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Chapter 9 of 10
Important Questions

Solutions — Important Questions

Tamil Nadu Board · Class 10 · Science

43 important questions from Solutions for Tamil Nadu Board Class 10 Science, with answers. Includes multiple choice and numerical questions.

43 questions32 flashcards5 concepts

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A labeled diagram showing the experiment of heating hydrated copper sulphate crystals, observing the loss of water (turning white) and the formation of water droplets, and then re-adding water to rest
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43 Questions·
multiple choicenumerical

Important Questions from Solutions

1multiple choice
1 marks

The principle 'like dissolves like' in chemistry means which of the following?

Show answer

Polar solvents dissolve polar solutes and non-polar solvents dissolve non-polar solutes

Step 1: The phrase 'like dissolves like' refers to the polarity of substances. Step 2: Polar compounds (like common salt, NaCl) are soluble in polar solvents (like water). Step 3: Non-polar compounds (like fat, sulphur) are soluble in non-polar solvents (like ether, carbon disulphide). Step 4: This is why sulphur dissolves in CS₂ but not in water — sulphur is non-polar and water is polar. Step 5: Options C and D describe irrelevant physical properties (size, weight) that do not determine solubility.

2multiple choice
1 marks

When blue copper sulphate crystals (CuSO₄·5H₂O) are gently heated, what happens?

Show answer

They lose water of crystallization and turn colourless

Step 1: Copper sulphate pentahydrate (CuSO₄·5H₂O) is a hydrated salt — it has 5 molecules of water of crystallization. Step 2: When gently heated, the salt loses these 5 water molecules: CuSO₄·5H₂O → CuSO₄ + 5H₂O. Step 3: The blue colour of CuSO₄ crystals is due to the presence of water of crystallization. Step 4: After losing water, the resulting anhydrous CuSO₄ becomes colourless/white and amorphous. Step 5: This reaction is reversible — adding a few drops of water to anhydrous CuSO₄ makes it turn blue again, which is used as a test for moisture.

3multiple choice
1 marks

What is the solubility of a solute if 1.5 g of it dissolves in 15 g of water to form a saturated solution at 298 K?

Show answer

10 g per 100 g water

Step 1: Formula: Solubility = (Mass of solute / Mass of solvent) × 100. Step 2: Mass of solute = 1.5 g; Mass of solvent = 15 g. Step 3: Solubility = (1.5 / 15) × 100 = 10 g per 100 g of water. Step 4: This means 10 g of this solute can dissolve in 100 g of water to form a saturated solution at 298 K. Step 5: Option C (15 g) is a common error where students confuse the mass of solvent directly with solubility without scaling to 100 g.

4multiple choice
1 marks

Which of the following substances is an example of a deliquescent substance?

Show answer

Caustic soda (NaOH)

Step 1: Deliquescent substances absorb so much moisture from the air that they completely dissolve in the absorbed water. Step 2: Caustic soda (NaOH) is a classic deliquescent substance — it absorbs water from humid air and eventually forms a liquid solution. Step 3: Silica gel, Quick lime (CaO), and Phosphorus pentoxide (P₂O₅) are hygroscopic substances — they absorb moisture but do not dissolve. Step 4: The key difference is that deliquescent substances change their physical state (solid → liquid), while hygroscopic substances do not. Step 5: Deliquescence is maximum at low temperatures and

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Frequently Asked Questions

What are the important topics in Solutions for Tamil Nadu Board Class 10 Science?
Key topics in Solutions include Definition and Basic Concepts of Solutions, Types of Solutions, Solubility and Factors Affecting It, Concentration of Solutions. Study these first, then practise questions on each for the Tamil Nadu Board Class 10 board exam.
How many important questions are there in Solutions?
Super Tutor has 43 practice questions for Solutions, including multiple choice, numerical questions. A sample with answers is on this page.

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