Light
Tamil Nadu Board · Class 9 · Science
Flashcards for Light — Tamil Nadu Board Class 9 Science. Quick Q&A cards covering key concepts, definitions, and formulas.
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Explore the full setWhat is light and how is it defined in physics?
Answer
Light is a form of energy that travels as electromagnetic waves and produces the sensation of sight. It is one of the fundamental forms of energy. Light travels in straight lines through a uniform med…
State the first law of reflection.
Answer
The incident ray, the reflected ray, and the normal at the point of incidence all lie in the same plane. This means that the direction of light reflection is confined to a single 2D plane, not scatter…
State the second law of reflection with a mathematical expression.
Answer
The angle of incidence (i) is equal to the angle of reflection (r): i = r. Both angles are measured from the normal (perpendicular line) to the reflecting surface, not from the surface itself. This ap…
What is lateral inversion and why does it happen in plane mirrors?
Answer
Lateral inversion is the apparent left-right reversal seen in plane mirrors. However, mirrors don't actually reverse left and right - they reverse front and back (inside-out reversal). This optical il…
Distinguish between real and virtual images with examples.
Answer
Real images: Light rays actually converge after reflection/refraction. They are inverted and can be projected on a screen. Example: Image formed by concave mirror when object is beyond focal length. V…
What are the four rules for ray construction in spherical mirrors?
Answer
Rule 1: A ray through the center of curvature reflects back along its own path. Rule 2: A ray parallel to principal axis reflects through (concave) or appears to come from (convex) the focal point. Ru…
A concave mirror has a focal length of 10 cm. Where will an object placed 15 cm in front of the mirror form its image? What is the nature of the image?
Answer
Using mirror formula: 1/f = 1/u + 1/v, where u = -15 cm, f = -10 cm. So: 1/-10 = 1/-15 + 1/v → 1/v = -1/10 + 1/15 = -3+2/30 = -1/30 → v = -30 cm. Image position: 30 cm in front of mirror. Nature: Real…
Calculate the magnification if an object 2 cm high placed in front of a concave mirror produces a real image 4 cm high.
Answer
Magnification m = h_image / h_object = -4 / 2 = -2 (negative sign indicates real, inverted image). The image is twice the size of the object. Alternatively, using m = -v/u: if magnification is -2, the…
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