Introduction to Three Dimensional Geometry — Flashcards
ICSE · Class 11 · Mathematics
30 flashcards for Introduction to Three Dimensional Geometry (ICSE Class 11 Mathematics) to test yourself on key terms and facts.
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Solve: Find the coordinates of the foot of the perpendicular from P(2,4,5) on the xy-plane, yz-plane, and xz-plane.
Answer
Step 1: On the xy-plane, the z-coordinate becomes 0, so the foot is D(2,4,0). Step 2: On the yz-plane, the x-coordinate becomes 0, so the foot is E(0,4,5). Step 3: On the xz-plane, the y-coordinate be…
Solve: A point lies on the x-axis. What are its coordinates?
Answer
Step 1: A point on the x-axis has y = 0 and z = 0. Step 2: So its coordinates are of the form (x,0,0). Answer: (x,0,0).
Solve: A point lies on the yz-plane. What are its coordinates and plane equation?
Answer
Step 1: A point on the yz-plane has x = 0. Step 2: So its coordinates are of the form (0,y,z). Step 3: The equation of the yz-plane is x = 0. Answer: Coordinates (0,y,z), equation x = 0.
Solve: Find the reflection of P(-3,2,7) in the xy-plane, yz-plane, and xz-plane.
Answer
Step 1: Reflection in the xy-plane changes only the sign of z. So the image is (-3,2,-7). Step 2: Reflection in the yz-plane changes only the sign of x. So the image is (3,2,7). Step 3: Reflection in …
Solve: Find the octant of the point (4,-2,-5).
Answer
Step 1: Use the signs of x, y, z. Step 2: ( +, -, - ) corresponds to the VIII octant. Answer: VIII octant.
Solve: Find the octant of the point (-4,2,5).
Answer
Step 1: The signs are ( -, +, + ). Step 2: This matches the II octant. Answer: II octant.
Solve: Find the perpendicular distance of P(3,-2,5) from the y-axis.
Answer
Step 1: Distance from the y-axis is √(x² + z²). Step 2: Substitute x = 3 and z = 5. Step 3: Distance = √(3² + 5²) = √(9 + 25) = √34. Answer: √34 units.
Formula for distance between two points in 3D, with a quick example.
Answer
Formula: PQ = √((x2-x1)² + (y2-y1)² + (z2-z1)²). Meaning: P(x1,y1,z1) and Q(x2,y2,z2) are two points in space. Example: For P(2,3,5) and Q(4,3,1), PQ = √((4-2)² + (3-3)² + (1-5)²) = √(4 + 0 + 16) = √2…
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