Data Through Pictures

Given: A table showing the number of children watching TV for different durations.

Children who watch TV for more than half an hour includes those who watch for 1 hour, 1½ hours, 2 hours, and more than 2 hours.

Since the actual filled values in the table are not visible in the OCR, we note the method:

$$\text{Answer} = \text{(No. of children watching 1 hr)} + \text{(1½ hr)} + \text{(2 hrs)} + \text{(more than 2 hrs)}$$

Add the number of children from all rows except the '½ hour' row to get the answer.

Note: The exact numbers depend on the data filled in the table (not visible in the image). Apply the above method to the given table.

Children who watch TV for less than two hours includes those who watch for ½ hour, 1 hour, and 1½ hours.

$$\text{Answer} = \text{(No. of children watching ½ hr)} + \text{(1 hr)} + \text{(1½ hr)}$$

Add the number of children from the first three rows of the table.

Note: Apply this method to the actual numbers given in your table.

Look at the last row of the table — 'More than 2 hours' — and read the number of children recorded there.

That number is the answer.

Note: Fill in the blank using the value from the 'More than 2 hours' row of your table.

Compare the number of children in the '2 hours' row with the number in the '½ hour' row.

- If the number for '2 hours' $>$ number for '½ hour', the statement is True.
- If the number for '2 hours' $\leq$ number for '½ hour', the statement is False.

Note: Apply this comparison to the actual values in your table to determine True or False.

Given: In the pictograph, each icon (picture) represents 5 items. Scale: 1 icon = 5 items.

Method:
$$\text{Number of toys} = \text{Number of icons in the Toys row} \times 5$$

Count the number of icons shown in the 'Toys' row of the pictograph and multiply by 5.

Note: Since the image is not fully visible, apply the formula above to the number of icons shown in your textbook's pictograph.

Given: Scale: 1 icon = 5 items.

$$\text{Number of board games} = \text{Number of icons in the Board Games row} \times 5$$

Count the icons in the 'Board games' row and multiply by 5.

Note: Apply this to the actual pictograph in your textbook.

Given: Scale: 1 icon = 5 items.

$$\text{Total play items} = (\text{Number of toys}) + (\text{Number of board games}) + (\text{Number of sports items})$$

Step 1: Find the number of each item by multiplying the icons in each row by 5.

Step 2: Add all three values.

$$\text{Total} = (\text{Toys icons} \times 5) + (\text{Board games icons} \times 5) + (\text{Sports items icons} \times 5)$$

Note: Apply this formula to the actual icon counts in your textbook's pictograph.

Given: Scale: 1 icon = 3 two-wheelers.

From the pictograph:
- Monday: Count the icons and multiply by 3.
- Wednesday: Count the icons and multiply by 3.
- Friday: Count the icons and multiply by 3.

From the OCR representation, Friday appears to have the most icons.

$$\textbf{Answer: Friday}$$

Friday had the most two-wheelers passing Deepti's house.

Given: Scale: 1 icon = 3 two-wheelers.

From the pictograph (counting icons from OCR):
- Monday: 7 icons $\Rightarrow 7 \times 3 = 21$ two-wheelers
- Wednesday: 4 icons $\Rightarrow 4 \times 3 = 12$ two-wheelers (approximately, based on OCR)
- Friday: 8 icons $\Rightarrow 8 \times 3 = 24$ two-wheelers

$$\text{Total} = 21 + 12 + 24 = 57 \text{ two-wheelers}$$

Note: Count the exact icons from your textbook's pictograph and apply the same method. The answer may vary based on exact icon count.

Given: Scale: 1 icon = 3 two-wheelers.

$$\text{Fewer two-wheelers} = \text{Two-wheelers on Monday} - \text{Two-wheelers on Wednesday}$$

Using values from Question 2:
$$= 21 - 12 = 9 \text{ two-wheelers}$$

9 fewer two-wheelers were seen on Wednesday than on Monday.

Note: Use the exact icon counts from your textbook for the precise answer.

Given: Scale: 1 icon = 3 two-wheelers.

$$\text{More two-wheelers} = \text{Two-wheelers on Friday} - \text{Two-wheelers on Wednesday}$$

Using values from Question 2:
$$= 24 - 12 = 12 \text{ two-wheelers}$$

12 more two-wheelers were seen on Friday than on Wednesday.

Note: Use the exact icon counts from your textbook for the precise answer.

Given data (approximate):
- Monday: 21 two-wheelers
- Wednesday: 12 two-wheelers
- Friday: 24 two-wheelers

New Scale chosen: 1 icon = 6 two-wheelers

$$\text{Monday: } \frac{21}{6} = 3\frac{1}{2} \text{ icons}$$
$$\text{Wednesday: } \frac{12}{6} = 2 \text{ icons}$$
$$\text{Friday: } \frac{24}{6} = 4 \text{ icons}$$

Pictograph (to be drawn in notebook):

| Day | Number of Two-wheelers (1 icon = 6 two-wheelers) |
|---|---|
| Monday | 🛵🛵🛵½ |
| Wednesday | 🛵🛵 |
| Friday | 🛵🛵🛵🛵 |

A half icon represents 3 two-wheelers (half of 6).

Draw this pictograph neatly in your notebook with the scale clearly mentioned.

Given:
- Raman's table shows: Time spent sleeping = 8 boxes = 8 hours (since 1 box = 1 hour).
- Sheela's bar graph: Read the bar for 'Sleeping' from her graph.

From Raman's table: Sleeping = 8 hours.

Compare with Sheela's bar graph value for sleeping.

If Sheela's sleeping bar shows less than 8 hours, then Raman spends more time sleeping.

Note: Read Sheela's bar graph from your textbook and compare. Based on typical data in this chapter, Raman spends more time sleeping (8 hours).

Given:
- Raman's table: Time in school = 5 boxes = 5 hours.
- Sheela's bar graph: Read the bar for 'School'.

Compare the two values. The one with the higher value spends more hours in school.

Note: Read Sheela's bar for school from your textbook and compare with Raman's 5 hours to determine the answer.