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Cartesian System of Coordinates

Telangana Open School (TOSS) · Class 12 · Mathematics

Flashcards for Cartesian System of Coordinates — Telangana Open School (TOSS) Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

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24 Flashcards
Card 1Distance Formula

Find the distance between points A(3, 4) and B(7, 1).

Answer

Step 1: Use distance formula: $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ Step 2: Substitute values: $\sqrt{(7 - 3)^2 + (1 - 4)^2} = \sqrt{(4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5$ Answer: 5 unit

Card 2Collinearity

Show that points A(1, 1), B(4, 5), and C(6, 7) are collinear using distance formula.

Answer

Step 1: Find AB, BC, and AC. AB = $\sqrt{(4-1)^2 + (5-1)^2} = \sqrt{9 + 16} = \sqrt{25} = 5$ BC = $\sqrt{(6-4)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$ AC = $\sqrt{(6-1)^2 + (7-1)^2} = \

Card 3Section Formula

Find the coordinates of the point dividing the line segment joining (2, 3) and (8, 9) in the ratio 1:2 internally.

Answer

Step 1: Use section formula (internal): $x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2}, y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2}$ Step 2: $m_1 = 1, m_2 = 2, x_1 = 2, y_1 = 3, x_2 = 8, y_2 = 9$ $x = \frac{1(8)

Card 4Midpoint Formula

Find the midpoint of the line segment joining (−4, 6) and (10, −2).

Answer

Step 1: Use midpoint formula: $\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$ Step 2: $x = \frac{-4 + 10}{2} = \frac{6}{2} = 3$ $y = \frac{6 + (-2)}{2} = \frac{4}{2} = 2$ Answer: (3, 2)

Card 5Area of Triangle

Find the area of triangle with vertices (1, 2), (4, 6), and (7, 3).

Answer

Step 1: Use area formula: $\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$ Step 2: Let $x_1 = 1, y_1 = 2; x_2 = 4, y_2 = 6; x_3 = 7, y_3 = 3$ Area = $\frac{1}{2} |1(6

Card 6Collinearity

Show that points (2, 3), (4, 7), and (6, 11) are collinear using area formula.

Answer

Step 1: Apply area formula: $\text{Area} = \frac{1}{2} |2(7 - 11) + 4(11 - 3) + 6(3 - 7)|$ = $\frac{1}{2} |2(-4) + 4(8) + 6(-4)| = \frac{1}{2} |-8 + 32 - 24| = \frac{1}{2} |0| = 0$ Since area is 0,

Card 7Slope of a Line

Find the slope of the line joining points (−3, 5) and (2, −7).

Answer

Step 1: Use slope formula: $m = \frac{y_2 - y_1}{x_2 - x_1}$ Step 2: $m = \frac{-7 - 5}{2 - (-3)} = \frac{-12}{5} = -\frac{12}{5}$ Answer: $-\frac{12}{5}$

Card 8Collinearity

Find the value of $k$ if the points (1, 2), (3, 4), and (5, k) are collinear.

Answer

Step 1: Use area formula and set to 0: $\frac{1}{2} |1(4 - k) + 3(k - 2) + 5(2 - 4)| = 0$ Step 2: Simplify: $|4 - k + 3k - 6 + 5(-2)| = |4 - k + 3k - 6 - 10| = |2k - 12| = 0$ So, $2k - 12 = 0 \Rig

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Frequently Asked Questions

What are the important topics in Cartesian System of Coordinates for Telangana Open School (TOSS) Class 12 Mathematics?
Cartesian System of Coordinates covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Cartesian System of Coordinates — Telangana Open School (TOSS) Class 12 Mathematics?
Understand the core concepts first, then work through the 49 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 24 flashcards for Cartesian System of Coordinates covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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