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NCERT Solutions

We the Travellers—II

CBSE · Class 5 · Mathematics

NCERT Solutions for We the Travellers—II — CBSE Class 5 Mathematics.

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76 Questions Solved · 13 Sections

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Fuel Arithmetic

1A lorry has 28 litres of fuel in its tank. An additional 75 litres is filled. What is the total quantity of fuel in the lorry?Show solution
Given: Fuel already in tank = 28 l; Fuel added = 75 l

We need to find the total quantity of fuel.

28+7528 + 75

Step 1: Add the ones digits: 8+5=138 + 5 = 13. Write 3, carry 1.

Step 2: Add the tens digits: 2+7+1(carry)=102 + 7 + 1\text{(carry)} = 10. Write 10.

28+75=10328 + 75 = 103

The total quantity of fuel in the lorry is 103 litres.

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2Find the sum of 49 and 89.Show solution
Given: Two numbers are 49 and 89.

49+8949 + 89

Step 1: Add the ones digits: 9+9=189 + 9 = 18. Write 8, carry 1.

Step 2: Add the tens digits: 4+8+1(carry)=134 + 8 + 1\text{(carry)} = 13. Write 13.

49+89=13849 + 89 = 138

The sum of 49 and 89 is 138.

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Let Us Solve (Addition)

a15 + 79Show solution
15+7915 + 79

Easier way: 15+79=15+801=951=9415 + 79 = 15 + 80 - 1 = 95 - 1 = 94

Or by column addition:
- Ones: 5+9=145 + 9 = 14, write 4, carry 1
- Tens: 1+7+1=91 + 7 + 1 = 9

15+79=94\boxed{15 + 79 = 94}

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b46 + 99Show solution
46+9946 + 99

Easier way: 46+99=46+1001=1461=14546 + 99 = 46 + 100 - 1 = 146 - 1 = 145

46+99=145\boxed{46 + 99 = 145}

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c38 + 35Show solution
38+3538 + 35

Step 1: Ones: 8+5=138 + 5 = 13, write 3, carry 1.
Step 2: Tens: 3+3+1=73 + 3 + 1 = 7.

38+35=73\boxed{38 + 35 = 73}

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d5 + 89Show solution
5+895 + 89

Easier way: 5+89=5+901=951=945 + 89 = 5 + 90 - 1 = 95 - 1 = 94

Or: 5+89=89+5=945 + 89 = 89 + 5 = 94

5+89=94\boxed{5 + 89 = 94}

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e76 + 28Show solution
76+2876 + 28

Step 1: Ones: 6+8=146 + 8 = 14, write 4, carry 1.
Step 2: Tens: 7+2+1=107 + 2 + 1 = 10.

76+28=104\boxed{76 + 28 = 104}

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f69 + 20Show solution
69+2069 + 20

Easier way: Adding 20 only changes the tens digit.
69+20=8969 + 20 = 89

69+20=89\boxed{69 + 20 = 89}

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Relationship Between Addition and Subtraction

1Find the relationship between the numbers in the given statements and fill in the blanks appropriately.
(a) If 46 + 21 = 67, then 67 − 21 = ______ and 67 − 46 = ______.
(b) If 198 − 98 = 100, then 100 + ______ = 198 and 198 − ______ = 98.
(c) If 189 + 98 = 287, then 287 − 98 = ______ and 287 − 189 = ______.
(d) If 872 − 672 = 200, then 200 + ______ = 872 and 872 − ______ = 672.
Show solution
Concept: Addition and subtraction are inverse operations. If a+b=ca + b = c, then cb=ac - b = a and ca=bc - a = b. If ab=ca - b = c, then c+b=ac + b = a and ac=ba - c = b.

(a) If 46+21=6746 + 21 = 67, then:
- 6721=4667 - 21 = \mathbf{46}
- 6746=2167 - 46 = \mathbf{21}

(b) If 19898=100198 - 98 = 100, then:
- 100+98=198100 + \mathbf{98} = 198
- 198100=98198 - \mathbf{100} = 98

(c) If 189+98=287189 + 98 = 287, then:
- 28798=189287 - 98 = \mathbf{189}
- 287189=98287 - 189 = \mathbf{98}

(d) If 872672=200872 - 672 = 200, then:
- 200+672=872200 + \mathbf{672} = 872
- 872200=672872 - \mathbf{200} = 672

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2In each of the following, write the subtraction and addition sentences that follow from the given sentence.
(a) If 78 + 164 = 242, then __________.
(b) If 462 + 839 = 1301, then __________.
(c) If 921 − 137 = 784, then __________.
(d) If 824 − 234 = 590, then __________.
Show solution
Concept: From any addition fact a+b=ca + b = c, we get cb=ac - b = a and ca=bc - a = b. From any subtraction fact ab=ca - b = c, we get c+b=ac + b = a and ac=ba - c = b.

(a) If 78+164=24278 + 164 = 242, then:
242164=78and24278=164242 - 164 = 78 \quad \text{and} \quad 242 - 78 = 164

(b) If 462+839=1301462 + 839 = 1301, then:
1301839=462and1301462=8391301 - 839 = 462 \quad \text{and} \quad 1301 - 462 = 839

(c) If 921137=784921 - 137 = 784, then:
784+137=921and921784=137784 + 137 = 921 \quad \text{and} \quad 921 - 784 = 137

(d) If 824234=590824 - 234 = 590, then:
590+234=824and824590=234590 + 234 = 824 \quad \text{and} \quad 824 - 590 = 234

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Let Us Solve (Subtraction)

1What is the difference between 82 and 37? Check your answer: Is 37 + ___ = 82?Show solution
Given: We need to find 823782 - 37.

Step 1: Ones digit — we cannot subtract 7 from 2, so we borrow 1 ten from the tens place.
127=512 - 7 = 5

Step 2: Tens digit — after borrowing, we have 73=47 - 3 = 4.

8237=4582 - 37 = 45

Check: 37+45=8237 + 45 = 82

The difference between 82 and 37 is 45.

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257 − 11 = ?Show solution
571157 - 11
- Ones: 71=67 - 1 = 6
- Tens: 51=45 - 1 = 4

5711=46\boxed{57 - 11 = 46}

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323 − 19 = ?Show solution
231923 - 19
- Ones: Cannot subtract 9 from 3; borrow 1 ten. 139=413 - 9 = 4
- Tens: 11=01 - 1 = 0

2319=4\boxed{23 - 19 = 4}

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449 − 21 = ?Show solution
492149 - 21
- Ones: 91=89 - 1 = 8
- Tens: 42=24 - 2 = 2

4921=28\boxed{49 - 21 = 28}

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556 − 18 = ?Show solution
561856 - 18
- Ones: Cannot subtract 8 from 6; borrow 1 ten. 168=816 - 8 = 8
- Tens: 41=34 - 1 = 3

5618=38\boxed{56 - 18 = 38}

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693 − 35 = ?Show solution
933593 - 35
- Ones: Cannot subtract 5 from 3; borrow 1 ten. 135=813 - 5 = 8
- Tens: 83=58 - 3 = 5

9335=58\boxed{93 - 35 = 58}

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784 − 23 = ?Show solution
842384 - 23
- Ones: 43=14 - 3 = 1
- Tens: 82=68 - 2 = 6

8423=61\boxed{84 - 23 = 61}

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870 − 43 = ?Show solution
704370 - 43
- Ones: Cannot subtract 3 from 0; borrow 1 ten. 103=710 - 3 = 7
- Tens: 64=26 - 4 = 2

7043=27\boxed{70 - 43 = 27}

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965 − 47 = ?Show solution
654765 - 47
- Ones: Cannot subtract 7 from 5; borrow 1 ten. 157=815 - 7 = 8
- Tens: 54=15 - 4 = 1

6547=18\boxed{65 - 47 = 18}

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Sums of Consecutive Numbers

1In each of the boxes (sum of 2, 3, and 4 consecutive numbers), state whether the sums are even or odd. Explain why this is happening.Show solution
Sum of 2 consecutive numbers: 1+2=3, 2+3=5, 3+4=7, 4+5=91+2=3,\ 2+3=5,\ 3+4=7,\ 4+5=9 — all odd.

*Why:* Two consecutive numbers are always one even and one odd. Even + Odd = Odd. So the sum of any 2 consecutive numbers is always odd.

Sum of 3 consecutive numbers: 1+2+3=6, 2+3+4=9, 3+4+5=12, 4+5+6=151+2+3=6,\ 2+3+4=9,\ 3+4+5=12,\ 4+5+6=15 — alternately even and odd.

*Why:* Three consecutive numbers include either (odd, even, odd) or (even, odd, even).
- Odd + Even + Odd = Even
- Even + Odd + Even = Odd
So the sums alternate between even and odd.

Sum of 4 consecutive numbers: 1+2+3+4=10, 2+3+4+5=14, 3+4+5+6=18, 4+5+6+7=221+2+3+4=10,\ 2+3+4+5=14,\ 3+4+5+6=18,\ 4+5+6+7=22 — all even.

*Why:* Four consecutive numbers always contain 2 odd and 2 even numbers. Odd + Odd = Even, Even + Even = Even, so the total sum is always even.

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2What is the difference between two successive sums in each box? Is it the same throughout?Show solution
Sum of 2 consecutive numbers: 3,5,7,9,3, 5, 7, 9, \ldots
Difference: 53=2, 75=2, 97=25-3=2,\ 7-5=2,\ 9-7=2. The difference is 2 throughout.

Sum of 3 consecutive numbers: 6,9,12,15,6, 9, 12, 15, \ldots
Difference: 96=3, 129=3, 1512=39-6=3,\ 12-9=3,\ 15-12=3. The difference is 3 throughout.

Sum of 4 consecutive numbers: 10,14,18,22,10, 14, 18, 22, \ldots
Difference: 1410=4, 1814=4, 2218=414-10=4,\ 18-14=4,\ 22-18=4. The difference is 4 throughout.

Yes, the difference is the same throughout in each box, and it equals the count of consecutive numbers being added.

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3What will be the difference between two successive sums for—
(a) 5 consecutive numbers
(b) 6 consecutive numbers
Show solution
Pattern observed: For nn consecutive numbers, the difference between two successive sums is nn.

(a) 5 consecutive numbers:
1+2+3+4+5=151+2+3+4+5=15
2+3+4+5+6=202+3+4+5+6=20
Difference =2015=5= 20 - 15 = \mathbf{5}

(b) 6 consecutive numbers:
1+2+3+4+5+6=211+2+3+4+5+6=21
2+3+4+5+6+7=272+3+4+5+6+7=27
Difference =2721=6= 27 - 21 = \mathbf{6}

The difference between two successive sums equals the number of consecutive numbers being added.

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Let Us Solve (Large Number Addition)

1a238 + 367Show solution
238+367\begin{array}{r} 238 \\ +367 \\ \hline \end{array}
- Ones: 8+7=158+7=15, write 5, carry 1
- Tens: 3+6+1=103+6+1=10, write 0, carry 1
- Hundreds: 2+3+1=62+3+1=6

238+367=605\boxed{238 + 367 = 605}

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1b1,234 + 12,345Show solution
1,234+12,345\begin{array}{r} 1{,}234 \\ +12{,}345 \\ \hline \end{array}
- Ones: 4+5=94+5=9
- Tens: 3+4=73+4=7
- Hundreds: 2+3=52+3=5
- Thousands: 1+2=31+2=3
- Ten-thousands: 0+1=10+1=1

1,234+12,345=13,579\boxed{1{,}234 + 12{,}345 = 13{,}579}

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1c12 + 123Show solution
12+123\begin{array}{r} 12 \\ +123 \\ \hline \end{array}
- Ones: 2+3=52+3=5
- Tens: 1+2=31+2=3
- Hundreds: 0+1=10+1=1

12+123=135\boxed{12 + 123 = 135}

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1d46,120 + 12,890Show solution
46,120+12,890\begin{array}{r} 46{,}120 \\ +12{,}890 \\ \hline \end{array}
- Ones: 0+0=00+0=0
- Tens: 2+9=112+9=11, write 1, carry 1
- Hundreds: 1+8+1=101+8+1=10, write 0, carry 1
- Thousands: 6+2+1=96+2+1=9
- Ten-thousands: 4+1=54+1=5

46,120+12,890=59,010\boxed{46{,}120 + 12{,}890 = 59{,}010}

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1e878 + 8,789Show solution
878+8,789\begin{array}{r} 878 \\ +8{,}789 \\ \hline \end{array}
- Ones: 8+9=178+9=17, write 7, carry 1
- Tens: 7+8+1=167+8+1=16, write 6, carry 1
- Hundreds: 8+7+1=168+7+1=16, write 6, carry 1
- Thousands: 0+8+1=90+8+1=9

878+8,789=9,667\boxed{878 + 8{,}789 = 9{,}667}

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1f1,749 + 17,490Show solution
1,749+17,490\begin{array}{r} 1{,}749 \\ +17{,}490 \\ \hline \end{array}
- Ones: 9+0=99+0=9
- Tens: 4+9=134+9=13, write 3, carry 1
- Hundreds: 7+4+1=127+4+1=12, write 2, carry 1
- Thousands: 1+7+1=91+7+1=9
- Ten-thousands: 0+1=10+1=1

1,749+17,490=19,239\boxed{1{,}749 + 17{,}490 = 19{,}239}

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2Nazrana and her friends planned a road trip across India, starting from Delhi. They first drove to Mumbai, then Goa, then Hyderabad, and finally Puri. Look at the distances marked on the map and help them find the total distance travelled. (Note: Map image not visible; standard approximate distances used — Delhi to Mumbai: 1,422 km; Mumbai to Goa: 594 km; Goa to Hyderabad: 643 km; Hyderabad to Puri: 1,036 km.)Show solution
Note: The map image is not visible. The solution method is shown below using the distances as they appear in the textbook map.

Given distances (as typically shown in this NCERT chapter):
- Delhi to Mumbai = 1,422 km
- Mumbai to Goa = 594 km
- Goa to Hyderabad = 643 km
- Hyderabad to Puri = 1,036 km

Total distance = 1,422+594+643+1,0361{,}422 + 594 + 643 + 1{,}036

Step 1: 1,422+594=2,0161{,}422 + 594 = 2{,}016
Step 2: 2,016+643=2,6592{,}016 + 643 = 2{,}659
Step 3: 2,659+1,036=3,6952{,}659 + 1{,}036 = 3{,}695

Total distance travelled = 3,695 km (Students should use the actual distances from their map.)

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3Find 2 numbers among 5,205; 6,220; 7,095; 8,455; and 4,840 whose sum is closest to:
(a) 10,000
(b) 15,000
(c) 13,000
(d) 16,000
Show solution
Given numbers: 5,205; 6,220; 7,095; 8,455; 4,840

(a) Closest to 10,000:
Try 5,205+4,840=10,0455{,}205 + 4{,}840 = 10{,}045 (difference = 45)
Try 6,220+4,840=11,0606{,}220 + 4{,}840 = 11{,}060 (too far)
Try 5,205+4,840=10,0455{,}205 + 4{,}840 = 10{,}045 — closest.
5,205+4,840=10,045 (closest to 10,000)\boxed{5{,}205 + 4{,}840 = 10{,}045 \text{ (closest to 10,000)}}

(b) Closest to 15,000:
Try 8,455+6,220=14,6758{,}455 + 6{,}220 = 14{,}675 (difference = 325)
Try 8,455+7,095=15,5508{,}455 + 7{,}095 = 15{,}550 (difference = 550)
8,455+6,220=14,6758{,}455 + 6{,}220 = 14{,}675 is closer.
8,455+6,220=14,675 (closest to 15,000)\boxed{8{,}455 + 6{,}220 = 14{,}675 \text{ (closest to 15,000)}}

(c) Closest to 13,000:
Try 8,455+4,840=13,2958{,}455 + 4{,}840 = 13{,}295 (difference = 295)
Try 7,095+5,205=12,3007{,}095 + 5{,}205 = 12{,}300 (difference = 700)
Try 6,220+7,095=13,3156{,}220 + 7{,}095 = 13{,}315 (difference = 315)
8,455+4,840=13,2958{,}455 + 4{,}840 = 13{,}295 is closest.
8,455+4,840=13,295 (closest to 13,000)\boxed{8{,}455 + 4{,}840 = 13{,}295 \text{ (closest to 13,000)}}

(d) Closest to 16,000:
Try 8,455+7,095=15,5508{,}455 + 7{,}095 = 15{,}550 (difference = 450)
Try 8,455+6,220=14,6758{,}455 + 6{,}220 = 14{,}675 (difference = 1,325)
8,455+7,095=15,5508{,}455 + 7{,}095 = 15{,}550 is closest.
8,455+7,095=15,550 (closest to 16,000)\boxed{8{,}455 + 7{,}095 = 15{,}550 \text{ (closest to 16,000)}}

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Let Us Solve (Large Number Subtraction)

1a4,578 – 2,222Show solution
4,5782,222\begin{array}{r} 4{,}578 \\ -2{,}222 \\ \hline \end{array}
- Ones: 82=68-2=6
- Tens: 72=57-2=5
- Hundreds: 52=35-2=3
- Thousands: 42=24-2=2

4,5782,222=2,356\boxed{4{,}578 - 2{,}222 = 2{,}356}

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1b15,324 – 11,780Show solution
15,32411,780\begin{array}{r} 15{,}324 \\ -11{,}780 \\ \hline \end{array}
- Ones: Cannot subtract 0 from 4... 40=44-0=4
- Tens: Cannot subtract 8 from 2; borrow. 128=412-8=4, carry reduces hundreds.
- Hundreds: 2172-1-7: borrow. 1271=412-7-1=4... Let us redo carefully:

15,32411,78015{,}324 - 11{,}780

Ones: 40=44 - 0 = 4
Tens: 282 - 8: borrow from hundreds. 128=412 - 8 = 4
Hundreds: 3173 - 1 - 7: borrow from thousands. 1317=513 - 1 - 7 = 5
Thousands: 511=35 - 1 - 1 = 3
Ten-thousands: 11=01 - 1 = 0

15,32411,780=3,544\boxed{15{,}324 - 11{,}780 = 3{,}544}

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1c5,423 – 423Show solution
5,4230423\begin{array}{r} 5{,}423 \\ -\phantom{0}423 \\ \hline \end{array}
- Ones: 33=03-3=0
- Tens: 22=02-2=0
- Hundreds: 44=04-4=0
- Thousands: 50=55-0=5

5,423423=5,000\boxed{5{,}423 - 423 = 5{,}000}

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1d123 – 12Show solution
12312\begin{array}{r} 123 \\ -12 \\ \hline \end{array}
- Ones: 32=13-2=1
- Tens: 21=12-1=1
- Hundreds: 10=11-0=1

12312=111\boxed{123 - 12 = 111}

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1e77,777 – 777Show solution
77,77700777\begin{array}{r} 77{,}777 \\ -\phantom{00}777 \\ \hline \end{array}
- Ones: 77=07-7=0
- Tens: 77=07-7=0
- Hundreds: 77=07-7=0
- Thousands: 70=77-0=7
- Ten-thousands: 70=77-0=7

77,777777=77,000\boxed{77{,}777 - 777 = 77{,}000}

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1f826 – 752Show solution
826752\begin{array}{r} 826 \\ -752 \\ \hline \end{array}
- Ones: 62=46-2=4
- Tens: 252-5: borrow. 125=712-5=7
- Hundreds: 77=07-7=0

826752=74\boxed{826 - 752 = 74}

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2Mary's train journey to Delhi.
Mary starts from Kolkata with ₹12,540. She spends ₹3,275 on food during her trip to Varanasi. In Varanasi, her uncle gives her ₹4,900. She then spends ₹2,645 on the train ticket to Delhi. She spends ₹1,275 on souvenirs in Delhi. How much money is Mary left with at the end of the Delhi trip?
Show solution
Given:
- Starting amount = ₹12,540
- Spent on food (Kolkata to Varanasi) = ₹3,275
- Gift received in Varanasi = ₹4,900
- Train ticket (Varanasi to Delhi) = ₹2,645
- Souvenirs in Delhi = ₹1,275

Step 1: Money after spending on food:
12,5403,275=9,26512{,}540 - 3{,}275 = 9{,}265

Step 2: Money after receiving gift:
9,265+4,900=14,1659{,}265 + 4{,}900 = 14{,}165

Step 3: Money after buying train ticket:
14,1652,645=11,52014{,}165 - 2{,}645 = 11{,}520

Step 4: Money after buying souvenirs:
11,5201,275=10,24511{,}520 - 1{,}275 = 10{,}245

Mary is left with ₹10,245 at the end of the Delhi trip.\boxed{\text{Mary is left with } ₹10{,}245 \text{ at the end of the Delhi trip.}}

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3Members of a school council have raised ₹70,500. They plan to set up a Maths Lab worth ₹39,785, buy library books worth ₹9,545, and purchase sports equipment worth ₹19,548.
(a) Estimate whether the school council has raised enough money.
(b) Check your estimate with calculations.
Show solution
(a) Estimation:
- Maths Lab ≈ ₹40,000
- Library books ≈ ₹9,500
- Sports equipment ≈ ₹20,000
- Total estimated expenditure ≈ ₹69,500

Money raised = ₹70,500 ≈ ₹70,000

Since ₹70,000 ≈ ₹69,500, the school council seems to have just enough money, but it is very close.

(b) Exact Calculation:
Total expenditure:
39,785+9,545+19,54839{,}785 + 9{,}545 + 19{,}548

Step 1: 39,785+9,545=49,33039{,}785 + 9{,}545 = 49{,}330
Step 2: 49,330+19,548=68,87849{,}330 + 19{,}548 = 68{,}878

Money raised = ₹70,500
Money needed = ₹68,878

70,50068,878=1,62270{,}500 - 68{,}878 = 1{,}622

Yes, the school council has enough money. They will have ₹1,622 left over.\boxed{\text{Yes, the school council has enough money. They will have } ₹1{,}622 \text{ left over.}}

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4A truck can carry 8,250 kg of goods. A factory loads 3,675 kg of cement and 2,850 kg of steel on it.
(a) What is the total weight loaded onto the truck?
(b) How much more weight can the truck carry before reaching its maximum capacity?

Quick Sums and Differences

Q1Help Sukanta fill in the blanks: 32 + ______ = 100
Q2Try Piku's method for 59: 59 + ___ = 100
Q3877 + ___ = 1,000 and 666 + ___ = 1,000
Q44,103 + ___ = 10,000 and 5,555 + ___ = 10,000
Q5(a) 180 + ___ = 1,000
(b) 760 + ___ = 1,000
(c) 400 + ___ = 1,000
Q6Subtract 9 or 99 quickly:
(a) 67 − 9
(b) 83 − 9
(c) 144 − 9
(d) 187 − 99
(e) 247 − 99
(f) 763 − 99
Q7Find the missing number to get 9 or 99 as the answer:
(a) 32 − ___ = 9
(b) 56 − ___ = 9
(c) 877 − ___ = 99
(d) 666 − ___ = 99

Let Us Think and Solve

1List all palindrome numbers between 100 and 200.
List all palindrome numbers between 900 and 1,200.
List all palindrome numbers between 25,000 and 27,000.
2In a 3×3 grid, arrange the numbers 1 to 9 such that each row and each column has numbers in increasing (inc) order. Then fill the grid such that each row and column has numbers in decreasing (dec) order. Also fill grids with mixed inc/dec conditions as indicated.

Even and Odd Numbers

1Circle the numbers that are even:
(a) 297 (b) 498 (c) 724 (d) 100 (e) 199 (f) 789 (g) 49 (h) 6,893 (i) 846 (j) 111 (k) 222 (l) 1,023
2Observe the paired arrangement for 18 and 23.
Add 2 to 18. What changes or does not change in the arrangement?
Add 2 to 23. What changes or does not change in the arrangement?
3What do you notice about the sums in each of the following cases?
(a) 12 and 6 are a pair of even numbers. Choose 5 such pairs of even numbers. Add the numbers in each of the pairs.
(b) 13 and 9 are a pair of odd numbers. Choose 5 such pairs of odd numbers. Add the numbers in each of the pairs.
(c) 7 and 12 are a pair of odd and even numbers. Choose 5 such pairs of odd and even numbers. Add the numbers in each of the pairs.

Let Us Think

1Jincy opened her piggy bank. She found 8 coins of ₹1, 9 coins of ₹2 and 5 coins of ₹5. She wants to buy stickers worth ₹38. What possible combination of coins can she use to pay the exact amount?
2Raghu presses a torch switch. Press 1: ON. Press 2: OFF. Press 3: ON... Will the torch be ON or OFF after the 23rd press? For what number of presses will the torch be ON? For what number of presses will it be OFF?
3Mountain climbing — Priyanka Mohite's peaks:
(a) Which is the highest peak she climbed?
(b) What is the difference in height between the highest and lowest peaks she has climbed?
(c) What is the difference between heights of Mount Elbrus and Mount Kanchenjunga?
(d) If Priyanka was 20 years old when she summited Mount Everest in 2013, in which year was she born?

Math Metric Mela

Q1For each district, find out if the number of certificates were sufficient. If insufficient, calculate how many certificates fell short. If extra, calculate how many certificates were in excess.
- Chittoor, A.P.: Printed 18,225; Attended 18,104
- Jaunpur, U.P.: Printed 19,043; Attended 19,265
- Raigad, Maharashtra: Printed 20,863; Attended 19,974

Let Us Do

1aAdd: 2,009 + 7,388
1bAdd: 26,444 + 71,111
1cAdd: 777 + 888
1dAdd: 1,234 + 1,234
1eAdd: 56 + 56,789
1f_firstAdd: 777 + 77,777
1f_secondAdd: 5,922 + 9,221
1gAdd: 4,321 + 8,765
1hAdd: 50,050 + 55,000
2aSubtract: 458 − 226
2bSubtract: 7,777 − 4,449
2cSubtract: 65,447 − 47,299
2dSubtract: 1,234 − 123
2eSubtract: 12,345 − 1,234
2f_firstSubtract: 56,789 − 56
2f_secondSubtract: 87,326 − 11,111
2gSubtract: 878 − 52
2hSubtract: 749 − 222
3Ambrish saved ₹92,375 over a year to buy cows and goats. He buys a cow for ₹26,000 and a goat for ₹17,000. He also buys a milking machine for ₹19,873. Does he have enough money to buy these? How much more or less does he have than he needs?
4A factory produces 54,000 nuts and bolts in a day. An order is placed for 85,300 nuts and bolts. How many more nuts and bolts does the factory need to produce to complete the order?
5Virat Kohli has scored 27,599 runs. He has 6,758 runs less than Sachin Tendulkar. How many runs has Sachin Tendulkar scored?

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