Light: Mirrors and Lenses
CBSE · Class 8 · Science
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Keep the Curiosity Alive — Chapter 10: Light: Mirrors and Lenses
1A light ray is incident on a mirror and gets reflected by it. The angle made by the incident ray with the normal to the mirror is 40°. What is the angle made by the reflected ray with the mirror?
(i) 40°
(ii) 50°
(iii) 45°
(iv) 60°Show solution
Concept used: By the first law of reflection, the angle of incidence equals the angle of reflection. The angle made by a ray with the mirror = 90° − (angle made with the normal).
Working:
- Angle of reflection = angle of incidence = 40°
- Angle made by the reflected ray with the mirror = 90° − 40° = 50°
Answer: Option (ii) 50°
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2Fig. 10.22 shows three different situations where a light ray falls on a mirror:
(i) The light ray falls along the normal.
(ii) The mirror is tilted, but the light ray still falls along the normal to the tilted surface.
(iii) The mirror is tilted, and the light ray falls at an angle of 20° from the normal.
Draw the reflected ray in each case. What is the angle of reflection in each case?Show solution
1. Angle of incidence (i) = Angle of reflection (r), both measured from the normal.
2. The incident ray, normal, and reflected ray all lie in the same plane.
Case (i): Light ray falls along the normal
- The angle of incidence = 0° (ray is along the normal).
- Therefore, angle of reflection = 0°.
- The reflected ray travels back along the same path as the incident ray (i.e., along the normal, but in the opposite direction).
- Angle of reflection = 0°
Case (ii): Mirror is tilted, but the light ray still falls along the normal to the tilted surface
- Even though the mirror is tilted, the ray still falls along the normal, so the angle of incidence = 0°.
- Therefore, angle of reflection = 0°.
- The reflected ray again travels back along the same path as the incident ray.
- Angle of reflection = 0°
Case (iii): Mirror is tilted, and the light ray falls at an angle of 20° from the normal
- Angle of incidence = 20°.
- By the law of reflection, angle of reflection = 20°.
- Draw the normal at the point of incidence on the tilted mirror. Using a protractor, draw the reflected ray on the other side of the normal such that it makes an angle of 20° with the normal.
- Angle of reflection = 20°
*(Note: Use a ruler and protractor to draw the diagrams accurately as instructed. The reflected ray is always on the opposite side of the normal from the incident ray, making an equal angle.)*
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3In Fig. 10.23, the cap of a sketch pen is placed in front of three types of mirrors. Match each image with the correct mirror.
| Image | Mirror |
|---|---|
| (i) | Plane mirror |
| (ii) | Convex mirror |
| (iii) | Concave mirror |Show solution
- A plane mirror always forms an image that is erect and of the same size as the object.
- A convex mirror always forms an image that is erect and smaller (diminished) than the object.
- A concave mirror (when the object is close) forms an image that is erect and larger (enlarged) than the object.
Matching:
| Image | Mirror |
|---|---|
| (i) — erect image, same size as object | Plane mirror |
| (ii) — erect image, smaller than object | Convex mirror |
| (iii) — erect image, larger than object | Concave mirror |
Answer: Image (i) → Plane mirror; Image (ii) → Convex mirror; Image (iii) → Concave mirror.
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4In Fig. 10.24, the cap of a sketch pen is placed behind a convex lens, a concave lens, and a flat transparent glass piece — all at the same distance. Match each image with the correct type of lens or glass.
| Image | Lens/glass type |
|---|---|
| (i) | Flat transparent glass piece |
| (ii) | Convex lens |
| (iii) | Concave lens |Show solution
- A flat transparent glass piece does not bend light; the object appears the same size and shape.
- A convex lens (converging lens), when the object is placed close, forms an erect and enlarged image.
- A concave lens (diverging lens) always forms an erect and diminished (smaller) image.
Matching:
| Image | Lens/glass type |
|---|---|
| (i) — erect image, same size as object | Flat transparent glass piece |
| (ii) — erect image, larger (enlarged) than object | Convex lens |
| (iii) — erect image, smaller (diminished) than object | Concave lens |
Answer: Image (i) → Flat transparent glass piece; Image (ii) → Convex lens; Image (iii) → Concave lens.
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5When the light is incident along the normal on the mirror, which of the following statements is true:
(i) Angle of incidence is 90°
(ii) Angle of incidence is 0°
(iii) Angle of reflection is 90°
(iv) No reflection of light takes place in this caseShow solution
Concept used: The angle of incidence is measured between the incident ray and the normal at the point of incidence. If the ray travels along the normal, the angle between the ray and the normal is 0°.
Working:
- Angle of incidence = 0° (since the ray is along the normal).
- By the law of reflection, angle of reflection = angle of incidence = 0°.
- The reflected ray travels back along the normal (same path, opposite direction).
- Reflection does take place.
Answer: Option (ii) Angle of incidence is 0°
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6Three mirrors—plane, concave and convex are placed in Fig. 10.25. On the basis of the images of the graph sheet formed in the mirrors, identify the mirrors and write their names above the mirrors.Show solution
- A plane mirror reflects the graph sheet image with squares of the same size — the image is neither enlarged nor diminished.
- A concave mirror (when the graph sheet is close) forms an enlarged image — the squares appear bigger.
- A convex mirror always forms a diminished image — the squares appear smaller and more squares are visible.
Identification (based on the images seen in Fig. 10.25):
- The mirror showing the graph squares of the same size → Plane mirror
- The mirror showing the graph squares larger (enlarged) → Concave mirror
- The mirror showing the graph squares smaller (diminished, more squares visible) → Convex mirror
*(Note: Since the actual figure cannot be seen, the identification is based on the standard properties of the three mirrors as described above.)*
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(i) her erect image keeps decreasing in size.
(ii) her inverted image keeps decreasing in size.
(iii) her inverted image keeps increasing in size and eventually it becomes erect and magnified.
(iv) her erect image keeps increasing in size.
| Column I | Column II |
|---|---|
| (i) Concave mirror | (a) Spherical mirror with a reflecting surface that curves inwards. |
| (ii) Convex mirror | (b) It forms an image which is always erect and diminished in size. |
| (iii) Convex lens | (c) Object placed behind it may appear inverted at some distance. |
| (iv) Concave lens | (d) Object placed behind it always appears diminished in size. |
Assertion: Convex mirrors are preferred for observing the traffic behind us.
Reason: Convex mirrors provide a significantly larger view area than plane mirrors.
Choose the correct option:
(i) Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.
(ii) Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.
(iii) Assertion is correct but Reason is incorrect.
(iv) Both Assertion and Reason are incorrect.
(i) Figure (a) indicates a plane mirror and Figure (b) indicates a concave mirror.
(ii) Figure (a) indicates a convex mirror and Figure (b) indicates a concave mirror.
(iii) Figure (a) indicates a concave mirror and Figure (b) indicates a convex mirror.
(iv) Figure (a) indicates a plane mirror and Figure (b) indicates a convex mirror.
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