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The d-and f-Block Elements

Punjab Board · Class 12 · Chemistry

Flashcards for The d-and f-Block Elements — Punjab Board Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions35 flashcards5 concepts

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A flowchart detailing the industrial preparation of potassium dichromate, starting from chromite ore and involving fusion, acidification, and conversion steps.
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35 Flashcards
Card 1Electronic Configuration of d-block

What is the general electronic configuration of d-block transition elements?

Answer

(n-1)d¹⁻¹⁰ns¹⁻² where (n-1) represents the inner d orbitals with 1-10 electrons and ns represents the outermost orbital with 1-2 electrons. Exception: Palladium has configuration [Kr]4d¹⁰5s⁰. This par

Card 2Anomalous Electronic Configurations

Why is Chromium (Cr) written as [Ar]3d⁵4s¹ instead of [Ar]3d⁴4s²?

Answer

Chromium exhibits anomalous electronic configuration because of the extra stability of half-filled d orbitals (d⁵). The energy gap between 3d and 4s orbitals is small enough that one electron from 4s

Card 3Classification of Transition Elements

Why is Zinc (Zn) not considered a true transition element despite being in the d-block?

Answer

Zinc is not classified as a true transition element because it has a completely filled d¹⁰ configuration ([Ar]3d¹⁰4s²) in its ground state and all common oxidation states. According to IUPAC definitio

Card 4Magnetic Properties - Calculations

Calculate the magnetic moment (μ) of Fe²⁺ ion using spin-only formula if it has 4 unpaired electrons.

Answer

Formula: μ = √[n(n+2)] where n = number of unpaired electrons Step 1: Identify n = 4 unpaired electrons in Fe²⁺ (d⁶ configuration) Step 2: μ = √[4(4+2)] = √[4×6] = √24 = 4.90 BM Answer: 4.90 Bohr magn

Card 5Magnetic Properties

What is the 'spin-only' formula for magnetic moment and what does it calculate?

Answer

Formula: μ = √[n(n+2)] where μ is magnetic moment in Bohr magnetons (BM) and n is the number of unpaired electrons. This formula calculates the magnetic moment arising solely from the spin angular mom

Card 6Preparation of K₂Cr₂O₇

Write the balanced equation for the preparation of potassium dichromate from chromite ore using fusion method.

Answer

4FeCr₂O₄(s) + 8Na₂CO₃(s) + 7O₂(g) → 8Na₂CrO₄(aq) + 2Fe₂O₃(s) + 8CO₂(g) This is the fusion reaction where chromite ore reacts with sodium carbonate in free access of air. This produces yellow sodium c

Card 7Chromate and Dichromate Equilibrium

Write the conversion reaction between chromate and dichromate ions in acidic and basic conditions.

Answer

Acidic Condition (formation of dichromate): 2CrO₄²⁻(aq) + 2H⁺(aq) → Cr₂O₇²⁻(aq) + H₂O(l) Basic Condition (formation of chromate): Cr₂O₇²⁻(aq) + 2OH⁻(aq) → 2CrO₄²⁻(aq) + H₂O(l) Both CrO₄²⁻ and Cr₂O₇²

Card 8Redox Properties of K₂Cr₂O₇

What is the standard electrode potential (E°) for the reduction of dichromate ion in acidic solution and what does it oxidize?

Answer

Half-reaction: Cr₂O₇²⁻(aq) + 14H⁺(aq) + 6e⁻ → 2Cr³⁺(aq) + 7H₂O(l) E° = +1.33 V With such a positive E° value, acidified K₂Cr₂O₇ is a strong oxidizing agent. It oxidizes: - Iodides (I⁻) to iodine (I₂)

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Frequently Asked Questions

What are the important topics in The d-and f-Block Elements for Punjab Board Class 12 Chemistry?
Key topics in The d-and f-Block Elements include d-Block and f-Block Elements: Comprehensive Overview, Complete Overview of d- and f-Block Elements, D-Block Elements: Properties and Characteristics. These are the concepts Punjab Board Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in The d-and f-Block Elements — Punjab Board Class 12 Chemistry?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for The d-and f-Block Elements?
There are 35 flashcards for The d-and f-Block Elements covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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