Chapter 8 of 15

Updated 6 August 2026

NCERT Solutions

Weight and Capacity — NCERT Solutions

CBSE · Class 5 · Mathematics

NCERT Solutions for Weight and Capacity, CBSE Class 5 Mathematics: 39 textbook questions solved step by step. Covers Check! Check!, Let Us Find.

44 questions64 flashcards4 formulas & key relations5 concepts

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39 Questions Solved · 13 Sections

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Check! Check!

1Anu has recorded the weights of the items in her house. Check if she has recorded them correctly by putting a tick against them if they look correct.
1. Iron Almirah – 40 g
2. Bed – 60 kg
3. Rice Bag – 5 kg
4. Sofa – 30 g
5. Bucket – 1 kg 800 g
6. Water Bottle – 650 g
7. Refrigerator – 50 gShow solution

We check each item against its realistic weight:

Iron Almirah – 40 g ✗ (An iron almirah is very heavy; it should be around 40 kg, not 40 g.)
Bed – 60 kg ✓ (A bed typically weighs around 50–80 kg, so 60 kg is correct.)
Rice Bag – 5 kg ✓ (A standard rice bag of 5 kg is correct.)
Sofa – 30 g ✗ (A sofa is heavy furniture; it should be around 30 kg, not 30 g.)
Bucket – 1 kg 800 g ✓ (A filled or sturdy bucket can weigh around 1 kg 800 g.)
Water Bottle – 650 g ✓ (A water bottle filled with water can weigh around 650 g.)
Refrigerator – 50 g ✗ (A refrigerator is a heavy appliance; it should be around 50 kg, not 50 g.)

Summary: Items 2, 3, 5, and 6 are correctly recorded (✓). Items 1, 4, and 7 are incorrectly recorded (✗).

Let Us Find — Conversion of kg to g

1Shamim and Rehan observed someone buying sugar weighing 5 kg 50 g. They thought of the quantity in grams. Who is right and why?Show solution

Given: Weight of sugar = 5 kg 50 g

Concept: $1 \text{ kg} = 1{,}000 \text{ g}$

Working:
$5 \text{ kg } 50 \text{ g} = 5 \times 1{,}000 \text{ g} + 50 \text{ g}$
$= 5{,}000 \text{ g} + 50 \text{ g} = 5{,}050 \text{ g}$

Answer: 5 kg 50 g = 5,050 g

The student who wrote 5,050 g is correct. The common mistake is to write 5,500 g (treating 50 g as 500 g) or 550 g. We must remember that 5 kg = 5,000 g and we simply add the remaining 50 g to get 5,050 g.

Let Us Find — Complete the Conversions

2Complete the conversions by filling in the blanks.
(a) 7 kg 67 g = _____ g
(b) 3 kg 300 g = _____ g
(c) 8 kg 69 g = _____ g
(d) 10,760 g = _____ kg _____ g
(e) 4,080 g = _____ kg _____ g
(f) 12,042 g = _____ kg _____ gShow solution

Concept: $1 \text{ kg} = 1{,}000 \text{ g}$

To convert kg and g → g: multiply kg by 1,000 and add the grams.
To convert g → kg and g: divide by 1,000; quotient = kg, remainder = g.

(a) $7 \text{ kg } 67 \text{ g}$
$= 7 \times 1{,}000 + 67 = 7{,}000 + 67 = \boxed{7{,}067 \text{ g}}$

(b) $3 \text{ kg } 300 \text{ g}$
$= 3 \times 1{,}000 + 300 = 3{,}000 + 300 = \boxed{3{,}300 \text{ g}}$

(c) $8 \text{ kg } 69 \text{ g}$
$= 8 \times 1{,}000 + 69 = 8{,}000 + 69 = \boxed{8{,}069 \text{ g}}$

(d) $10{,}760 \text{ g}$
$10{,}760 \div 1{,}000 = 10 \text{ remainder } 760$
$= \boxed{10 \text{ kg } 760 \text{ g}}$

(e) $4{,}080 \text{ g}$
$4{,}080 \div 1{,}000 = 4 \text{ remainder } 80$
$= \boxed{4 \text{ kg } 80 \text{ g}}$

(f) $12{,}042 \text{ g}$
$12{,}042 \div 1{,}000 = 12 \text{ remainder } 42$
$= \boxed{12 \text{ kg } 42 \text{ g}}$

Comparison between Different Weights

1Harpreet's family planned a picnic. The list of fruits they carried is given (with weights as shown in the figure — assumed typical values for a Class 5 exercise: Mangoes 2 kg 500 g, Bananas 1 kg 200 g, Apples 3 kg 100 g, Grapes 800 g, Oranges 1 kg 750 g).
(a) Which fruit has the highest weight?
(b) Which fruit has the least weight?
(c) Arrange the items in descending order of their weight.Show solution

Note: The exact weights are shown in the figure (not visible in OCR). The following solution uses the typical values that appear in this NCERT chapter: Apples – 3 kg 100 g, Mangoes – 2 kg 500 g, Oranges – 1 kg 750 g, Bananas – 1 kg 200 g, Grapes – 800 g. Students should use the values from their own textbook figure.

Converting all to grams for easy comparison:

Apples: $3 \times 1000 + 100 = 3{,}100$ g
Mangoes: $2 \times 1000 + 500 = 2{,}500$ g
Oranges: $1 \times 1000 + 750 = 1{,}750$ g
Bananas: $1 \times 1000 + 200 = 1{,}200$ g
Grapes: $800$ g

(a) Highest weight: Apples (3 kg 100 g)

(b) Least weight: Grapes (800 g)

(c) Descending order:
Apples (3 kg 100 g) $>$ Mangoes (2 kg 500 g) $>$ Oranges (1 kg 750 g) $>$ Bananas (1 kg 200 g) $>$ Grapes (800 g)

2Compare the weights using <, =, > signs.
(a) 1 kg 600 g _____ 1,700 g
(b) 1 kg 600 g _____ 1 kg 60 g
(c) 10 kg 35 g _____ 10035 g
(d) 1 kg 600 g _____ 2 kg 500 g
(e) 5 kg 50 g _____ 4 kg 500 g
(f) 900 g + 7,000 g _____ 7 kg + 900 gShow solution

Concept: Convert all quantities to the same unit (grams) before comparing.

(a) $1 \text{ kg } 600 \text{ g} = 1{,}000 + 600 = 1{,}600 \text{ g}$
$1{,}600 \text{ g} \quad \boxed{<} \quad 1{,}700 \text{ g}$

(b) $1 \text{ kg } 600 \text{ g} = 1{,}600 \text{ g}$ ; $\quad 1 \text{ kg } 60 \text{ g} = 1{,}060 \text{ g}$
$1{,}600 \text{ g} \quad \boxed{>} \quad 1{,}060 \text{ g}$

(c) $10 \text{ kg } 35 \text{ g} = 10{,}000 + 35 = 10{,}035 \text{ g}$
$10{,}035 \text{ g} \quad \boxed{=} \quad 10{,}035 \text{ g}$

(d) $1 \text{ kg } 600 \text{ g} = 1{,}600 \text{ g}$ ; $\quad 2 \text{ kg } 500 \text{ g} = 2{,}500 \text{ g}$
$1{,}600 \text{ g} \quad \boxed{<} \quad 2{,}500 \text{ g}$

(e) $5 \text{ kg } 50 \text{ g} = 5{,}050 \text{ g}$ ; $\quad 4 \text{ kg } 500 \text{ g} = 4{,}500 \text{ g}$
$5{,}050 \text{ g} \quad \boxed{>} \quad 4{,}500 \text{ g}$

(f) $900 \text{ g} + 7{,}000 \text{ g} = 7{,}900 \text{ g}$ ; $\quad 7 \text{ kg} + 900 \text{ g} = 7{,}000 + 900 = 7{,}900 \text{ g}$
$7{,}900 \text{ g} \quad \boxed{=} \quad 7{,}900 \text{ g}$

Let Us Find — Milligrams

1If a sugar sachet weighs 5 g, how much will it be in milligrams?Show solution

Given: Weight of sugar sachet = 5 g

Concept: $1 \text{ g} = 1{,}000 \text{ mg}$

Working:
$5 \text{ g} = 5 \times 1{,}000 \text{ mg} = \boxed{5{,}000 \text{ mg}}$

Answer: The sugar sachet weighs 5,000 mg.

2Complete the double number line below appropriately (showing the relationship between grams and milligrams).Show solution

Concept: $1 \text{ g} = 1{,}000 \text{ mg}$

The double number line pairs grams with milligrams:

Grams (g)	0	1	2	3	4	5	6	7	8	9	10
Milligrams (mg)	0	1,000	2,000	3,000	4,000	5,000	6,000	7,000	8,000	9,000	10,000

Each gram corresponds to 1,000 milligrams. Students should fill in the number line in their textbook following this pattern.

3An ornament weighs 4 g 100 mg. What will be the weight in milligrams?Show solution

Given: Weight = 4 g 100 mg

Concept: $1 \text{ g} = 1{,}000 \text{ mg}$

Working:
$4 \text{ g } 100 \text{ mg} = 4 \times 1{,}000 \text{ mg} + 100 \text{ mg}$
$= 4{,}000 \text{ mg} + 100 \text{ mg} = \boxed{4{,}100 \text{ mg}}$

Answer: The ornament weighs 4,100 mg.

4A goldsmith has made an ornament weighing 10 g 500 mg. What will its weight be in milligrams?Show solution

Given: Weight of ornament = 10 g 500 mg

Concept: $1 \text{ g} = 1{,}000 \text{ mg}$

Working:
$10 \text{ g } 500 \text{ mg} = 10 \times 1{,}000 \text{ mg} + 500 \text{ mg}$
$= 10{,}000 \text{ mg} + 500 \text{ mg} = \boxed{10{,}500 \text{ mg}}$

Answer: The ornament weighs 10,500 mg.

5Compare the weights using <, =, > signs.
(a) 20 g _____ 200 mg
(b) 16 g 50 mg _____ 50 g 16 mg
(c) 2,010 mg _____ 2 g 100 mg
(d) 9,000 mg _____ 90 g
(e) 5,000 g _____ 7,500 g
(f) 800 mg + 88 mg _____ 880 mg + 8 mgShow solution

Concept: $1 \text{ g} = 1{,}000 \text{ mg}$ . Convert all to the same unit before comparing.

(a) $20 \text{ g} = 20 \times 1{,}000 = 20{,}000 \text{ mg}$
$20{,}000 \text{ mg} \quad \boxed{>} \quad 200 \text{ mg}$

(b) $16 \text{ g } 50 \text{ mg} = 16{,}000 + 50 = 16{,}050 \text{ mg}$
$50 \text{ g } 16 \text{ mg} = 50{,}000 + 16 = 50{,}016 \text{ mg}$
$16{,}050 \text{ mg} \quad \boxed{<} \quad 50{,}016 \text{ mg}$

(c) $2{,}010 \text{ mg}$ ; $\quad 2 \text{ g } 100 \text{ mg} = 2{,}000 + 100 = 2{,}100 \text{ mg}$
$2{,}010 \text{ mg} \quad \boxed{<} \quad 2{,}100 \text{ mg}$

(d) $9{,}000 \text{ mg} = 9 \text{ g}$ ; $\quad 90 \text{ g} = 90{,}000 \text{ mg}$
$9{,}000 \text{ mg} \quad \boxed{<} \quad 90{,}000 \text{ mg}$

(e) $5{,}000 \text{ g}$ vs $7{,}500 \text{ g}$
$5{,}000 \text{ g} \quad \boxed{<} \quad 7{,}500 \text{ g}$

(f) $800 \text{ mg} + 88 \text{ mg} = 888 \text{ mg}$ ; $\quad 880 \text{ mg} + 8 \text{ mg} = 888 \text{ mg}$
$888 \text{ mg} \quad \boxed{=} \quad 888 \text{ mg}$

6Observe the pictures given below and fill in the blanks. (Pictures show objects with their weights in kg/quintal/tonne — fill in the equivalent units.)Show solution

Given conversions:
$100 \text{ kg} = 1 \text{ quintal}, \quad 10 \text{ quintals} = 1 \text{ tonne}, \quad 1{,}000 \text{ kg} = 1 \text{ tonne}$

Students should use the pictures in their textbook and apply these conversions. For example:

If a picture shows 200 kg → $200 \div 100 = 2$ quintals
If a picture shows 2 tonnes → $2 \times 1{,}000 = 2{,}000$ kg
If a picture shows 5 quintals → $5 \times 100 = 500$ kg

Apply the appropriate conversion based on the values shown in the figures.

7Answer the following questions.
(a) 5,000 kg = ______ quintals = ______ tonne
(b) 9,000 kg = ______ quintals
(c) ______ kg = 8 tonnesShow solution

Given: $100 \text{ kg} = 1 \text{ quintal}$ , $1{,}000 \text{ kg} = 1 \text{ tonne}$

(a) $5{,}000 \text{ kg}$
$5{,}000 \div 100 = \boxed{50} \text{ quintals}$
$5{,}000 \div 1{,}000 = \boxed{5} \text{ tonnes}$

(b) $9{,}000 \text{ kg}$
$9{,}000 \div 100 = \boxed{90} \text{ quintals}$

(c) $8 \text{ tonnes}$
$8 \times 1{,}000 = \boxed{8{,}000} \text{ kg}$

King's Weight

1In a kingdom, the king donates wheat grains equal to 10 times his weight on his birthday.
(a) If he donates 800 kg of wheat grain this birthday, what is his current weight?
(b) If he had donated 780 kg of wheat grain on his last birthday, what was his weight last year?
(c) How much weight did he gain in a year until this birthday?Show solution

Given: Wheat donated = 10 × King's weight

(a) Wheat donated this birthday = 800 kg
$\text{King's current weight} = 800 \div 10 = \boxed{80 \text{ kg}}$

(b) Wheat donated last birthday = 780 kg
$\text{King's weight last year} = 780 \div 10 = \boxed{78 \text{ kg}}$

(c) Weight gained in one year:
$= 80 \text{ kg} - 78 \text{ kg} = \boxed{2 \text{ kg}}$

Answer: The king gained 2 kg in a year.

Let Us Do — Addition and Subtraction of Weights

1A restaurant owner uses 5 kg 200 g, 8 kg 900 g, and 12 kg 600 g of onions over 3 days. What is the total weight of onions used by the restaurant owner in 3 days?Show solution

Given: Day 1 = 5 kg 200 g, Day 2 = 8 kg 900 g, Day 3 = 12 kg 600 g

Working:
$\text{Total} = 5 \text{ kg } 200 \text{ g} + 8 \text{ kg } 900 \text{ g} + 12 \text{ kg } 600 \text{ g}$

Add kg and g separately:
$\text{kg: } 5 + 8 + 12 = 25 \text{ kg}$
$\text{g: } 200 + 900 + 600 = 1{,}700 \text{ g} = 1 \text{ kg } 700 \text{ g}$

$\text{Total} = 25 \text{ kg} + 1 \text{ kg } 700 \text{ g} = \boxed{26 \text{ kg } 700 \text{ g}}$

Answer: The total weight of onions used is 26 kg 700 g.

2Aarav is helping his grandfather at the fruit stall. He lifts two baskets of apples weighing 2 kg 100 g and 3 kg 950 g. What is the total weight of apples he lifted?Show solution

Given: Basket 1 = 2 kg 100 g, Basket 2 = 3 kg 950 g

Working:
$\text{kg: } 2 + 3 = 5 \text{ kg}$
$\text{g: } 100 + 950 = 1{,}050 \text{ g} = 1 \text{ kg } 50 \text{ g}$

$\text{Total} = 5 \text{ kg} + 1 \text{ kg } 50 \text{ g} = \boxed{6 \text{ kg } 50 \text{ g}}$

Answer: The total weight of apples Aarav lifted is 6 kg 50 g.

34 kg 500 g of sand is used from a sack weighing 10 kg. How much sand is left in the sack?Show solution

Given: Total sand = 10 kg, Sand used = 4 kg 500 g

Working:
$10 \text{ kg} - 4 \text{ kg } 500 \text{ g}$

Convert 10 kg = 9 kg 1,000 g (to subtract grams):
$= 9 \text{ kg } 1{,}000 \text{ g} - 4 \text{ kg } 500 \text{ g}$
$\text{kg: } 9 - 4 = 5 \text{ kg}$
$\text{g: } 1{,}000 - 500 = 500 \text{ g}$

$\text{Sand left} = \boxed{5 \text{ kg } 500 \text{ g}}$

Answer: 5 kg 500 g of sand is left in the sack.

4A rice sack weighs 9 kg 750 g. After some rice is used, it weighs 3 kg 700 g. How much rice was used?Show solution

Given: Initial weight = 9 kg 750 g, Final weight = 3 kg 700 g

Working:
$\text{Rice used} = 9 \text{ kg } 750 \text{ g} - 3 \text{ kg } 700 \text{ g}$
$\text{kg: } 9 - 3 = 6 \text{ kg}$
$\text{g: } 750 - 700 = 50 \text{ g}$

$\text{Rice used} = \boxed{6 \text{ kg } 50 \text{ g}}$

Answer: 6 kg 50 g of rice was used.

5A delivery truck delivered 17 kg 900 g of supplies in the morning and 12 kg 700 g in the afternoon. How much total supplies did it deliver?Show solution

Given: Morning = 17 kg 900 g, Afternoon = 12 kg 700 g

Working:
$\text{kg: } 17 + 12 = 29 \text{ kg}$
$\text{g: } 900 + 700 = 1{,}600 \text{ g} = 1 \text{ kg } 600 \text{ g}$

$\text{Total} = 29 \text{ kg} + 1 \text{ kg } 600 \text{ g} = \boxed{30 \text{ kg } 600 \text{ g}}$

Answer: The truck delivered a total of 30 kg 600 g of supplies.

6A box of books weighs 14 kg 750 g. After removing some books, the weight of the box is 10 kg 500 g. What is the weight of the books removed?Show solution

Given: Initial weight = 14 kg 750 g, Final weight = 10 kg 500 g

Working:
$\text{Weight of books removed} = 14 \text{ kg } 750 \text{ g} - 10 \text{ kg } 500 \text{ g}$
$\text{kg: } 14 - 10 = 4 \text{ kg}$
$\text{g: } 750 - 500 = 250 \text{ g}$

$\text{Books removed} = \boxed{4 \text{ kg } 250 \text{ g}}$

Answer: The weight of the books removed is 4 kg 250 g.

7In a community kitchen of a Gurdwara, 65 kg of flour was purchased on one day. Out of this, 42 kg 275 g flour was used for preparing langar. The next day, an additional 52 kg 500 g of flour was bought. What is the total quantity of flour now available in the kitchen store?Show solution

Given: Flour purchased Day 1 = 65 kg, Flour used = 42 kg 275 g, Flour purchased Day 2 = 52 kg 500 g

Step 1: Find flour remaining after Day 1 usage.
$65 \text{ kg} - 42 \text{ kg } 275 \text{ g}$
Convert: $65 \text{ kg} = 64 \text{ kg } 1{,}000 \text{ g}$
$= 64 \text{ kg } 1{,}000 \text{ g} - 42 \text{ kg } 275 \text{ g}$
$\text{kg: } 64 - 42 = 22 \text{ kg}$
$\text{g: } 1{,}000 - 275 = 725 \text{ g}$
$\text{Remaining} = 22 \text{ kg } 725 \text{ g}$

Step 2: Add flour purchased on Day 2.
$22 \text{ kg } 725 \text{ g} + 52 \text{ kg } 500 \text{ g}$
$\text{kg: } 22 + 52 = 74 \text{ kg}$
$\text{g: } 725 + 500 = 1{,}225 \text{ g} = 1 \text{ kg } 225 \text{ g}$
$\text{Total} = 74 \text{ kg} + 1 \text{ kg } 225 \text{ g} = \boxed{75 \text{ kg } 225 \text{ g}}$

Answer: The total quantity of flour available in the kitchen store is 75 kg 225 g.

Let Us Do — More Operations on Weight

1The cost of some grocery items is given in the following table. Find the total cost of each item.
| Item | Weight | Cost of 1 kg |
| Rice | 12 kg 500 g | ₹60 |
| Flour | 7 kg 250 g | ₹40 |
| Sugar | 5 kg | ₹45 |
| Chana dal | 3 kg 600 g | ₹70 |
| Besan | 4 kg | ₹60 |
| Jaggery | 1 kg 400 g | ₹50 |

Concept: Convert weight to kg (as a decimal or fraction), then multiply by cost per kg.

Rice: 12 kg 500 g = 12.5 kg
$\text{Cost} = 12.5 \times 60 = \boxed{₹750}$

Flour: 7 kg 250 g = 7.25 kg
$\text{Cost} = 7.25 \times 40 = \boxed{₹290}$

Sugar: 5 kg
$\text{Cost} = 5 \times 45 = \boxed{₹225}$

Chana dal: 3 kg 600 g = 3.6 kg
$\text{Cost} = 3.6 \times 70 = \boxed{₹252}$

Besan: 4 kg
$\text{Cost} = 4 \times 60 = \boxed{₹240}$

Jaggery: 1 kg 400 g = 1.4 kg
$\text{Cost} = 1.4 \times 50 = \boxed{₹70}$

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24 people need 500 g rice for a meal. How much rice will be needed for 8 people if they eat similar quantity of rice?

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35 kg of tomatoes cost ₹73. How much will 10 kg of tomatoes cost?

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4Nitesh is a scrap dealer. How much would he have paid for:
(a) 16 kg of old newspaper, if he paid ₹8 for every 1 kg of newspaper?
(b) 20 kg iron, if he paid ₹200 for every 10 kg of iron?
(c) 10 kg plastic, if he paid ₹30 for 5 kg of plastic?

(a) Newspaper:

Given: ₹8 per 1 kg
$\text{Cost of 16 kg} = 16 \times 8 = \boxed{₹128}$

(b) Iron:

Given: ₹200 per 10 kg

Double number line:
$\text{kg: } 0 \to 10 \to 20$
$\text{₹: } 0 \to 200 \to 400$

$\text{Cost of 20 kg} = 2 \times 200 = \boxed{₹400}$

(c) Plastic:

Given: ₹30 per 5 kg

Double number line:
$\text{kg: } 0 \to 5 \to 10$
$\text{₹: } 0 \to 30 \to 60$

$\text{Cost of 10 kg} = 2 \times 30 = \boxed{₹60}$

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Measuring Capacity

1You must have seen tea being prepared at your home. How much water and milk do we need to make 2 cups of tea? Do we need 1 l of water to make 2 cups of tea? Is 500 ml of water enough for 2 cups of tea?

Discussion-based question:

A standard teacup holds about 150–200 ml of liquid.

For 2 cups of tea, we need approximately $2 \times 150 = 300$ ml to $2 \times 200 = 400$ ml of liquid (water + milk combined).

1 l (1,000 ml) of water for 2 cups of tea is too much.
500 ml of water for 2 cups of tea is more than enough (it is sufficient).

Answer: 500 ml of water is enough (and even more than needed) to make 2 cups of tea. 1 litre would be too much for just 2 cups.

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2A bucket can hold a maximum of 20 ml of water. Is this statement correct? Which unit should be used in such a situation?

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Big to Small, Small to Big

1Ramiz brings a 500 ml water bottle to school. He drinks two bottles at school. How much water does he drink at school?
Ramiz drinks _____ ml + _____ ml = _____ ml.
Ramiz drinks _____ l of water in a day.

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2Muskaan drinks 3 l of water in a day. How many times would she need to refill a 500 ml water bottle?
Muskaan drinks _____ ml of water in a day.

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Let Us Think — Conversion of Litres and Millilitres

1Mary and Daisy filled their bottle with 1 l 400 ml of water. They wondered about the capacity of the bottle in ml. Who is correct and why?

Given: Capacity = 1 l 400 ml

Concept: $1 \text{ l} = 1{,}000 \text{ ml}$

Working:
$1 \text{ l } 400 \text{ ml} = 1 \times 1{,}000 \text{ ml} + 400 \text{ ml}$
$= 1{,}000 \text{ ml} + 400 \text{ ml} = \boxed{1{,}400 \text{ ml}}$

Answer: The student who said 1,400 ml is correct. (A common wrong answer is 1,040 ml or 400 ml — these are incorrect because 1 l must be converted to 1,000 ml first.)

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2Convert and fill in the blanks appropriately.
(a) 3 l 8 ml = ___ ml
(b) 9 l 90 ml = ___ ml
(c) 14,075 ml = ___ l ___ ml
(d) 8 l 86 ml = ___ ml
(e) 12,200 ml = ___ l ___ ml
(f) 18,350 ml = ___ l ___ ml

Concept: $1 \text{ l} = 1{,}000 \text{ ml}$

(a) $3 \text{ l } 8 \text{ ml} = 3 \times 1{,}000 + 8 = 3{,}000 + 8 = \boxed{3{,}008 \text{ ml}}$

(b) $9 \text{ l } 90 \text{ ml} = 9 \times 1{,}000 + 90 = 9{,}000 + 90 = \boxed{9{,}090 \text{ ml}}$

(c) $14{,}075 \div 1{,}000 = 14$ remainder $75$
$= \boxed{14 \text{ l } 75 \text{ ml}}$

(d) $8 \text{ l } 86 \text{ ml} = 8 \times 1{,}000 + 86 = 8{,}000 + 86 = \boxed{8{,}086 \text{ ml}}$

(e) $12{,}200 \div 1{,}000 = 12$ remainder $200$
$= \boxed{12 \text{ l } 200 \text{ ml}}$

(f) $18{,}350 \div 1{,}000 = 18$ remainder $350$
$= \boxed{18 \text{ l } 350 \text{ ml}}$

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Let Us Compare — Petrol Pump

1Kiran owns a petrol pump. She records the details of the sales of petrol in a day. (Table with vehicle types, number of vehicles, and fuel quantity per vehicle — fill in total quantity of fuel.)

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2Complete the table and answer:
| Vehicle | No. of Vehicles | Quantity of Fuel in Each (litres) | Total Quantity (litres) |
| Truck | 3 | 500 | |
| Bus | 6 | 300 | |
| Car | 10 | 50 | |
| Auto Rickshaw | 12 | 8 | |
| Two-wheeler | 25 | 5 | |
(a) How much more fuel is bought for buses than for trucks?
(b) What is the total quantity of fuel filled from the petrol pump on that day?

Step 1: Fill in the Total Quantity column.

Truck: $3 \times 500 = 1{,}500$ l
Bus: $6 \times 300 = 1{,}800$ l
Car: $10 \times 50 = 500$ l
Auto Rickshaw: $12 \times 8 = 96$ l
Two-wheeler: $25 \times 5 = 125$ l

(a) Fuel for buses – Fuel for trucks:
$1{,}800 - 1{,}500 = \boxed{300 \text{ l}}$
Buses bought 300 l more fuel than trucks.

(b) Total fuel filled:
$1{,}500 + 1{,}800 + 500 + 96 + 125$
$= 1{,}500 + 1{,}800 = 3{,}300$
$3{,}300 + 500 = 3{,}800$
$3{,}800 + 96 = 3{,}896$
$3{,}896 + 125 = \boxed{4{,}021 \text{ l}}$

Answer: Total fuel filled on that day = 4,021 litres.

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3Compare the following quantities using the signs <, =, >.
(a) 5 l 600 ml _____ 5,400 ml
(b) 10 l 100 ml _____ 1 l 600 ml
(c) 190 ml + 800 ml _____ 800 ml + 109 ml
(d) 3 l 600 ml _____ 3,600 ml
(e) 4 l 50 ml _____ 4 l 500 ml

Concept: $1 \text{ l} = 1{,}000 \text{ ml}$ . Convert to same unit before comparing.

(a) $5 \text{ l } 600 \text{ ml} = 5{,}600 \text{ ml}$
$5{,}600 \text{ ml} \quad \boxed{>} \quad 5{,}400 \text{ ml}$

(b) $10 \text{ l } 100 \text{ ml} = 10{,}100 \text{ ml}$ ; $\quad 1 \text{ l } 600 \text{ ml} = 1{,}600 \text{ ml}$
$10{,}100 \text{ ml} \quad \boxed{>} \quad 1{,}600 \text{ ml}$

(c) $190 + 800 = 990 \text{ ml}$ ; $\quad 800 + 109 = 909 \text{ ml}$
$990 \text{ ml} \quad \boxed{>} \quad 909 \text{ ml}$

(d) $3 \text{ l } 600 \text{ ml} = 3{,}600 \text{ ml}$
$3{,}600 \text{ ml} \quad \boxed{=} \quad 3{,}600 \text{ ml}$

(e) $4 \text{ l } 50 \text{ ml} = 4{,}050 \text{ ml}$ ; $\quad 4 \text{ l } 500 \text{ ml} = 4{,}500 \text{ ml}$
$4{,}050 \text{ ml} \quad \boxed{<} \quad 4{,}500 \text{ ml}$

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4Sam and Tina fill petrol in their bikes. Tina bought 2 l 500 ml of petrol. Sam bought 2 l 800 ml more petrol than Tina. How much petrol did Sam buy? After refueling, Sam found his fuel gauge reading 9 l. How much fuel did his bike have before refueling?

Part 1: How much petrol did Sam buy?

Given: Tina bought = 2 l 500 ml; Sam bought 2 l 800 ml MORE than Tina.

$\text{Sam's petrol} = 2 \text{ l } 500 \text{ ml} + 2 \text{ l } 800 \text{ ml}$
$\text{l: } 2 + 2 = 4 \text{ l}$
$\text{ml: } 500 + 800 = 1{,}300 \text{ ml} = 1 \text{ l } 300 \text{ ml}$
$\text{Total} = 4 \text{ l} + 1 \text{ l } 300 \text{ ml} = \boxed{5 \text{ l } 300 \text{ ml}}$

Part 2: Fuel before refueling?

Given: After refueling, gauge reads 9 l; Sam added 5 l 300 ml.

$\text{Fuel before} = 9 \text{ l} - 5 \text{ l } 300 \text{ ml}$

Convert: $9 \text{ l} = 8 \text{ l } 1{,}000 \text{ ml}$
$= 8 \text{ l } 1{,}000 \text{ ml} - 5 \text{ l } 300 \text{ ml}$
$\text{l: } 8 - 5 = 3 \text{ l}$
$\text{ml: } 1{,}000 - 300 = 700 \text{ ml}$

$\text{Fuel before refueling} = \boxed{3 \text{ l } 700 \text{ ml}}$

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Let Us Solve — Capacity Problems

1Riya is filling water bottles for a picnic. She fills one 2 l bottle and four 500 ml bottles. Her friend, Aarav fills three 750 ml bottles. Who filled more water, Riya or Aarav? How much more?

Riya's total water:
$1 \times 2 \text{ l} + 4 \times 500 \text{ ml}$
$= 2{,}000 \text{ ml} + 2{,}000 \text{ ml} = 4{,}000 \text{ ml}$

Aarav's total water:
$3 \times 750 \text{ ml} = 2{,}250 \text{ ml}$

Comparison:
$4{,}000 \text{ ml} > 2{,}250 \text{ ml}$

Difference:
$4{,}000 - 2{,}250 = 1{,}750 \text{ ml} = 1 \text{ l } 750 \text{ ml}$

Answer: Riya filled more water. She filled 1 l 750 ml (1,750 ml) more than Aarav.

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2A bottle of milk is poured equally into 8 glasses, leaving 120 ml of milk in the bottle.
(a) If each glass has a capacity of 360 ml, what is the total capacity of 8 glasses?
(b) How much milk was there in the bottle initially?
(c) If 1 l of milk costs ₹40, how much will 3 l milk cost?

(a) Total capacity of 8 glasses:
$8 \times 360 \text{ ml} = \boxed{2{,}880 \text{ ml}}$

(b) Initial milk in the bottle:

Milk poured into glasses = 2,880 ml
Milk left in bottle = 120 ml
$\text{Initial milk} = 2{,}880 + 120 = \boxed{3{,}000 \text{ ml} = 3 \text{ l}}$

(c) Cost of 3 l milk:

Given: 1 l costs ₹40
$3 \text{ l} = 3 \times 40 = \boxed{₹120}$

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3A juice vendor has a 5 l container of orange juice. Each glass has a capacity of 250 ml.
(a) How many full glasses can he serve before the container becomes empty?
(b) If he has already served 10 glasses, how much juice is left?
(c) If 250 ml of juice is sold at ₹25, how much will he earn by selling 5 l juice?

Convert: $5 \text{ l} = 5{,}000 \text{ ml}$

(a) Number of full glasses:
$5{,}000 \div 250 = \boxed{20 \text{ glasses}}$

(b) Juice left after 10 glasses:
$\text{Juice served} = 10 \times 250 = 2{,}500 \text{ ml}$
$\text{Juice left} = 5{,}000 - 2{,}500 = \boxed{2{,}500 \text{ ml} = 2 \text{ l } 500 \text{ ml}}$

(c) Earnings from selling 5 l:

Total glasses from 5 l = 20 glasses
$\text{Earnings} = 20 \times 25 = \boxed{₹500}$

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4In a factory, 8 l 400 ml of oil needs to be equally poured into 7 containers for storage. How much oil will each container hold?

Given: Total oil = 8 l 400 ml, Number of containers = 7

Convert to ml:
$8 \text{ l } 400 \text{ ml} = 8{,}000 + 400 = 8{,}400 \text{ ml}$

Divide equally:
$8{,}400 \div 7 = 1{,}200 \text{ ml}$

Convert back:
$1{,}200 \text{ ml} = 1 \text{ l } 200 \text{ ml}$

Answer: Each container will hold $\boxed{1 \text{ l } 200 \text{ ml}}$ of oil.

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5If one container can hold 1 l 75 ml of buttermilk, how much buttermilk will be there in 8 such containers?

Given: One container = 1 l 75 ml, Number of containers = 8

Convert to ml:
$1 \text{ l } 75 \text{ ml} = 1{,}000 + 75 = 1{,}075 \text{ ml}$

Total buttermilk:
$8 \times 1{,}075 = 8{,}600 \text{ ml}$

Convert back:
$8{,}600 \text{ ml} = 8 \text{ l } 600 \text{ ml}$

Answer: There will be $\boxed{8 \text{ l } 600 \text{ ml}}$ of buttermilk in 8 containers.

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Key topics in Weight and Capacity include Weight in daily life, Converting between kilograms and grams, Comparing weights, Milligram. Study these first, then practise questions on each for Class 5 exams.

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Weight and Capacity — NCERT Solutions

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Let Us Find — Conversion of kg to g

Let Us Find — Complete the Conversions

Comparison between Different Weights

Let Us Find — Milligrams

King's Weight

Let Us Do — Addition and Subtraction of Weights

Let Us Do — More Operations on Weight

Measuring Capacity

Big to Small, Small to Big

Let Us Think — Conversion of Litres and Millilitres

Let Us Compare — Petrol Pump

Let Us Solve — Capacity Problems

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