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Chapter 5 of 14
Practice Quiz

Gravitation

Maharashtra Board · Class 11 · Physics

Practice quiz for Gravitation — Maharashtra Board Class 11 Physics. MCQs and questions with answers to test your preparation.

45 questions24 flashcards5 concepts

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Quick Quiz: Gravitation

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1

What is the value of universal gravitational constant G in SI units?

2

According to Kepler's first law, planets move in which type of orbit around the Sun?

3

A satellite is orbiting Earth at a height of 400 km above the surface. If Earth's radius is 6400 km and g = 10 m/s², what is the orbital velocity of the satellite?

4

What is the escape velocity from Earth's surface? (Given: g = 10 m/s², R = 6.4 × 10⁶ m)

45 Questions·
multiple choicemultiple correct

Sample Questions

1multiple correct

Which of the following factors affect the acceleration due to gravity on Earth's surface? (Select all correct answers)

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Mass of the Earth, Radius of the Earth, Rotation of the Earth, Latitude, Shape of the Earth

Acceleration due to gravity g = GM/R² depends on Earth's mass M and radius R. Earth's rotation causes centrifugal effect reducing apparent g. Latitude affects g due to rotation and Earth's oblate shape. The mass of the object cancels out in the acceleration formula, so it doesn't affect g.

2multiple choice

At what height above Earth's surface does the acceleration due to gravity become one-fourth of its surface value?

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R (one Earth radius)

Step-by-step solution: At height h: gₕ = GM/(R+h)² At surface: g = GM/R² Given: gₕ = g/4 Therefore: GM/(R+h)² = (1/4) × GM/R² (R+h)² = 4R² R+h = 2R h = R So at height equal to Earth's radius, gravity becomes one-fourth.

3multiple choice

Which statement about geostationary satellites is correct?

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They orbit Earth in 24 hours

Geostationary satellites have an orbital period of 24 hours, which matches Earth's rotational period. This makes them appear stationary relative to Earth's surface. They orbit in the equatorial plane at a specific altitude of about 36,000 km above Earth's surface.

4multiple choice

The gravitational force between two masses is 100 N when they are 10 m apart. What will be the force when the distance is doubled?

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25 N

Step-by-step solution: Gravitational force F = Gm₁m₂/r² Initially: F₁ = 100 N at r₁ = 10 m Finally: r₂ = 2r₁ = 20 m F₂ = Gm₁m₂/(2r₁)² = Gm₁m₂/(4r₁²) = F₁/4 = 100/4 = 25 N When distance doubles, force becomes one-fourth due to inverse square law.

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Frequently Asked Questions

What are the important topics in Gravitation for Maharashtra Board Class 11 Physics?
Gravitation covers several key topics that are frequently asked in Maharashtra Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Gravitation — Maharashtra Board Class 11 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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