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Special Type of Quadrilaterals

ICSE · Class 8 · Mathematics

Flashcards for Special Type of Quadrilaterals — ICSE Class 8 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Quadrilateral angles

Solve: How many degrees is the sum of the interior angles of a quadrilateral?

Answer

Step 1: Use the formula for a quadrilateral. ∠A + ∠B + ∠C + ∠D = 360° Step 2: Add the angles. So, the sum of the interior angles is 360°. Answer: 360°

Card 2Quadrilateral angles

Apply the quadrilateral angle-sum formula to find the missing angle: ∠A = 80°, ∠B = 95°, ∠C = 110°. Find ∠D.

Answer

Step 1: Use ∠A + ∠B + ∠C + ∠D = 360°. Step 2: Substitute the known angles. 80° + 95° + 110° + ∠D = 360° Step 3: Add the known angles. 285° + ∠D = 360° Step 4: Subtract 285° from both sides. ∠D = 360°

Card 3Parallelogram angles

Why do consecutive angles of a parallelogram add up to 180°?

Answer

In a parallelogram, opposite angles are equal. So if ∠A = ∠C and ∠B = ∠D, then: ∠A + ∠B + ∠C + ∠D = 360° ∠A + ∠B + ∠A + ∠B = 360° 2∠A + 2∠B = 360° ∠A + ∠B = 180° So consecutive angles are supplementar

Card 4Parallelogram angles

Solve: In a parallelogram, ∠A = 3 times ∠B. Find all the angles.

Answer

Step 1: Let ∠B = x. Then ∠A = 3x. Step 2: Consecutive angles of a parallelogram add to 180°. 3x + x = 180° Step 3: Solve. 4x = 180° x = 45° Step 4: Find the angles. ∠B = 45° ∠A = 135° Step 5: Opposite

Card 5Parallelogram diagonals

When do you use the fact that the diagonals of a parallelogram bisect each other?

Answer

Use it when the diagonals intersect at a point O and the halves are needed. If AC and BD are diagonals of parallelogram ABCD, then: OA = OC and OB = OD Example: If OB = 6 cm, then BD = 12 cm. If OA =

Card 6Parallelogram diagonals

Solve: In a parallelogram, OB = 6 cm. Find BD.

Answer

Step 1: Use the fact that diagonals of a parallelogram bisect each other. Step 2: OB is half of BD. OB = 1/2 BD Step 3: Substitute OB = 6 cm. 6 cm = 1/2 BD Step 4: Multiply by 2. BD = 12 cm Answer: 12

Card 7Parallelogram diagonals

Solve: In a parallelogram, the diagonals intersect at O. If OA = 2x + 6 and OD = 3x + 3, find x.

Answer

Step 1: In a parallelogram, diagonals bisect each other. So OA = OC and OB = OD. Step 2: Use the given equal halves. OA = OD 2x + 6 = 3x + 3 Step 3: Solve. 6 = x + 3 x = 3 Answer: x = 3

Card 8Parallelogram perimeter

Solve: In a parallelogram, the adjacent sides are in the ratio 5:3 and the perimeter is 96 cm. Find the sides.

Answer

Step 1: Let the sides be 5x cm and 3x cm. Step 2: Use perimeter of a parallelogram. Perimeter = 2(5x + 3x) Step 3: Substitute 96 cm. 2(5x + 3x) = 96 2(8x) = 96 16x = 96 Step 4: Find x. x = 6 Step 5: F

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What are the important topics in Special Type of Quadrilaterals for ICSE Class 8 Mathematics?
Special Type of Quadrilaterals covers several key topics that are frequently asked in ICSE Class 8 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Special Type of Quadrilaterals — ICSE Class 8 Mathematics?
Understand the core concepts first, then work through the 53 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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