Ch 03 -Trigonometric Functions
ICSE · Class 11 · Mathematics
Flashcards for Ch 03 -Trigonometric Functions — ICSE Class 11 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
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Explore the full setSolve: Convert 60° into radians.
Answer
Step 1: Use the degree-radian relation: 180° = π radian. Step 2: 1° = π/180 rad. Step 3: 60° = 60 × π/180 = π/3 rad. Answer: π/3 radian.
Solve: Convert π/6 radian into degrees.
Answer
Step 1: Use 1 rad = (180/π)°. Step 2: (π/6) × (180/π) = 180/6 = 30°. Answer: 30°.
Solve: Find the length of an arc of radius 5 cm that subtends 15° at the centre.
Answer
Step 1: Arc length formula: l = rθ, and θ must be in radians. Step 2: 15° = 15 × π/180 = π/12 rad. Step 3: l = 5 × (π/12) = 5π/12 cm. Answer: 5π/12 cm.
Solve: Find the area of a sector of radius 10 cm that subtends 45° at the centre.
Answer
Step 1: Sector area formula: A = (1/2)r²θ, with θ in radians. Step 2: 45° = π/4 rad. Step 3: A = (1/2) × 10² × (π/4) = 50 × (π/4) = 25π/2 cm². Answer: 25π/2 cm².
Solve: If l = 11 cm and r = 25 cm, find the angle in radians.
Answer
Step 1: Use l = rθ. Step 2: θ = l/r = 11/25 rad. Answer: 11/25 radian.
Solve: If a central angle of 60° intercepts an arc of length 37.4 cm, find the radius.
Answer
Step 1: Convert 60° to radians: 60° = π/3. Step 2: Use l = rθ. Step 3: r = l/θ = 37.4 ÷ (π/3) = 37.4 × 3/π. Step 4: Taking π = 22/7, r = 37.4 × 3 × 7 / 22 = 35.7 cm. Answer: 35.7 cm.
Solve: Find the angle between the hour and minute hands at 3:30 a.m.
Answer
Step 1: Hour hand in 3.5 hours moves 3.5 × 30° = 105°. Step 2: Minute hand in 30 minutes moves 30 × 6° = 180°. Step 3: Angle between them = 180° - 105° = 75°. Answer: 75°.
Solve: Find the angle between the hour and minute hands at 6:40 p.m.
Answer
Step 1: Hour hand in 6 hours 40 minutes moves (20/3) × 30° = 200°. Step 2: Minute hand in 40 minutes moves 40 × 6° = 240°. Step 3: Angle between them = 240° - 200° = 40°. Answer: 40°.
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