times 5 = __, there are __ gulab jamuns.
(ii) 5 groups of 4 gulab jamuns: __ times 4 is __, 5×4=5 \times 4 = __, there are __ gulab jamuns.
Show solution

(i) 4 groups of 5:

4 times 5 is 20

4×5=204 \times 5 = 20

There are 20 gulab jamuns.

(ii) 5 groups of 4:

5 times 4 is 20

5×4=205 \times 4 = 20

There are 20 gulab jamuns.

Observation: 4×5=5×4=204 \times 5 = 5 \times 4 = 20

3Fill in the blanks:
(i) 6 groups of 4 flowers: __ times 4 is __, 6×4=6 \times 4 = __, there are __ flowers.
(ii) 4 groups of 6 flowers: __ times 6 is __, 4×6=4 \times 6 = __, there are __ flowers.
Show solution

(i) 6 groups of 4:

6 times 4 is 24

6×4=246 \times 4 = 24

There are 24 flowers.

(ii) 4 groups of 6:

4 times 6 is 24

4×6=244 \times 6 = 24

There are 24 flowers.

Word Problems — How Many?

AThere are 8 packets of bindis. Each packet has 5 bindis. How many bindis are there in all?Show solution

Given:
Number of packets = 8
Number of bindis in each packet = 5

8 groups of 5 bindis.

8×5=40 bindis8 \times 5 = 40 \text{ bindis}

There are 40 bindis in all.

BBharti puts 4 buttons on each shirt. She wants to put buttons on 7 shirts. How many buttons does she need?Show solution

Given:
Number of shirts = 7
Number of buttons on each shirt = 4

7 groups of 4 buttons.

7×4=28 buttons7 \times 4 = 28 \text{ buttons}

Bharti needs 28 buttons.

CRita bought 6 pencils of ₹4 each. How much money will she give to the shopkeeper?

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DFive people can sit in a car. How many people can sit in 8 such cars?

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Table of 6 from Table of 3

1Make the table of 6 from the table of 3 by completing the given grid:
Table of 3 (top row): 3, 6, ☐, 12, ☐, ☐, 21, ☐, ☐, 30
Second row (Table of 3 again): 3, ☐, 9, ☐, ☐, 18, ☐, 24, ☐, ☐
Table of 6 (bottom row): 6, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐

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Table of 8 from Tables of 2 and 6

1Make the table of 8 from the tables of 2 and 6 by completing the grid:
Table of 2: 2, 4, ☐, ☐, 10, ☐, 14, ☐, 18, 20
Table of 6: 6, ☐, ☐, ☐, ☐, 36, ☐, 48, ☐, ☐
Table of 8: 8, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐, ☐

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Project Work — Arrays with 24 Objects

1Collect 24 small objects. Arrange them in different arrays and write the related multiplication facts.

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Gulab Jamuns

AHow many gulab jamuns were there in total? (Based on the picture showing gulab jamuns shared among children.)

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BHave they shared equally? Yes/No

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CHow many gulab jamuns did each of them get?

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Let us Do — Sharing Activities

AComplete Ritu's art and craft project by drawing 12 bindis equally on 2 ice cream cones as cherries. How many bindis on each cone?

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BPooja has 2 plates with laddoos. Help her divide the laddoos equally in 3 plates. (The 2 plates together have some laddoos — a common version uses 12 laddoos total.)

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Let us Make — Division Problems

AEach string has 7 beads. How many strings can we make with 21 beads?

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BThere are 54 flowers. Join 9 flowers to make 1 bracelet. How many bracelets can we make with 54 flowers?

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CThere are 25 roses. 5 roses can be placed in 1 vase. How many vases are needed for placing 25 roses?

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DThere are 27 candles. Put them equally in 3 boxes. How many candles will be in each box?

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EA tailor puts 6 buttons on one shirt. Here are 30 buttons. On how many shirts can the tailor put buttons?

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FShare 24 bananas equally among 3 monkeys. How many bananas will each monkey get?

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16 more solved questions in Grouping and Sharing (Multiplication and Division)

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Frequently Asked Questions

What are the important topics in Grouping and Sharing (Multiplication and Division) for CBSE Class 2 Mathematics?
Key topics in Grouping and Sharing (Multiplication and Division) include Multiplication as Equal Groups, Tables and Table Patterns, Multiplication Word Problems, Division as Sharing and Making Groups. Study these first, then practise questions on each for Class 2 exams.
Are these NCERT Solutions for Grouping and Sharing (Multiplication and Division) free?
The first 16 of the 32 solutions on this page are open to read. The other 16 are free with a Super Tutor account — signing up is free and needs no card.
How should I revise Grouping and Sharing (Multiplication and Division) for Class 2 exams?
Learn the core ideas first, then work through the 43 practice questions on Grouping and Sharing (Multiplication and Division). Revise definitions regularly and use flashcards for quick recall before the exam.

Sources & Official References

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