Determinants and their Applications
Telangana Open School (TOSS) · Class 12 · Mathematics
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Evaluate: \(\left| \begin{array}{cc} 6 & 4 \\ 8 & 2 \end{array} \right|\)
Answer
Step 1: Use the formula for 2×2 determinant: \(ad - bc\) Here, \(a = 6\), \(b = 4\), \(c = 8\), \(d = 2\) Step 2: Compute: \((6)(2) - (8)(4) = 12 - 32 = -20\) Answer: \(-20\)…
Evaluate: \(\left| \begin{array}{cc} a + b & 2b \\ 2a & a + b \end{array} \right|\)
Answer
Step 1: Apply 2×2 determinant formula: \((a + b)(a + b) - (2a)(2b)\) Step 2: Expand: \(= a^2 + 2ab + b^2 - 4ab = a^2 - 2ab + b^2\) Step 3: Factor: \(= (a - b)^2\) Answer: \((a - b)^2\)…
Find \(x\) if \(\left| \begin{array}{cc} x - 3 & x \\ x + 1 & x + 3 \end{array} \right| = 6\)
Answer
Step 1: Expand determinant: \((x - 3)(x + 3) - x(x + 1) = x^2 - 9 - x^2 - x = -x - 9\) Step 2: Set equal to 6: \(-x - 9 = 6\) Step 3: Solve: \(-x = 15 \Rightarrow x = -15\) Answer: \(x = -15\)…
Evaluate: \(\left| \begin{array}{ccc} 1 & 2 & 3 \\ 2 & 4 & 1 \\ 3 & 2 & 5 \end{array} \right|\) using first row
Answer
Step 1: Expand along R₁: \(1 \cdot \left| \begin{array}{cc} 4 & 1 \\ 2 & 5 \end{array} \right| - 2 \cdot \left| \begin{array}{cc} 2 & 1 \\ 3 & 5 \end{array} \right| + 3 \cdot \left| \begin{array}{cc}…
Evaluate: \(\left| \begin{array}{ccc} 1 & 2 & 3 \\ 3 & 1 & 2 \\ 2 & 3 & 1 \end{array} \right|\) using second column
Answer
Step 1: Expand along C₂: \(-2 \cdot \left| \begin{array}{cc} 3 & 2 \\ 2 & 1 \end{array} \right| + 1 \cdot \left| \begin{array}{cc} 1 & 3 \\ 2 & 1 \end{array} \right| - 3 \cdot \left| \begin{array}{cc…
Find minors of elements in second row of \(\left| \begin{array}{ccc} 1 & 6 & 3 \\ 5 & 2 & 4 \\ 7 & 0 & 8 \end{array} \right|\)
Answer
Step 1: Minor of \(a_{21} = 5\): Delete R₂, C₁ → \(\left| \begin{array}{cc} 6 & 3 \\ 0 & 8 \end{array} \right| = 48\) Step 2: Minor of \(a_{22} = 2\): Delete R₂, C₂ → \(\left| \begin{array}{cc} 1 & 3…
Find cofactors of elements in second row of \(\left| \begin{array}{ccc} 1 & 6 & 3 \\ 5 & 2 & 4 \\ 7 & 0 & 8 \end{array} \right|\)
Answer
Step 1: Use \(C_{ij} = (-1)^{i+j} M_{ij}\) \(C_{21} = (-1)^{3} \cdot 48 = -48\) \(C_{22} = (-1)^{4} \cdot (-13) = -13\) \(C_{23} = (-1)^{5} \cdot (-42) = 42\) Answer: \(C_{21} = -48\), \(C_{22} = …
Evaluate \(\left| \begin{array}{ccc} 3 & 1 & 7 \\ -6 & 2 & -3 \\ 8 & 4 & 5 \end{array} \right|\) using cofactors of first row
Answer
Step 1: Find cofactors: \(C_{11} = (+)\left| \begin{array}{cc} 2 & -3 \\ 4 & 5 \end{array} \right| = 10 + 12 = 22\) \(C_{12} = (-)\left| \begin{array}{cc} -6 & -3 \\ 8 & 5 \end{array} \right| = -(-3…
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