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Differentiation — Flashcards

Telangana Open School (TOSS) · Class 12 · Mathematics

23 flashcards for Differentiation (Telangana Open School (TOSS) Class 12 Mathematics) to test yourself on key terms and facts.

49 questions23 flashcards8 formulas & key relations5 concepts

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23 Flashcards·
Power RuleFirst PrinciplesSum and Difference RulesProduct RuleQuotient RuleDerivative of ConstantChain Rule
Card 1Power Rule

Find the derivative of \( x^5 \) using the power rule.

Answer

Using the power rule: \( \frac{d}{dx}(x^n) = nx^{n-1} \) Step 1: Identify \( n = 5 \) Step 2: Apply the formula: \[ \frac{d}{dx}(x^5) = 5x^{5-1} = 5x^4 \] Answer: \( 5x^4 \)…

Card 2First Principles

Differentiate \( \sqrt{x} \) from first principles.

Answer

Let \( f(x) = \sqrt{x} \) By definition: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} = \lim_{h \to 0} \frac{\sqrt{x+h} - \sqrt{x}}{h} \] Rationalize the numerator: \[ = \lim_{h \to 0} \frac{\s…

Card 3Sum and Difference Rules

Differentiate \( y = x^3 + 2x^2 - 5x + 7 \)

Answer

Use the sum and difference rule: derivative of sum is sum of derivatives. \[ \frac{d}{dx}(x^3) = 3x^2 \] \[ \frac{d}{dx}(2x^2) = 4x \] \[ \frac{d}{dx}(-5x) = -5 \] \[ \frac{d}{dx}(7) = 0 \quad \text{…

Card 4Product Rule

When do you use the product rule? Apply it to \( y = (x^2 + 1)(x^3 - 2) \)

Answer

Use the product rule when differentiating the product of two functions: \( \frac{d}{dx}(uv) = u'v + uv' \) Let \( u = x^2 + 1 \Rightarrow u' = 2x \) Let \( v = x^3 - 2 \Rightarrow v' = 3x^2 \) Appl…

Card 5Quotient Rule

Differentiate \( y = \frac{3x + 1}{x - 2} \) using the quotient rule.

Answer

Quotient Rule: \( \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v u' - u v'}{v^2} \) Let \( u = 3x + 1 \Rightarrow u' = 3 \) Let \( v = x - 2 \Rightarrow v' = 1 \) Apply the formula: \[ \frac{dy}{dx…

Card 6Derivative of Constant

What is the derivative of a constant function?

Answer

The derivative of any constant function is zero. For example, if \( f(x) = 5 \), then \( f'(x) = 0 \) This is because there is no change in the function value as \( x \) changes. General Rule: \( \…

Card 7Chain Rule

Differentiate \( y = (2x + 3)^4 \) using the chain rule.

Answer

Chain Rule: \( \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \) Let \( u = 2x + 3 \Rightarrow \frac{du}{dx} = 2 \) Then \( y = u^4 \Rightarrow \frac{dy}{du} = 4u^3 \) Now apply the chain rule: …

Card 8Power Rule

Find the derivative of \( \frac{1}{x^2} \)

Answer

Rewrite the function: \( \frac{1}{x^2} = x^{-2} \) Apply the power rule: \( \frac{d}{dx}(x^n) = nx^{n-1} \) Here, \( n = -2 \) \[ \frac{d}{dx}(x^{-2}) = -2x^{-3} = -\frac{2}{x^3} \] Answer: \( -\f…

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Frequently Asked Questions

What are the important topics in Differentiation for Telangana Open School (TOSS) Class 12 Mathematics?
Key topics in Differentiation include Introduction to Derivatives, Geometric Interpretation of Derivatives, Derivative of Constant and Power Functions, Algebra of Derivatives. Study these first, then practise questions on each for the Telangana Open School (TOSS) Class 12 board exam.
How many flashcards are available for Differentiation?
There are 23 flashcards for Differentiation covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Differentiation for the Telangana Open School (TOSS) Class 12 board exam?
Learn the core ideas first, then work through the 49 practice questions on Differentiation. Revise definitions regularly and use flashcards for quick recall before the exam.

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