Distance Formula
ICSE · Class 9 · Mathematics
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Find the distance between points A(3, 4) and B(7, 1).
What is the distance of point P(-5, 12) from the origin?
Find the distance between points M(2, -3) and N(-1, 1).
The point (4, 0) lies on which axis?
Sample Questions
Which of the following points are at a distance of 5 units from the origin?
Show answer
(3, 4), (0, 5), (-3, -4)
Check each: (3,4): √[9+16] = 5 ✓, (0,5): √[0+25] = 5 ✓, (-3,-4): √[9+16] = 5 ✓, (5,5): √[25+25] = 5√2 ≠ 5, (2,3): √[4+9] = √13 ≠ 5
If the distance between points (a, 2) and (3, 6) is 5 units, find the possible values of 'a'.
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a = 0, a = 6
Using distance formula: 5 = √[(3-a)² + (6-2)²] → 25 = (3-a)² + 16 → (3-a)² = 9 → 3-a = ±3 → a = 0 or a = 6
Find the distance between points A(-2, -5) and B(1, -1).
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5 units
Distance = √[(1-(-2))² + (-1-(-5))²] = √[(3)² + (4)²] = √[9 + 16] = √25 = 5 units
Which point on the x-axis is equidistant from A(3, 4) and B(7, 2)?
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(6, 0)
Let point be (x, 0). Setting distances equal: √[(x-3)² + 16] = √[(x-7)² + 4] → (x-3)² + 16 = (x-7)² + 4 → x² - 6x + 9 + 16 = x² - 14x + 49 + 4 → 8x = 48 → x = 6
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